1147 MAC (3032) - Quiz #2
Name:
Solution Key
For full credit, you must show all work and circle your nal answer.
1
Multiply the two terms together. (2 points)
1
x3
5
1
x3
5
2
1
x+3
5
1
x+3
5
1
1
1
1
= x x3 x+3 x33
5
5
5
5
3
12 3
= x x+ x9
25
5
5
12
= x 9.
25
Write the expression in simplest form. (3 points)
Hint: Do not forget to specify domain restrictions, if necessary.
18y 5
60y 2
18y 5
6y 3 3y 2
3y 2
=
=
, y=0
60y 2
6y 2 10
10
3
Find all if solutions, any exist. Do not forget to check for extraneous solutions. (3 points)
2
1
2
=
+
(x 4)(x 2)
x4 x2
Multiply both sides by (x 4)(x 2) to get:
2 = (x 2) + 2(x 4)
2 = x 2 + 2x 8
2 = 3x 10
12 = 3x
x = 4.
The equation is undened for x = 4, and so this solution is extraneous. Thus, there are no solutions.
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