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HW 12 ANSWERS

Course: PHYSICS 211, Spring 2012
School: Syracuse
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Assignment MasteringPhysics: Print View Page 1 of 2 12 - Bonus assignment for Newton's 2nd Law and friction Due: 8:00pm on Wednesday, February 29, 2012 Note: To understand how points are awarded, read your instructor's Grading Policy. [ Print ] [Switch to Standard Assignment View] This is an extra credit problem. Your grade will not go down if you don't work on it. However, you can earn bonus credit if you...

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Assignment MasteringPhysics: Print View Page 1 of 2 12 - Bonus assignment for Newton's 2nd Law and friction Due: 8:00pm on Wednesday, February 29, 2012 Note: To understand how points are awarded, read your instructor's Grading Policy. [ Print ] [Switch to Standard Assignment View] This is an extra credit problem. Your grade will not go down if you don't work on it. However, you can earn bonus credit if you do. Pushing a Lawnmower Consider a lawnmower of mass handle, which makes an angle which can slide across a horizontal surface with a coefficient of friction with the horizontal. Assume that . In this problem the lawnmower is pushed using a massless , the force exerted by the handle, is parallel to the handle. Take the positive x direction to be to the right and the postive y direction to be upward. Use for the magnitude of the acceleration due to gravity. Part A Find the magnitude, Hint A.1 , of the force required to slide the lawnmower over the ground at constant speed by pushing the handle. How to approach this problem . If the lawnmower is to move at constant velocity, the net force acting on it must be zero. Using this fact, find two equations, one for the vertical and one for the horizontal components of all forces acting on the lawnmower. Solve these equations for , eliminating unknown quantities in favor of quantities given in the problem introduction. Hint A.2 Compute the sum of vertical forces The lawnmower is not accelerating vertically. Express the sum of the vertical components of all the forces on the lawnmower. ANSWER: = Answer Requested Hint A.3 Find =0 Compute the normal force , the magnitude of the normal force exerted on the lawnmower by the ground. Express in terms of ANSWER: = Do not assume that and other given variables. Correct without starting from . Here's an example of one of the many ways that assumption can fail--when there is another force on the object that has a vertical component. Hint A.4 Compute the sum of horizontal forces The phrase "at constant speed" implies that there is no x component of acceleration. Therefore, the sum of the x components of all the real forces acting on the lawnmower is zero. Find the sum of the x components all of of the forces. Remember, the positive direction is up and to the right. http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1738195 4/16/2012 MasteringPhysics: Assignment Print View Express your answer in terms of the given forces, , and Page 2 of 2 , the magnitude of the friction force. [ Print ] ANSWER: Answer Requested Once you have obtained the equations for the vertical and horizontal equilibrium, solve them simultaneously to find . Express the required force in terms of given quantities. ANSWER: = Answer Requested Part B The solution for has a singularity (that is, becomes infinitely large) at a certain angle However, a negative applied force . For any angle , the expression for will be negative. would reverse the direction of friction acting on the lawnmower, and thus this is not a physically acceptable solution. In fact, the increased normal force at these large angles makes the force of friction too large to move the lawnmower at all. Find an expression for Hint B.1 . How to approach the problem Look at the expression you have derived for in Part A. The force will become infinite when the denominator becomes zero. Use this criterion to find the required quantity. ANSWER: = Answer Requested You should have found that , the force required to push the lawnmower at constant speed, was . Note that this expression becomes infinite when the denominator equals zero: , or . (The phrase " has a singularity at angle " means that " goes to infinity at a certain angle It's not too hard to understand what this means. Suppose you were pushing straight down on the lawnmower ( according to the equation for , when you plug in .") degrees). It obviously wouldn't move. But, degrees, you get a negative force (which doesn't make sense). The more vertical you push, the harder it gets to move the lawnmower. At , it gets impossible to move it. The force required to move it goes to infinity; you have to push infinitely hard. Score Summary: Your score on this assignment is 10.5%. You received 2.1 out of a possible total of 20 points. http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1738195 4/16/2012
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