Unformatted Document Excerpt

Coursehero >> Florida >> FGCU >> MAP 3161

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
There is no excerpt for this document.
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
Solution to Problem Set #5MAP 3161 - Spring 20111.xy= 2x 4y + 3xy = F (x, y )= x + y + x2 = G(x, y )(a) Note that F and G are twice dierentiable for all real numbers since they are bothpolynomials with integer exponents. Thus the system above is a
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Electrochemistry Practice QuestionsAnswers1.D2.E3.D4.D5.D6.B7.C8.C&D: Notes: 1) I will include table with Reduction Potentials on test. (2) I wonthave any answers with more than one correct letter(3) To answer this, Pb will oxidize any
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
CHEM 1420 Chapter 13 Homework Solutions TEXTBOOK HOMEWORK 19. Answer: (a) nine times faster (b) one quarter as fast Strategy and Explanation: Given the rate law of a reaction, determine what happens to the rate when the concentration is changed. Knowing t
North Texas - CHEM - 1420
CHEM 1420 Chapter 14 Homework Solutions TEXTBOOK HOMEWORK 13. Answer: (a)[H2O] [O2 ] Kc = 2 [H2O2 ]2(b) Kc =[PCl5 ] [PCl3 ] [Cl2 ](c) Kc = [CO]2(d) Kc =[H2S] [H2 ]Strategy and Explanation: For the expression of the equilibrium constant, use this f
North Texas - CHEM - 1420
CHEM 1420 Chapter 15 Homework Solutions TEXTBOOK HOMEWORK 6. Henrys law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above that liquid. Three factors that govern the solubility of a gas are,
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
CHEMICAL KINETICS: RATES OF REACTIONS Chapter 13 Outline Probs: 19, 20, 26, 30, 41, 46, 51, 61 (also calculate A), 64, 65, 67, 69, 73, 74 + Supplementary Questions (attached) Title and Comments Reaction Rate Effect of Concentration on Reaction Rate Rate L
North Texas - CHEM - 1420
CHEMICAL EQUILIBRIUM Chapter 14 Outline Probs: 13, 19, 21, 29, 34, 36, 41, 45, 46, 53, 55, 59, 61, 63 + Supplementary Questions (attached) Title and Comments Charactistics of Chemical Equilibrium The Equilibrium Constant Determining Equilibrium Constants
North Texas - CHEM - 1420
THE CHEMISTRY OF SOLUTES AND SOLUTIONS Chapter 15 Outline Probs: 6, 7, 8, 40, 41, 44, 49, 53, 54, 57, 60, 62, 65, 67, 76 + Supplementary Questions (attached) Title and Comments Solubility and Intermolecular Forces Enthalpy, Entropy and Dissolving Solutes
North Texas - CHEM - 1420
THERMODYNAMICS: DIRECTIONALITY OF CHEMICAL REACTIONS Chapter 18 Outline Probs: 22, 25, 28, 31, 35, 40, 45, 48, 64, 74, 78 + Supplementary Questions (attached) Title and Comments Reactant-Favored and Product Favored Processes Chemical Reactions and Dispers
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 1 Answers 1. 2. 3. 4. 5. 6. 7. 8. 9. B D D E C D C D E10. A 11. B [second sentence of Question should be: To determine the Activation Energy,] 12. A 13. B 14. A 15. B 16. Ask me to draw it in recitation 17. Rate = k[NO][H2]2 - k = 9.6x104 M
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 2Answers1.E - Was on our first test2.B- Was on our first test3.A- Was on our first test4.E- Was on our first test5.B- Was on our first test6.C7.D- Was on our first test8.B9.D- Was on our first test10. Not on either test1
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 3 Answers 1. 2. 3. 4. 5. 6. 7. 8. 9. B D B A B A C B D10. A 11. C 12. E 13. A 14. A 15. B [should read: A Bronsted-Lowry acid is a substance that can donate a proton and . - i.e. not donate a proton donor] 16. 8.0x10-5 17. 3.37 3.4 18. 10.2
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 4Answers1.D2.C3.D - However, you are not responsible for this question4.C5.E6.D7.D8.A9.B10. B - but you are not responsible for entropy of solution of ionic solids11. D12. B13. B - However, you are not responsible for
North Texas - CHEM - 1413
COVALENT BONDINGChapter 8 OutlineProbs:Sect.12, 17, 32, 33, 34, 36, 42, 44, 46, 51+ supplementary questions (attached)Title and CommentsRequired?1.Covalent BondingYES2.Single Covalent Bonds and Lewis StructuresYES3.Multiple Covalent BondsY
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 1 Sept. 22, 2010 - Part 1Name_(51)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. 25. g/cm3 = _ g/m3 ?(A) 2.5x10-11(C) 2.5x10-
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 1 Sept. 21, 2011 - Part 1Constants and Conversion FactorsAvogadro's Number: NA = 6.02x1023 mol-1Conversion Factors:1 cm3 = 1mLMolar Masses: C3H8O3 - 92.PF5 - 126.P - 31.1 lb = 454 gF - 19.1 Qt. = 1.06 LCHEM 1413.001 - Exam
North Texas - CHEM - 1413
Credit for C or D
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 2 October 13, 2010 - Part 1Name_(60)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. The reaction, 2 Al(s) + 3 O2(g) Al2O3(s), is
North Texas - CHEM - 1413
Exam 3 - Nov. 3, 2010Exam 3 - Nov. 3, 2010
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 3 November 3, 2010 - Part 1Name_(27)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. For a process in which the internal energy c
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 3 November 2, 2011 - Part 1Molar Masses: C6H14 - 86.H2O - 18.C2H4 - 28.H2 - 2.Li - 6.9NH4Cl - 53.5CH3OH - 32.C2H6 - 30.CHEM 1413.001 - Exam 3 November 2, 2011 - Part 1Name_(27)MULTIPLE CHOICE (Circle the ONE correct answer
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 4 November 30, 2011 - Part 1Avogadro's Number: NA = 6.02x1023 mol-1Conversion Factors:1 atm. = 760 torr ,Molar Masses: CO2 - 44.CH4 - 16.C2H6 - 30.SO2 - 64.1CHEM 1413.001 - Exam 4 November 30, 2011 - Part 1Name_(42)MULTIPLE
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Final Exam Dec. 13, 2010If you would like to have your grade posted on the course web site, using a fourdigit number, then please sign in the space below and put the number.If you do not wish to have your grade posted, you can still lea
North Texas - CHEM - 1413
CHEM 1413.001 - Final Exam Dec. 14, 2011If you would like to have your grade posted on the course web site, using a fourdigit number, then please sign in the space below and put the number.If you do not wish to have your grade posted, you can still lea
North Texas - CHEM - 1413
CHEM 1413Chapter 6Homework SolutionsTEXTBOOK HOMEWORK29. Answer: 5.00 105 JStrategy and Explanation: Given the mass and initial temperature of a liquid substance, theboiling point of the liquid, the final temperature of the gaseous substance, the sp
North Texas - CHEM - 1413
CHEM 1413Chapter 8Homework SolutionsTEXTBOOK HOMEWORK12. Answer: (a). .l.C.. .Cl. ..O..O.(b) H_H.O.(c)HHBHH+H(d)HPHH. .. Cl ... Cl. . P . .Cl .(e) . ... Cl. .Cl.. ...F . .F ..17. Answer: (a)..F. .CC.
North Texas - CHEM - 1413
CHEM 1413Chapter 10Homework SolutionsTEXTBOOK HOMEWORK17. Answer: CH2Cl2 < Kr < N2 < CH4Strategy and Explanation: Given the formulas of various atoms and molecules and theircommon temperature, put their gases in order of increasing average molecular
North Texas - CHEM - 1413
CHEM 1413Chapter 11Homework SolutionsTEXTBOOK HOMEWORK10. Answer: Reduce the pressureStrategy and Explanation: A liquid can be converted to a vapor without changing thetemperature by reducing the pressure above it. This can be accomplished by puttin
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHAPTER 7SUPPLEMENTARY HOMEWORK QUESTIONS1.The maximum wavelength of light which can break the CO bond is 112 nm. Calculate the CObond strength, in kJ/mol.2.A lamp rated at 40 W (1 W = 1 J/s) emits blue light at a wavelength of 470 nm. How manyphot
North Texas - CHEM - 1413
CHAPTER 8SUPPLEMENTARY HOMEWORK QUESTIONS1.Without using a table of electronegativies, predict which order is correct for increasing polarity(least polar first)?(A) Si-Cl (B) S-Cl(A) C<D<B<A(D) C<B<D<A2.(C) P-Cl(D) Si-Si(B) D<C<B<A(E) A<B<C<D
North Texas - CHEM - 1413