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Course: MAP 3161, Spring 2011
School: FGCU
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FGCU - MAP - 3161
FGCU - MAP - 3161
Solution to Problem Set #5MAP 3161 - Spring 20111.xy= 2x 4y + 3xy = F (x, y )= x + y + x2 = G(x, y )(a) Note that F and G are twice dierentiable for all real numbers since they are bothpolynomials with integer exponents. Thus the system above is a
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
FGCU - MAP - 3161
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Electrochemistry Practice QuestionsAnswers1.D2.E3.D4.D5.D6.B7.C8.C&amp;D: Notes: 1) I will include table with Reduction Potentials on test. (2) I wonthave any answers with more than one correct letter(3) To answer this, Pb will oxidize any
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
CHEM 1420 Chapter 13 Homework Solutions TEXTBOOK HOMEWORK 19. Answer: (a) nine times faster (b) one quarter as fast Strategy and Explanation: Given the rate law of a reaction, determine what happens to the rate when the concentration is changed. Knowing t
North Texas - CHEM - 1420
CHEM 1420 Chapter 14 Homework Solutions TEXTBOOK HOMEWORK 13. Answer: (a)[H2O] [O2 ] Kc = 2 [H2O2 ]2(b) Kc =[PCl5 ] [PCl3 ] [Cl2 ](c) Kc = [CO]2(d) Kc =[H2S] [H2 ]Strategy and Explanation: For the expression of the equilibrium constant, use this f
North Texas - CHEM - 1420
CHEM 1420 Chapter 15 Homework Solutions TEXTBOOK HOMEWORK 6. Henrys law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above that liquid. Three factors that govern the solubility of a gas are,
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
North Texas - CHEM - 1420
CHEMICAL KINETICS: RATES OF REACTIONS Chapter 13 Outline Probs: 19, 20, 26, 30, 41, 46, 51, 61 (also calculate A), 64, 65, 67, 69, 73, 74 + Supplementary Questions (attached) Title and Comments Reaction Rate Effect of Concentration on Reaction Rate Rate L
North Texas - CHEM - 1420
CHEMICAL EQUILIBRIUM Chapter 14 Outline Probs: 13, 19, 21, 29, 34, 36, 41, 45, 46, 53, 55, 59, 61, 63 + Supplementary Questions (attached) Title and Comments Charactistics of Chemical Equilibrium The Equilibrium Constant Determining Equilibrium Constants
North Texas - CHEM - 1420
THE CHEMISTRY OF SOLUTES AND SOLUTIONS Chapter 15 Outline Probs: 6, 7, 8, 40, 41, 44, 49, 53, 54, 57, 60, 62, 65, 67, 76 + Supplementary Questions (attached) Title and Comments Solubility and Intermolecular Forces Enthalpy, Entropy and Dissolving Solutes
North Texas - CHEM - 1420
THERMODYNAMICS: DIRECTIONALITY OF CHEMICAL REACTIONS Chapter 18 Outline Probs: 22, 25, 28, 31, 35, 40, 45, 48, 64, 74, 78 + Supplementary Questions (attached) Title and Comments Reactant-Favored and Product Favored Processes Chemical Reactions and Dispers
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 1 Answers 1. 2. 3. 4. 5. 6. 7. 8. 9. B D D E C D C D E10. A 11. B [second sentence of Question should be: To determine the Activation Energy,] 12. A 13. B 14. A 15. B 16. Ask me to draw it in recitation 17. Rate = k[NO][H2]2 - k = 9.6x104 M
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 2Answers1.E - Was on our first test2.B- Was on our first test3.A- Was on our first test4.E- Was on our first test5.B- Was on our first test6.C7.D- Was on our first test8.B9.D- Was on our first test10. Not on either test1
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 3 Answers 1. 2. 3. 4. 5. 6. 7. 8. 9. B D B A B A C B D10. A 11. C 12. E 13. A 14. A 15. B [should read: A Bronsted-Lowry acid is a substance that can donate a proton and . - i.e. not donate a proton donor] 16. 8.0x10-5 17. 3.37 3.4 18. 10.2
North Texas - CHEM - 1420
North Texas - CHEM - 1420
Practice Exam 4Answers1.D2.C3.D - However, you are not responsible for this question4.C5.E6.D7.D8.A9.B10. B - but you are not responsible for entropy of solution of ionic solids11. D12. B13. B - However, you are not responsible for
North Texas - CHEM - 1413
COVALENT BONDINGChapter 8 OutlineProbs:Sect.12, 17, 32, 33, 34, 36, 42, 44, 46, 51+ supplementary questions (attached)Title and CommentsRequired?1.Covalent BondingYES2.Single Covalent Bonds and Lewis StructuresYES3.Multiple Covalent BondsY
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 1 Sept. 22, 2010 - Part 1Name_(51)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. 25. g/cm3 = _ g/m3 ?(A) 2.5x10-11(C) 2.5x10-
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 1 Sept. 21, 2011 - Part 1Constants and Conversion FactorsAvogadro's Number: NA = 6.02x1023 mol-1Conversion Factors:1 cm3 = 1mLMolar Masses: C3H8O3 - 92.PF5 - 126.P - 31.1 lb = 454 gF - 19.1 Qt. = 1.06 LCHEM 1413.001 - Exam
North Texas - CHEM - 1413
Credit for C or D
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 2 October 13, 2010 - Part 1Name_(60)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. The reaction, 2 Al(s) + 3 O2(g) Al2O3(s), is
North Texas - CHEM - 1413
Exam 3 - Nov. 3, 2010Exam 3 - Nov. 3, 2010
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 3 November 3, 2010 - Part 1Name_(27)MULTIPLE CHOICE (Circle the ONE correct answer)NOTE: All required Molar Masses and non-metric conversion factors aregiven at the end of the test.1. For a process in which the internal energy c
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 3 November 2, 2011 - Part 1Molar Masses: C6H14 - 86.H2O - 18.C2H4 - 28.H2 - 2.Li - 6.9NH4Cl - 53.5CH3OH - 32.C2H6 - 30.CHEM 1413.001 - Exam 3 November 2, 2011 - Part 1Name_(27)MULTIPLE CHOICE (Circle the ONE correct answer
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Exam 4 November 30, 2011 - Part 1Avogadro's Number: NA = 6.02x1023 mol-1Conversion Factors:1 atm. = 760 torr ,Molar Masses: CO2 - 44.CH4 - 16.C2H6 - 30.SO2 - 64.1CHEM 1413.001 - Exam 4 November 30, 2011 - Part 1Name_(42)MULTIPLE
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHEM 1413.001 - Final Exam Dec. 13, 2010If you would like to have your grade posted on the course web site, using a fourdigit number, then please sign in the space below and put the number.If you do not wish to have your grade posted, you can still lea
North Texas - CHEM - 1413
CHEM 1413.001 - Final Exam Dec. 14, 2011If you would like to have your grade posted on the course web site, using a fourdigit number, then please sign in the space below and put the number.If you do not wish to have your grade posted, you can still lea
North Texas - CHEM - 1413
CHEM 1413Chapter 6Homework SolutionsTEXTBOOK HOMEWORK29. Answer: 5.00 105 JStrategy and Explanation: Given the mass and initial temperature of a liquid substance, theboiling point of the liquid, the final temperature of the gaseous substance, the sp
North Texas - CHEM - 1413
CHEM 1413Chapter 8Homework SolutionsTEXTBOOK HOMEWORK12. Answer: (a). .l.C.. .Cl. ..O..O.(b) H_H.O.(c)HHBHH+H(d)HPHH. .. Cl ... Cl. . P . .Cl .(e) . ... Cl. .Cl.. ...F . .F ..17. Answer: (a)..F. .CC.
North Texas - CHEM - 1413
CHEM 1413Chapter 10Homework SolutionsTEXTBOOK HOMEWORK17. Answer: CH2Cl2 &lt; Kr &lt; N2 &lt; CH4Strategy and Explanation: Given the formulas of various atoms and molecules and theircommon temperature, put their gases in order of increasing average molecular
North Texas - CHEM - 1413
CHEM 1413Chapter 11Homework SolutionsTEXTBOOK HOMEWORK10. Answer: Reduce the pressureStrategy and Explanation: A liquid can be converted to a vapor without changing thetemperature by reducing the pressure above it. This can be accomplished by puttin
North Texas - CHEM - 1413
North Texas - CHEM - 1413
CHAPTER 7SUPPLEMENTARY HOMEWORK QUESTIONS1.The maximum wavelength of light which can break the CO bond is 112 nm. Calculate the CObond strength, in kJ/mol.2.A lamp rated at 40 W (1 W = 1 J/s) emits blue light at a wavelength of 470 nm. How manyphot
North Texas - CHEM - 1413
CHAPTER 8SUPPLEMENTARY HOMEWORK QUESTIONS1.Without using a table of electronegativies, predict which order is correct for increasing polarity(least polar first)?(A) Si-Cl (B) S-Cl(A) C&lt;D&lt;B&lt;A(D) C&lt;B&lt;D&lt;A2.(C) P-Cl(D) Si-Si(B) D&lt;C&lt;B&lt;A(E) A&lt;B&lt;C&lt;D
North Texas - CHEM - 1413
North Texas - CHEM - 1413
North Texas - CHEM - 1413
ENERGY AND CHEMICAL REACTIONSChapter 6 OutlineProbs:Sect.29, 36, 37, 41, 47, 50, 54, 58, 63, 70, 79+ Supplementary Questions (attached)Title and CommentsRequired?1.The Nature of EnergyYES2.Conservation of EnergyYESIn addition to discussing w
North Texas - CHEM - 1413
ELECTRON CONFIGURATIONS AND THE PERIODIC TABLEChapter 7 OutlineProbs:Sect.8, 23, 30, 38, 45, 47, 55, 57, 62, 65, 73, 88+ supplementary questions (attached)Title and CommentsRequired?1.Electromagnetic Radiation and MatterYES2.Plancks Quantum Th