12 Pages

PHOTOSYNTHESIS

Course: BSC 2010, Spring 2009
School: Broward College
Rating:
 
 
 
 
 

Word Count: 2831

Document Preview

AND LIGHT PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Now that you have been exposed to the principles of light and that you know how chlorophyll traps that light, its time to discuss the actual process of photosynthesis. First, you need to know scientists dont know everything about photosynthesis. What scientists do know is amazing. For our purposes, we will only brush the topic. However, you will probably feel you...

Register Now

Unformatted Document Excerpt

Coursehero >> Florida >> Broward College >> BSC 2010

Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.

Course Hero has millions of student submitted documents similar to the one below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
AND LIGHT PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Now that you have been exposed to the principles of light and that you know how chlorophyll traps that light, its time to discuss the actual process of photosynthesis. First, you need to know scientists dont know everything about photosynthesis. What scientists do know is amazing. For our purposes, we will only brush the topic. However, you will probably feel you have been overexposed to the process after finishing this lecture. Just keep your eye on the concept this is the most important biochemical process on earth and everyone needs to understand a little about it. Autotrophic vs Heterotrophic Scientists often categorize organisms into their forms of energy sources. Organisms that convert carbon dioxide (an inorganic compound) into organic compounds (such as glucose) utilizing some energy source (in our case, the sun) are called autotrophic. Organisms that depend on other organisms for their source of organic compounds (such as food) are called heterotrophic. Plants and some bacteria are autotrophic through the process of photosynthesis. Photosynthesis There are two basic sets of reactions in photosynthesis: light dependent and light independent. Like their name indicates, light dependent reactions require sunlight to take place. The light independent reactions may take place in daylight or in darkness. The light dependent reactions have two subsets of reactions: Photosystem I and Photosystem II. The light independent reactions have one of three possible tracks: Calvin-Benson Cycle, C-4 pathway, or the Crassulacean Acid Metabolism pathway (CAM photosynthesis). PHOTO1 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Light Dependent Reactions Photosystem II The light dependent reactions begin with Photosystem II (not Photosystem I). Photosystem II is actually a cluster of chlorophyll molecules. These molecules of chlorophyll trap sunlight in the 680 nanometer range of the visible spectrum. The cluster of molecules is sometimes referred to as the P680 site or receptor site. As these molecules trap sunlight, the energy is transferred to a special chlorophyll molecule called the acceptor molecule within the site. The massive input of energy from the other chlorophyll molecules causes two electrons to not only be bounced to a higher energy level, but to be totally bounced out of the orbit of the molecule. These two electrons are then trapped by another molecule within the Photosystem called Quinone. quinone 2e- PHOTO2 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Quinone becomes reduced (gains two electrons) and the acceptor molecule becomes oxidized (loses two electrons). Remember oxidation-reduction reactions go hand in hand. As one material is oxidized, another must be reduced, in turn. Quinone passes these highly energized electrons to cytochrome b3, one of the many cytochrome pigments associated with photosynthesis and respiration. Cytochrome b3 becomes reduced and Quinone is oxidized. Cytochrome b3 passes the electrons to Plastoquinone which becomes reduced as Cytochrome b3 becomes oxidized. Plastoquinone passes the electrons to Cytochrome f which becomes reduced. Cytochrome f finally passes the electrons to Plastocyanin which becomes reduced. quinone PHOTOSYSTEM II Cyto b3 Plastoquinone Cyto f 2e- Plastocyanin sunlight Receptor molecule Acceptor site or P680 site Photolysis While these electrons are being passed from molecule to molecule, back at the aggregation site, water is split into hydrogen atoms and the oxide ion. This splitting of water with light is called photolysis. The hydrogen ions are used to eventually form ATP. quinone Cyto b3 Plastoquinone Cyto f 2e- Plastocyanin sunlight ATP H2O 2H+ + O photolysis PHOTO3 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Photosystem I Photosystem I is another aggregation of chlorophyll molecules. These trap light in the 700 nanometer range. The acceptor molecule of the P700 site accepts the electrons from Plastocyanin of Photosystem II. Sunlight energizes the P700 site and that energy is channeled into the acceptor molecule. The two electrons (from Photosystem II) are then shot out of their orbit to a molecule of Ferrodoxin bound which becomes reduced. Ferrodoxin bound passes the electrons to Ferrodoxin free, (again one material is oxidized, another reduced) and Ferrodoxin free passes them to Flavoprotein. Flavoprotein passes the electrons to Nicotinamide Adenine Dinucleotide Phosphate (NADP) which is reduced. FDbound PHOTOSYSTEM I FDfree FP 2e- NADP+ 700nm + electrons from Photosystem II Path of Electrons The electrons can, indeed, pass down the electron chain from Ferrodoxin bound to NADP. However, the electrons can just as easily lose their energy and fall back to the acceptor molecule. That energy that is lost may be converted to ATP. This process of elevating electrons and their falling back to their original position may occur over and over thus a cycle. FDbound FDfree 2e- FP 700nm CYCLIC PHOTOPHOSPHORYLATION PHOTO4 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Cyclic Photophosphorylation The process of forming ATP by the above process in Photosystem I is called cyclic photophosphorylation. Photo because it occurs in the presence of light. Phosphorylation because adding a phosphate group to a compound is called phosphorylation. quinone FDbound Cyto b3 FDfree Plastoquinone 2e - FP Cyto f 2e- 700nm Plastocyanin sunlight NADP+ ATP H2O 2H+ + O Whats Been Done In reality, only two things have been accomplished in Photosystems II and I. ATP has been produced (photolysis in Photosystem II and cyclic photophosphorylation in Photosystem I). Also, NADP has been reduced. Refer to the summary equation of photosynthesis. sunlight 6CO2 + 12 H2O ------------------------> C6H12O6 + 6 O2 + 6 H2O chlorophyll glucose The only issues addressed in the above reaction by Photosystem II and Photosystem I are shown in red. Water was split during photolysis and oxygen generated in photolysis. No carbon dioxide was used and no glucose was made. This occurs during the light independent reactions of photosynthesis. Why Cover Photosystem II First? It was a little strange to cover Photosystem II first. The reason is Photosystem I was the first Photosystem to evolve. Primitive plants have only Photosystem I. Higher plants on the evolutionary scale evolved Photosystem II to boost the production in Photosystem I. PHOTO5 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Hydrogen to ATP How does the chloroplast make ATP from hydrogen ions? The process is called the chemiosmotic theory. Remember that chlorophyll is found in the thylakoids of the chloroplasts. The thylakoids, like most membranes in cells, are composed of a phospholipids bilayer, just like the cell membrane with proteins scattered in and about. The materials scattered in and about not only include proteins, but may also include Photosystem I and Photosystem II receptor sites with other pigments and molecules, as previously discussed. A part of the thylakoids bilayer of lipids includes the P680 site of chlorophyll molecules. Next to that is the molecule Quinone, followed by cytochrome b3, Plastoquinone, cytochrome f, and Plastocyanin. Next to this line of molecules is the P700 site of chlorophyll molecules followed by Ferrodoxin bound, ferrodoxin free, flavoprotein, and NADP. All of this is repeated over and over in the lipid bilayer of the thylakoids. In addition, there is another molecule (a protein called ATP synthetase) found as a channel between the lipid bilayer. P680 Q b3 PQ f PC 2H+ 2H+ P700 2H+ 2H+ FDb 2H+ FDf FP NAD+ ATPase ATP 2H+ PHOTO6 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS In Photosystem II, as water is split to form hydrogen ions, the hydrogen ions build up in the lumen of the thylakoids. Soon there is a concentration gradient between hydrogen ions inside the thylakoids and the outside of the thylakoids. Osmosis occurs with the hydrogen ions passing through the molecule of ATP synthetase on their way to the outside of the thylakoids. This pumping mechanism, coupled with ATP synthetase, forms the ATP. Therefore, the pumping of hydrogen ions across a thylakoids membrane forms ATP and is the process is called the chemiosmotic theory. Light Independent Reactions To finish off the equation of photosynthesis the production of glucose we must study the light independent reactions. There are three possible paths for plants, depending upon the species of plants: 1. Calvin-Benson Cycle temperate plants 2. C-4 Pathway tropical plants 3. CAM Photosynthesis (Crassulacean Acid Metabolism) desert plants Calvin-Benson Cycle The Calvin-Benson Cycle begins when carbon dioxide (a single carbon compound) combines with a five carbon compound called ribulose biphosphate carboyxlase (sometimes written as diphosphate). This results in the formation of a six carbon intermediate. An intermediate is simply a shortlived compound. This reaction catalyzed is by an enzyme called ribulose biphosphate carboyxlase. (Most enzymes end in ase.) Naming Enyzmes Enzymes are often named for what they do. In the case with ribulose biphosphate carboyxlase, the enzyme takes ribulose biphosphate and adds carbon dioxide to it. Remember that adding a phosphate is called phosphorylation. Adding a carbon dioxide is called carboxylation, thus the name ribulose biphosphate carboyxlase. ribulose biphosphate carboxylase CO2 + ribulose biphosphate C-C-C-C-C-C PHOTO7 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS The six carbon intermediate breaks apart to form phosphogylceric acid (PGA). PGA, a 3 carbon compound, combines with NADPreduced and ATP to form phosphoglyceraldehyde (PGAL) another 3 carbon compound. Some of the PGAL goes to form glucose (6 carbons) and some other goes to form additional ribulose biphosphate (5 carbons). The ribulose biphosphate combines with another carbon dioxide and the cycle starts again. ribulose biphosphate carboxylase CO2 + ribulose biphosphate C-C-C-C-C-C 1C 5C 6C NADH2 NAD+ C6H12O6 PGAL 3C ADP PGA 3C ATP You Do the Math At first, from the above description of events, it seems a 3 carbon compound (PGAL) is forming a 6 carbon compound (glucose) and a five carbon compound (ribulose biphosphate). Nice trick if you can do it. Of course, you cannot. However, remember the summary equation for photosynthesis called for 6 carbon dioxides. That would combine with 6 ribulose biphosphates (and 6 enzymes) to for 6 six carbon intermediates (36 carbons). That would split to form 12 PGAs and that forms 12 PGALs (36 carbons). Six of those carbons form glucose and the other 30 form 6 ribulose biphosphates. Corn Is A Tropical Plant Calvin-Benson and C-4 Pathway Strangely, corn is a The Calvin-Benson cycle occurs in temperate plants. These are tropical plant. At first, plants found in the temperate zones of the world. Most of the you think, corn is grown continental United States falls within a temperate zone where the in Iowa and Iowa is winters are cold, but not too cold and the summers are hot, but anything but tropical. not too hot thus temperate. South Florida exhibits subtropical Youre right on that climate and Alaska exhibits some arctic climates. C-4 plants are account, but the ancestor found primarily in the tropics. The plants include palms, sugar to corn is a plant called cane (a grass), most grasses, bananas, and others. Whats the Teosinte, found in Central difference? It mostly has to do with leaf anatomy. America and Mexico, thus tropical. PHOTO8 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Structure of A Leaf A leaf is composed of three basic parts. The part most people recognize is called the blade or lamina. What attaches the leaf to the stem is called a petiole. At the base of the petiole may be a couple of leaf-like structures called stipules. If a leaf has all three parts, it is said to be complete. Some leaves are incomplete they are missing one or more parts. For example, some leaves do not have stipules. Other leaves may not have petioles the blade is attached directly to the stem as in grass. This condition is referred to as a sessile leaf. Still other leaves may not have blades. The cactus spines are actually the petiole and midvein of a leaf without the blade. Leaf Anatomy of Calvin-Benson Leaf Think of a leaf and cut that leaf in cross section. Look down into the leaf and imagine what you would see. cuticle upper epidermis palisade layer mesophyll lower epidermis vascular bundle guard cell Stoma* *See insert on the right on stomata and their mechanisms. There is an upper and lower epidermis. The upper epidermis is often covered in a waxy cuticle. Just beneath the upper epidermis is a group of columnar cells called the palisade layer which is has abundant chloroplasts in the cell. Underneath the palisade layer is a middle layer (mesophyll) that also contains chloroplasts. The lower epidermis has a variation from the upper epidermis. There are openings on the undersurface called stomata. The stomata are formed by guard cells. The guard cells also contain chloroplasts, although epidermal cells do not. The vascular bundle is composed primarily of two types of tissue: xylem and phloem. Xylem (in red) is tissue that is specialized for the conduction of water (typically upward from the roots) and phloem (in blue) is specialized tissue for the conduction of food (typically downward from the leaves to the rest of the plant). Stomata The word stoma meaning opening. The plural is stomata. Higher plants typically have stomata on the lower surfaces of their leaves (although you may also find them on upper surfaces, unless it is an aquatic plant with floating leaves). These openings allow the passage of three gases in and out of the leaf: carbon dioxide, oxygen, and water vapor. The openings are formed by cells called guard cells. Guard cells have a large, single chloroplast in each cell. Based on the condition of the environment around the guard cell, the guard cells either swell or shrink based on hypertonic or hypotonic environments. The question is: do guard cells open or close in a hypertonic environment? The answer is they close. The guard cells open (and form the stoma) when they are exposed to hypotonic environments. Think of two long, slender balloons full of air. Place the balloons between two solid surfaces so they line up like two hotdogs (parallel) and their ends are blocked by something. Think of those balloons if you continue to add air. Since the ends are blocked, the balloons have to expand and the only way they can do it is to bow outward from the middle, thus creating a gap between the balloons. Thats the same way stomata work. PHOTO9 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Leaf Anatomy of C-4 Leaf bundle sheath There are two major differences between a Calvin-Benson leaf and a C-4 leaf. The first should be obvious in that there is no palisade layer in a C-4 leaf. In addition, the C-4 leaf has another set of cells surrounding the vascular bundle called the bundle sheath. C-4 Pathway In the C-4 pathway, carbon dioxide combines with a three carbon compound called phosphoenolpyruvate (PEP). This forms a 4-carbon compound called oxaloacetate (OAA). The reaction to form OAA from PEP and carbon dioxide is catalyzed by phosphoenolpyruvate carboyxlase (PEP carboyxlase). OAA breaks apart to form two compounds: malate and aspartate. These two compound diffuse from the mesophyll cells to the bundle sheath. In the bundle sheath, they recombine to form OAA. OAA, in the bundle sheath, then splits to form PEP and carbon dioxide. The carbon dioxide then feeds into the Calvin-Benson cycle in the bundle sheath to make glucose. The PEP diffuses from the bundle sheath back to the mesophyll to begin again the process of forming OAA. PEP carboylase MESOPHYLL CO2 + PEP 1C 3C OAA 4C malate BUNDLE SHEATH Ribulose biphosphate CO2 aspartate malate aspartate OAA 4C Calvin-Benson PHOTO10 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS At first, it seems mother nature has gone a little crazy. Why go through the C-4 pathway in the mesophyll if all you are going to do is go through Calvin-Benson in the bundle sheath? Mother nature doesnt do anything capriciously. Oxygen Inhibition of Ribulose Biphosphate Carboxylase Review the material on the Calvin-Benson. Ribulose biphosphate carboyxlase, the enzyme important in Calvin-Benson, is inhibited by high levels of oxygen. In the tropics, you find plenty of water, plenty of carbon dioxide, and plenty of sunlight for the light dependent part of photosynthesis which makes oxygen. This oxygen would shut down the light independent reaction of Calvin Benson and the plant would starve as it produced oxygen. Instead, in the tropics, plants run the C-4 pathway in the mesophyll. PEP carboyxlase is not inhibited by high levels of oxygen, so it runs quite nicely in the tropics. The products of C-4 are then sent to the bundle sheath which has much less surface area than the rest of the leaf. Oxygen inhibition is not a problem there since oxygen, even though abundant, cannot get access to the ribulose biphosphate carboyxlase in the bundle sheath. In essence, the C-4 pathway is a means of getting around oxygen inhibition. PHOTO11 LIGHT AND PHOTOSYNTHESIS PART 2 - PHOTOSYNTHESIS Crassulacean Acid Metabolism (CAM Photosynthesis) CAM photosynthesis occurs in a group of plants collectively known as succulents. Succulents are plants with fleshy stems and/or leaves, such as cacti, Aloe vera, and stonecrops. These are plants of dry climates or deserts. Their chief problem is water loss by transpiration through the stomata on the leaves. As a consequence, desert plants do not open their stomata during the day the time of greatest potential water loss. Instead, they open them only at night with threat of evaporation and transpiration is less and they then run a modified Calvin-Benson cycle to produce glucose. PHOTO12
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more. Course Hero has millions of course specific materials providing students with the best way to expand their education.

Below is a small sample set of documents:

Broward College - BSC - 2010
PROTEINSBelow are some examples of the functionsof proteins.Proteins serve two basic functions: they build and theyregulate. Proteins build in the sense they make up largeportions of your body. For example, muscle is mostlyprotein; protein is found
Broward College - BSC - 2010
CELLULAR RESPIRATIONCellular RespirationOne of my favorite television programs growing up was Mr. Wizard. Mr. Wizard, akaDon Herbert, would invite neighborhood kids over and have them perform scienceexperiments, always having the kid explain what was
Broward College - BSC - 2010
CHROMOSOMAL BASIS FOR INHERITANCERemember, there are 23 pairs of chromosomes. Twenty-two of those pairs are not involved in sex determination. These 22 are called autosomes. Only one pair of chromosomes has anything to do with sex determination. They are
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
Broward College - PHY - 2048
PHY2048 20092Homework Chapter 6Questions p. 19310, 12, 19Problems p. 1947, 9, 10, 14, 17, 21, 29, 33, 36, 42, 53, 59
Broward College - PHY - 2048
Broward College - PHY - 2048
General PhysicsPHY 204820092Instructor:Office:Phone:email:C.J. Roddy07/144954-201-6678croddy@broward.eduOffice hours:M-F 8:00-3:00 pmCourse Description:This course introduces the fundamental concepts that describe the physical world. Topics
Broward College - PHY - 2048
PHY2048 Test 4 TH 20092Name_Questions1. Which will roll down the hill faster, a can of regular fruit juice or a can of frozenfruit juice? Explain your answer.2. When a tether ball wraps around a pole as shown, does the speed of the ballincrease, dec
Broward College - PHY - 2048
Equations of Motion and Problem SolvingProblem Solving protocol:1.2.3.4.5.6.Draw a pictureWrite down what is givenWrite down what is impliedFind an appropriate equationSolve the equationCheck the units.Problem Solving Template1. Drawing2.
Broward College - PHY - 2048
Vector HW 2Which one of the following choices is a vector quantity?(a) mass(c) time(b) temperature(d) displacement(e) volumeWhich one of the following quantities is a vector quantity?(a) the age of the earth(b) the mass of a freight train(c) the
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #20: Homework #11page 1 of 6PHYS 124: Homework #11April 25, 2012Homework #11 is due in Box outside of Rock 207:5:00 PM Sharp, Monday, April 30, 2012However, all students get an automatic penalty-free extension to5:0
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #16: Cycle 3 Review Sheetpage 1 of 4PHYS 124: Cycle 3 Review Sheet, Part 3March 30, 2012Maxwells Equations Microscopic vs. Macroscopic:So we have already seen Maxwells Equation in a complete form where everything we n
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #18: Review Sheet Cycle 4, Part 1page 1 of 3PHYS 122: Cycle 4 Review Sheet Part 1: Magnetic Fields in MaterialsUnder construction.
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #19: Cycle 4 Review Sheet Part 2page 1 of 3PHYS 124: Cycle 4 Review Sheet Part 2: Physical OpticsGeometric vs. Physical Optics:The study of Optics divides neatly into two regimes, depending on the size of the wave comp
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #21: Cycle 4 Review Sheet Part 3page 1 of 4PHYS 124: Cycle 4 Review Sheet Part 3, RelativityApril 20, 2011Michelson - Morley ExperimentAlbert Michelson and Edward Morley conducted an experiment in 1887 to look for evi
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #19: Homework #10PHYS 124: Homework #10April 17, 2012Homework #10 is due in Box outside of Rock 207:5:00 PM Sharp, Monday, April 23, 2012page 1 of 5Physics 124 Spring 2012 Document #19: Homework #10page 2 of 5Probl
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #16: Homework #08page 1 of 2PHYS 124: Homework #08March 30, 2011Homework #08 is due in Box outside of Rock 207:5:00 PM Sharp, Monday, April 26, 2012Reading Assignment from Ohanian and Markert Chapter 33, as follows:
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #14: Cycle 3 Review Sheetpage 1 of 6PHYS 124: Cycle 3 Review Sheet, Part 2March 8, 2012Electric Dipoles:If we have two point charges of equal but opposite magnitude, then we dene the electric dipolemoment as the vect
University of Texas - PHY 303K - phy 303k
Physics 124 Spring 2012 Document #13: Homework #07page 1 of 8PHYS 124: Homework #07March 04, 2012Homework #07 is due in Box outside of Rock 207:4:00 PM Sharp, Friday, March 9, 2012Problem 1:Part (a) Calculate the current though each of the three vo
University of Texas - PHY 303L - PHY 303L
Physics 124 Spring 2012 Document #12: Cycle 3 Review Sheet - Part 1page 1 of 9PHYS 124: Cycle 3 Review Sheet - Part 1February 27, 2012Electric Potential and the Gradient:Lets reconsider the electric potential, which we sometimes call voltage. The ele
University of Texas - PHY 303L - PHY 303L
Physics 124 Spring 2011 Document #11: Homework #06page 1 of 5PHYS 124: Homework #06Feb 27, 2012Homework #06 is due in Box outside of Rock 207:4:00 PM Sharp, Monday, March 5, 2012Reading assignment: Read text by Schey, Div, Grad, Curl and All That C
University of Texas - PHY 303L - PHY 303L
Physics 124 Spring 2012 Document #10: Cycle 2 Review Sheet Part 2page 1 of 12PHYS 124: Cycle 1 Review Sheet Part 2February 13, 2012Cycle 1 Materials:Physics is a cumulative subject and the this is especially so for the Cyclic approach. Thereforeis i
University of Texas - PHY 303L - PHY 303L
Physics 124 Spring 2012 Document #09: Homework #05page 1 of 17PHYS 124: Homework #05Feb 13, 2012Homework #05 is due in Box outside of Rock 207:4:00 PM Sharp, TUESDAY February 21, 2012Announcements: Note that this problem set is due Tuesday instead
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Document #08: Cycle 2 Review Sheet Part 1page 1 of 3PHYS 124: Cycle 1 Review Sheet Part 1February 8, 2011Calculating the Electric Field for Continuous Sources Using Direct IntegrationAs we introduced in Cycle 1, in principle w
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Document #06: Homework #03page 1 of 6PHYS 124: Homework #03January 27, 2012Homework #03 is due in Box outside of Rock 207:4:00 PM Sharp, Wednesday, February 1, 2012Announcements: Mr. Covaults Ofce Hours will generally be Mon
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Document #05: Cycle 1 Review Sheetpage 1 of 15PHYS 124: Cycle 1 Review SheetJanuary 20, 2012This Review Sheet delineates all main topics that students willbe responsible for for the First Hour Exam which will take placeMonday
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Document #03: Homework Guidelines & Examplespage 1 of 6PHYS 124: Guidelines and Examples for Doing Homework ProblemsJanuary 18, 2012Most students in the class have already some experience with solving physics problems. However,
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Document #02: Homework #01page 1 of 8PHYS 124: Homework #01January 18, 2012Homework #01 is due in Box outside of Rock 207:4:00 PM Sharp, Monday, January 23, 2012Announcements: Note: All homework assignments and other Handout
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 First Hour ExamSTUDENT ANSWER SHEETSPHYS 124: First Hour ExamFebruary 6, 2012Do not open this exam until instructed to do so. Pleasecomplete this form and read the rules on this cover sheet now.Your Name: (print neatly!)_You
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Second Hour ExamSTUDENT ANSWER SHEETSPHYS 124: Second Hour ExamFebruary 24, 2012Do not open this exam until instructed to do so. Pleasecomplete this form and read the rules on this cover sheet now.Your Name: (print neatly!)_
University of Texas - PHYS 303K - 21348
Physics 124 Spring 2012 Third Hour ExamSTUDENT ANSWER SHEETSPHYS 124: Third Hour ExamApril 4, 2012Do not open this exam until instructed to do so. Pleasecomplete this form and read the rules on this cover sheet now.Your Name: (print neatly!)_Your C
University of Texas - PHYS 303K - 3298
Physics 122 Spring 2008 Practice Problems with Solutionspage 2 of 14Problem P12: Flux ConceptsAB+CD+SNThe gure above shows four scenarios. In each case we consider the ux through an imaginaryclosed surface which is cylindrical. The closed surf
University of Texas - PHYS 303K - 3298
P124 Practice Problem: Faradays Law with a U-bar: With Solutionpage 1 of 4PHYS 124: Feb 26, 2010Problem: Faradays Law u-bar railHeres a problem to get more practice with Faradays Law. We still have a spatially uniformeld, but now the area is changing
University of Texas - PHYS 303K - 3298
Physics 122 Practice Problem of the Day #22page 1 of 1Physics 122: Practice Problem of the DayProblem #22: Using Gauss Law for a spatially varying charge density with planar symmetrySunday, April 5, 2009 Suppose we are given a continuous charge distri
University of Texas - PHYS 303K - 3298
Physics 122 Spring 2008 Practice Problems with Solutionspage 5 of 14Problem P13: Hoop in a SolenoidA solenoid with wire density n carries a current that varies with time according toI (t) = I0 et/ cos(t)Inside the solenoid is a circular hoop (radius
University of Texas - PHYS 303K - 3298
P124 Practice Problem: Maxwells Revenge: With Solutionpage 1 of 3PHYS 124: Feb 26, 2010Problem: Maxwells RevengeSuppose an electric potential function is dened within some arbitrary region as a position ofboth time and space in accordance with the fo
University of Texas - PHYS 303K - 3298
P124 Practice Problem Capacitorpage 1 of 4A Dielectric Diamagnetic CapacitorCapacitor made fromtwo circular plates eachwith radius a, separation D+V0rrR1rA circuit includes a capacitor made from two circular plates each with area A = a2 with a
University of Texas - PHYS 303K - 3298
Physics 124 Spring 2011 Third Hour Exam With SOLUTIONS1PHYS 124: Third Hour ExamMarch 28, 2011Do not open this exam until instructed to do so. Pleasecomplete this form and read the rules on this cover sheet now.Your Name: (print neatly!)_Your Case
UGA - MATH - 2260
Math 2260 Exam #1 Practice Problems1. What is the area bounded by the curves y = x2 1 and y = 2x + 7?2. What is the volume of the solid obtained by rotating the region bounded by the graphs of y =y = 2 x and y = 0 around the x-axis?x,3. What is the v
UGA - MATH - 2260
Math 2260 Exam #1 Practice Problem Solutions1. What is the area bounded by the curves y = x2 1 and y = 2x + 7?Answer: As we can see in the gure, the line y = 2x + 7 lies above the parabola y = x2 1 in theregion we care about. Also, the points of inters
UGA - MATH - 2260
Math 2260 Exam #1 Solutions1. (12 points) The curves determined by the equations y = x2 and x = y 2 enclose a region in the rstquadrant, as seen below.(a) What is the area of this region?Answer: First, notice that the portion of the curve x = y 2 adja
UGA - MATH - 2260
Math 2260 Exam #2 Practice Problems1. Evaluatetan3 (x) dx.2. Integratesin4 (2x) dx.3. Integrate4. Evaluateex2 25dx.x1dx.x(ln x)35. Suppose a 20 foot chain which weighs 5 pounds per foot is coiled on the ground. One end of the chainis attach
UGA - MATH - 2260
Math 2260 Exam #2 Practice Problem Solutions1. Evaluatetan3 (x) dx.Answer: Recall that tan(x) =sin(x)cos(x) ,so the above integral is equal tosin3 (x)dx.cos3 (x)Now, use the trig identity sin2 (x) = 1 cos2 (x) to re-write this assin2 (x) sin(x)
UGA - MATH - 2260
Math 2260 Exam #2 Solutions1. Integratexdx.x2 5x + 4Answer: I will use the method of partial fractions. First, I factor the denominator:xx=.x2 5x + 4(x 4)(x 1)Now, split this into two unknown fractions:ABx=+.(x 4)(x 1)x4 x1To solve fo
UGA - MATH - 2260
Math 2260 Exam #3 Practice Problems1. Does the following series converge or diverge? Explain your answer.2n.3n + n3n=02. Does the following series converge or diverge? Explain your answer.n.3nn=13. Does the following series converge or diverge?
UGA - MATH - 2260
Math 2260 Exam #3 Solutions1. Consider the sequence (an )n=1 wherean = n2 + n1/n.Does this sequence converge or diverge? If it converges, nd its limit.Answer: Notice that the term inside parentheses is going to , whereas the power is going to zero,
UGA - MATH - 2260
Math 2260 Final Exam Practice Problem Solutions1. Write down an integral which will compute the length of the part of y = ln x for 1 x 2. Dontworry about evaluating this integral.Answer: Sincedydx1= x , the arc length integral is21+11x22dx
UGA - MATH - 2260
Math 2260 HW #1Due 10:10 AM Friday, January 13Reading: Hass 5.15.5Problems: Do the assignment HW1 on WebWork. In addition, write up solutions to thefollowing problems and hand in your solutions in class on Friday.1. Evaluate the denite integral942
UGA - MATH - 2260
Math 2260 Written HW #1 Solutions1. Evaluate the denite integral942 dx.xAnswer: We can re-write this integral as92x1/2 dx,4which we can then integrate using the Fundamental Theorem of Calculus and the Power Rule:991/22x4x1/2dx = 21/24
UGA - MATH - 2260
Math 2260 HW #2Due 10:10 AM Friday, January 20Reading: Hass 6.16.2Problems: Do the assignment HW2 on WebWork. In addition, write up solutions to thefollowing problems and hand in your solutions in class on Friday.1. Find the area of the region that i
UGA - MATH - 2260
Math 2260 HW #4Due 10:10 AM Friday, February 3Reading: Hass 6.5Problems: Do the assignment HW4 on WebWork.1
UGA - MATH - 2260
Math 2260 HW #5Due 10:10 AM Friday, February 10Reading: Hass 6.5 & 7.2Problems: Do the assignment HW5 on WebWork. In addition, write up solutions to thefollowing problems and hand in your solutions in class on Friday.1. A spring has a natural length
UGA - MATH - 2260
Math 2260 Written HW #5 Solutions1. A spring has a natural length of 10 in. An 800-lb force stretches the spring to 14 in.(a) Find the force constant.Answer: Since 14 10 = 4 inches isknow that13of a foot and since, by Hookes Law, F = kx, we1800 =
UGA - MATH - 2260
Math 2260 Written HW #6 Solutions1. A lab receives a sample of polonium-210, which has a half-life of 139 days. The sample will beeectively useless by the time 95% percent of the radioactive nuclei present when the samplearrived have decayed. For how l