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### Lab28 INductance

Course: PHYSICS 1A+1B, Fall 2010
School: Laney College
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Word Count: 438

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the Lab12 Measuring Inductance of an Inductor Instructor: Dr. Mohebi Jiajie Huo(Jacky) Member: Ruihong Xiao TEJ Shiwakoti Anthony Hernandez Dana Saiez Rneiang Ye WAJIH RAHMAN 2. introduction In this experiment, we are generally focusing on measuring the inductance of an inductor and compare the experimental one with the theoretical one. 2 2 1. L=sqrt((R/x) -(r+R) )/2pi*f, while f refers to the frequency of the...

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Coursehero >> California >> Laney College >> PHYSICS 1A+1B

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the Lab12 Measuring Inductance of an Inductor Instructor: Dr. Mohebi Jiajie Huo(Jacky) Member: Ruihong Xiao TEJ Shiwakoti Anthony Hernandez Dana Saiez Rneiang Ye WAJIH RAHMAN 2. introduction In this experiment, we are generally focusing on measuring the inductance of an inductor and compare the experimental one with the theoretical one. 2 2 1. L=sqrt((R/x) -(r+R) )/2pi*f, while f refers to the frequency of the ac resource, R refers to the resistance of the resistor, r refers to the resistance of the inductor. x refers to the potential difference between point B and point C. 3. Procedure. Measure the wire resistance of the inductor , and we got r=2.3. 2. Assembled the circuit shown above and adjust the generator. We got R=100, and the changed the frequency of the generator to 3.48KHz. 3. Measure the potential difference across the inductor, so Vac=0.848V 4. Measure the potential difference between the generator, Vab=1V. 5. Read the potential difference across points C and B, and it is x=0.506V. 6. Subsititute the measured values into the formula to determine the inductance L, and we got L=0.0127H. 7. Repeat the measurement for another value of resistance, with the same frequency. 8. Repeat the measurement for another value of frequency and the same resistance. 1. 9. Compare the result for different values of resistance the and frequency. 10. Compare potential drop across the inductor with that across the resistor, find out which one is greater. We find that the potential drop is larger between the resistance R, and it makes sense because the resistance of R is greater than that of r. 11. Calculate the inductive reactance of the inductor for each case. 12. Calculate the impedance of the circuit. 13. Calculate the rms current in the circuit 14. Try to insert a metal core inside the coil, and find out the change of the inductance. And we found that the inductance of it had increased. 2. Data and result. f(KHz) 3.48 3.48 4.243 R() 100 150 100 r() Uab(V) 2.3 2.3 2.3 1 1 1 Uac(V) 0.848 0.724 0.88 Ubc(V) 0.506 0.66 0.42 Ltheo(H) Lexp(H) 6. Discussion and conclusion. In this experiment, we use the battery and the resistance and the bulb to prove the Ohms law. However, in the result, we find that the resistor is a ohmic device and it obeys Ohms law, and we found the difference of the experimental and actual resistance is 30%. On the other hand, the bulb do not obey Ohms law. We found that this result appeared due to the bulb is not a Ohm device and its internal resistance is changing when its temperature is changing. And the change of the temperature may due to the change of the current. Above all, this experiment is successful.
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