Rutgers - MATH - 115

Rutgers - MATH - 115

(1) For each of the functions given, sketch a graph of the function. Clearly label any keypoints and asymptotes. Then nd the exact value of any x- or y -intercepts.(a) 2x+5 3(b) ex1 2(c) 3x+1 + 1(d) log2 (x 4) + 1(e) ln(x + 2) 1(f) ln(x + 1) 1(2)

Rutgers - CHEM - 170

1. If you must smell a chemical, what is the procedure?-Waft the odor under your noseHow do you handle poisonous or noxious gases in the lab?-Use the fume hood2. This question refers to the experiment entitled: DENSITY: A PHYSICAL PROPERTY OFMATTER.

Rutgers - CHEM - 170

Chem 171 Quiz 10 Version A1. Hydrogen gas produced in the following reaction is collected over water at 296 K; thepressure is 742 mmHg.2 Al (s) + 6 HCl 2 AlCl3 (aq) + 3 H2(g)What volume of the wet gas will be collected in the reaction of 1.50 g Al (s)

Rutgers - CHEM - 170

Intro To Experimental ChemistryAtomic Orbitals Study GuideTopicConceptsExperimentAtomic OrbitalsIsosurfaces of variousAtomic Orbitals (single atomic orbitals and somewindow)hybrid orbitals aredisplayed.OrbitalsIsosurfaces, radialdistribution

Rutgers - CHEM - 161

Rutgers - CHEM - 161

Rutgers - CHEM - 161

Chemistry 161 Exam I September 30, 2009Student Name (Print): _Recitation Section Number:Recitation Instructor: _The exam booklet has 25 questions for credit and one additional question to check the color of yourexam booklet. Please answer all 26 ques

Rutgers - CHEM - 161

Chemistry 161 Exam IIIDecember 2, 2009Student Name (Print): _Recitation Section Number:Recitation Instructor: _The exam booklet has 25 questions for credit and one additional question to check the color of yourexam booklet. Please answer all 26 ques

Rutgers - CHEM - 161

Chemistry 161 Exam II October 28, 2009Student Name (Print): _Recitation Section Number:Recitation Instructor: _The exam booklet has 25 questions for credit and one additional question to check the color of yourexam booklet. Please answer all 26 quest

University of Florida - PUR - 3000

PUR3000NotesforExam2Chapter6FocusontermsandlistsfromthetextChapter 7The Goals of CommunicationoThethirdstepinthepublicrelationsprocessiscommunicationwhichistheimplementationofadecision,theprocessandthemeansbywhichobjectivesareachieved.oThisstepisal

University of Florida - PUR - 3000

PUR3000NotesforExam2Chapter6FocusontermsandlistsfromthetextChapter 6n The Value of Planningn Thesecondstepinthepublicrelationsprocessisplanning.n PlanningistheActioninRACEtheorganizationstartsmakingplanstodosomethingaboutanissueorsituation.n PRpl

University of Florida - MAN - 4504

TRANSPORTATION MODELS NOTES1) Transportation Modeling = A ninteractiveproc edurethatfindstheleastc ostlym eans ofm ovingproductsfro m aseriesofsourcestoaseriesofdestinations;Canbeusedto helpresolvedistributionandlocationdecisionsa) Aspecialclassofline

University of Florida - MAN - 4504

CHAPTER9LAYOUTSTRATEGIESa) MCDONALDSNEWLAYOUTa. Seventhmajorinnovationb. Redesigningall30,000outletsaroundtheworldc. Threeseparatediningareasd. LingerzonewithcomfortablechairsandWiFiconnectionse. Grabandgozonewithtallcountersf. Flexiblezoneforkidsa

University of Florida - GEB - 3373

A) DenteksUKDecisiona. JohnJanshekiisobviouslyanentrepreneuralthoughlargelyselftraineda.i. DentekisasmallfishinaverylargepondwithintenserivalryfromMNEslikeJ&J,P&Getca.i.1.Theyhaveatargetmarketbuttheycompeteheadtoheadagainstthesebigcompaniesa.ii. Gr

University of Florida - GEB - 3373

GEB 3373ONLINESpring 2011Exam 1 Answer1. According to the lecture, the term Global Business, in contrast to International Business,implies thatd. the importance of a home country is diminished because the essence of concern ishow to integrate the v

University of Florida - MAR - 3023

Summer 2009 Midterm 3 Answer KeysIf you missed the midterm tonight due to illness or family emergency, you need to contact me immediately viathe course email address to make arrangements for a makeup exam.The answer keys for all five forms of the exam

University of Florida - MAR - 3023

Summer 2009 Midterm 1 Answer KeysIf you missed the midterm tonight due to illness or family emergency, you need to contact me immediately viathe course email address to make arrangements for a makeup exam.The answer keys for all four forms of the exam

University of Florida - MAR - 3023

Summer 2009 Final Exam Answer KeysIf you missed the midterm tonight due to illness or family emergency, you need to contact me immediately viathe course email address to make arrangements for a makeup exam.The answer keys for all four forms of the exam

Purdue - ECE - 433

1ECE433-Midterm#2, April 11, 2011Name:PUID:1) True/False (10 pts). Briefly explain your answer and your judgment. Otherwise you donot get the credit.1-1)For a tolerance-band current controlled inverter, the switching frequency depends on theload to

Purdue - ECE - 433

ECE433-E xam 2,Name:March 28, 2012PUID:L) True/False (10 pts). Briefly explain your answer and your judgment. Otherwise you donot get the credit.1-1) A unipolar PWM, compared with a bipolar PWM, results in a lower THD of the loadvortageandcurrent T

Purdue - ECE - 433

id6n_ulr0zO1tf:lzIJf(o)t1r-Tf-ode =-LtVdc'Tr g(osvrsalzcosno ds=-LW t*,*-e)1T rnz Vdc sn =+WfT-,tlzh-+ -lzJrs) S'rho)doz4n s*") lo'TI "Ighnlz 6Pg notlz,.fl'+'-zsn/bcosl')f uit'T:Ivdc sanoo) dooLt!c. -= 1n-_2\&1l'

Purdue - ECE - 433

ECE433, Homework 3Due: March 9, 20121) A flyback converter is to be designed for an isolated computer laptop automotive charger. Theinput voltage ranges fromand the output voltage is to be regulated atand the switching frequency is. Nominal load is

Purdue - ECE - 433

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Purdue - ECE - 433

ECE433 HW4Due Date : 26th March (Monday)1) Given the following half-bridge inverter.+50Dl+50D2a)Determine a switching scheme that provides an ac output voltage vas.b)For the switching scheme in a) plot the voltage vas, and the current i as a s

Purdue - ECE - 433

ECE433 - HWl) Given the following half-bridge inverter.a)b)Determine a switclling scheme that provides an ac ouut voltage un".For the switching scheme in a) plot the voltage vas, and the current io, assuming a purelyinductive load. Label the devices

Purdue - ECE - 433

r)\rt( n llt v u'u'ttn ftt li',e ccsl'.&) 4nrrt3517, =5g?r) 3(-(tco)(t')Lutf-)7 + 3.6(Po)4 Ls =:so= t*s,sL,$tiuo)(tei)b)sl=|tLt Lcu*(nnCoSI: - Tuu)ui3 )(i'ti 32)--/ff LLo),tc-_aa,( ,_3L)ruec)(t"'l3 )Ltt/ft z'c))= IT-s;-I)a'

Purdue - ECE - 433

ECE433, Homework 5Due: April 20, 20121) Given a 3-phase rectifier that has = 100/ . The amplitude of the source voltage is220V, and L=1 mH. The average output voltage out of the rectifier is 350V.a) Determine the dc current out of the rectifier.b)

Purdue - ECE - 433

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Purdue - ECE - 433

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Purdue - ECE - 433

Bipolar PWMIrlina =ie>. ". ."#,r;ort'i'r,;tf!.t#H*ffio< t:AmPlitude Modulation Ratio: Frequency Modutation RatioItt-: Linear ModulationRange -"-h: t'S" - "'-VOt= moVr,tLo Sir3rllCl,tir,1i,LtsL-1ll-i *- cfw_.1'icfw_lll *'#IT"*

Purdue - ECE - 433

OvermodulationiTrt*t,i"r*De*i(t[,.+-oT*Drl*DB*i%t"+(;,rn'r*ttl'" inlllh ( ii'&stre cunpl,'lc\rc'[ lriias L'a*nn\ti\ A -*^n'cv -r"t *"YryI'nfd \gcfw_rwtct.,5- t@Mtttx,ri tfreLLt rY\tL, .)6tftSvWwPt)i Iitlrr npwnlt\ ,h,ch t.r o

Purdue - ECE - 433

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Purdue - ECE - 433

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Purdue - ECE - 433

Purdue - ECE - 433

Kt/tiute/;S'iottr o tae Set o? solarB'a rrtor.t (/49rr,paorrs )e[r,vrrr4A,tc mn&,t& ufteutlhe tanettk 'tctal"rc. ,_yo[tay ataf ol'ta ;ft ft Wto & snfe4,rc(i"nler,erX+/\vn/1!tu\N ,fnnt Jhu arat"kNJcfw_4rNt,I^\Mu,a,trh rfit't,tto'u

Purdue - ECE - 433

S;nXle _1*.Dioe riclXel,tpeuh'eui fe nerhp Wo+n)d^or,lle brdge ruhhffil$eae#nfaWn ttic nhteWtat:rfr)f Urh)" I Drb.D+;oN'+q)D tbD3'4\o'in.-Ito, ui'r if'Jrn (oD,Lo04zVl,4ot-. \)inin0t'G-,t,:6FD3 '0'+/4/inconPtm &et'h'e' )

Purdue - ECE - 433

tWtUtn,tl,r1 [)h6a = -i.JinD',hD- :a,tt,nzs'rtffiIIIL6'b-WWu*iffou.offl,DzbDSto"rylfir',f(-r0\io"bb:-th, Pedt tJ'fuflenPafrrloave)(0t&the, uloJ,scfw_rnm 'uo, + ntatru[&J1 bL see.tlYl)h,t *t<rfracnplre(t+tt'f hsr'nFantucfw

Purdue - ECE - 433

fi.eW&of,Sete.('rcnluttcl-ftt Olt llt rtftfrZ'tre'n a/(rnabtun )ter,l, W*,#er (nen-'lo*1.4"*"uM-b;n:cWeLo =l futsu.*,V l- ,t trf1Lwo)Lu6ls'ftc"J.n n M-,&WM bnry, fz'r' u'i'enlcfw_an*ur-twyu11, r'e6a*rueho*leqde p"\rr Unn wrh* hc\a.ee*'Vi

Purdue - ECE - 433

y(ru fh ull:IIO lon:*," lflftRecfrt(ttrh SSneJfutoe_briqea/ ocfw_ (/'/crt -a/(K?r,fw/tl$tql Accfw_antcs(/-r:).l'tnut'1vr,>'ryqWe nPLd'rtP'olAuout-| t'srt, oru la rcunef +Ip u'N-fcfw_r-ryLageuokae n/r, /ua a'P/rkternYcfw_- ue-,d

Purdue - ECE - 433

Lf a4tA(ffc 4 D '-N o =abrvoFF0L br '4Uu(ubtjDt"-o"M 7'at?'bDrP \)c(vubu+tlav-bt 0tPs:fDS'-at -_4 d=WP; 0;.":'fF,C,ouk*oWsinu&+Y!u'*,:W+. 'h"v\tn^ =hr+'VfN nt >' w(,&*\'Three-Phase Full Brdge Rectifiel'with ldeal Sourcels =0:

Purdue - ECE - 433

F'u.J5D5,D6!iiDl,vzD2,D3rlt:Ii D3,Dt 1,D5D5.D6; D6.DI'tIDiode Currnt in Three-Phase Full Bridge Diode Rectfier6-i.(-rlrf\=l=-A'^r\-\ 'S^"1-.rS\-r_t\a\$\>$P.'NFS\t"f\:.5's-n'='rL-'\r /,=r.F'C/J^\s')' si!cg\\

Purdue - ECE - 433

_)fcfw_t ali' l-JLsf,, cdnrry&r,rr,tr(rM(*'^ffi^u nb"rly!.r#,W\|,:ffi#:Ils6oUrh>qw(wurt _l. or o q& on '^ <ua'l, ,o#nnD6,conwahbn at urrl &ro^ D6ta aLqj&b)'rntrrrurP,AWd(, 2/rt, sltrt 'frt05, ob:,T,Dh/D I:05, DL,DIi qn'on'len

Purdue - ECE - 433

hxp,(vn E qLuvdl,et u'ntv'1t aP ll.e'4.-hft9de-\'r'etLs -l- I ryJCtf,ftWTirs?r l-^jVu.r(vo,t>=Ftn[ 'ro'l ]i:C,Sy..: | - )ut L 5'Lourt.16r^4 4n,*),$m ur9,4t,t/rilr(k1rrt)-*okswarCiaJcas616,Laitt1Jcfw_t-lL ouiI\nn/e . the

Purdue - ECE - 433

1,ECE433-Exam L, February 22,2012,6:00-7:45Name:pMPUID:Note: For each question, you have to develop the mathematical equations and showthe comprehensive work to get the credit. Do not write any final equation withoutshowing the procedure. otherwise

Purdue - ECE - 433

EcE433-Midterm#2, APril 11, 2011Name:PUID:L) True/False (10 pts).Briefly explain your answer and your judgment. Otherwise you donot get the credit.l-l)For a tolerance-band current controlle-d inverter, the switching frequency depends on the;ni ux n

Purdue - ECE - 433

Project 2: Analysis of PWM InvertersDue: April 6, 2012NOTE: Sharing the codes or reports is prohibited. In Project 1, there were a few cases withsimilar reports. You have to present your own work to get the credit for the project. Incase of plagiarism

Purdue - ECE - 433

ECE 433- Project 3Project#3 is a team-work research project on one of the suggested topics. Each team consists of3 students to do the following tasks:1) Choose one of the topics2) Understand the basics of operation of the chosen circuit and its corres

Purdue - ECE - 433

ECE433- Quiz 4 - March 23, Z0lzName:PUID:For a UNIPOLAR PWM H-bridge inverter, shown in Fig. I (sinusoidal and triangular waveformsshownin the next page):a) Specify the modulation index and the frequency ratio.'fa=+k:D,q+@= o'B =o,BVtrt1f"*

Purdue - CE - 371

1.1-2A building wall consists of 12-in. clay- brick and 2 x 4 unplastered woodstuds on both sides. Ifthe wall is 8 ft high, determine the load in pounds per foot length of wall that it exerts on thefloor.Using the data in Table 1-3,Minimum Design De

Purdue - CE - 371

CE 371 Section 001HW No. 121) 6-1333535(Points 10)2) 6-7(Points 10)3) 6-9(Points 10)4) 6-20Sol:MDmax(+) = 80(1/2)(5)(20) + 500(5)= 6500lbft = 6.50k.ftAnsBYmax(+) = 80(1/2)(1.75)(35) + 500(.75)= 3325lb = 3.32kAns(Points 10)5) 6-73Sol:

Purdue - CE - 371

CE 371.01 Structural Analysis IHomework #2due 12 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 2.2. Start reading Chapter 3.B. Problem assignments:Solve5. 2-28.6. 2-29.7. 2-34.8. 2-38.

Purdue - CE - 371

CE 371.02 Structural Analysis IHomework #3due 19 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 3.2. Start reading Chapter 4.B. Problem assignments:9. Classify each structure shown below as stable or unstable. If st

Purdue - CE - 371

CE 371.02 Structural Analysis IHomework #4Due 26 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 4.2. Read Chapter 8 Sections 8-1, 8-2, and 8-3. Note that you should be familiar with these topicsfrom CE270.B. Problem

Purdue - CE - 371

CE 371.01 Structural Analysis IHomework #724. Using the moment-area theorems, determine the slope at point B and the deflection at point C.E and I are constant over the length of the member. Assume that the support at A is a roller andthe support at B

Purdue - CE - 371

CE 371 - Section 02Homework No. 6 - Solutions8- 3Determine the equations of the elastic curve for the beam using the x1 and x2 coordinates.Specify the slope at A and the maximum deflection. EI is constantSol:PPM1 (x) = Px1M2 (x) = Pax1ax2 - a

Purdue - CE - 371

Purdue - CE - 371

CE 371.02 Structural Analysis IHomework #4 SolutionsSol:2.31kNEDB4530A X = 231kNCA2m2mAY =2kN2kNJoint E:2.31kN30FEAFEC1/7+ !FY = 0;FEA = FEC+ ! FX = 0 ;2.31 2FEA sin 30 = 0FEA = 2.31 kN (C)Ans (2 Points)FEC = 2.31kN (T)Ans (1

Purdue - CE - 371

CE371 Homework No. Zero (thats right! #0)Taken from CE270 Final Exam Spring 2008Name: _ ID # (last 5 digits): _Start time: _End time:_General Instructions:This is a closed book homework. A formula sheet is provided at the backThere will be partial

Purdue - CE - 371

C E 371 - Se c t io n 002HW No. 10Sol:FEMBC = -wL2/12 = -81;FEMCB = wL2/8 = 81FEMCD = -3PL/16 = -27BC = 0AB =CD =MBA =3EI(B +)/12MBC =2EI(2B +C)/18 81MCB =2EI(2C +B)/18 + 81MCD =3EI(C +)12 27MBA + MBC = 0;0.472EIB +0.11EIC +0.25EI=81( Po i n

Purdue - CE - 371

CE 371.02 Structural Analysis IHomework #5: SolutionsTotal = 80 pointsSol:12kN/m3 0kN/m48kN5m5m12kNV(kN)48Points 5x4m-12M(kN.m)96Points 59060x1/8Sol:Using the FBDs of members ABC and BCD:+MA = 0;CY (5) BY (3) -15(1.5) = 0+MD = 0