4 Pages

Lect32a

Course: ECE 433, Spring 2012
School: Purdue
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Word Count: 408

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Purdue - ECE - 433
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Purdue - ECE - 433
Lf a4tA(ffc 4 D '-N o =abrvoFF0L br '4Uu(ubtjDt&quot;-o&quot;M 7'at?'bDrP \)c(vubu+tlav-bt 0tPs:fDS'-at -_4 d=WP; 0;.&quot;:'fF,C,ouk*oWsinu&amp;+Y!u'*,:W+. 'h&quot;v\tn^ =hr+'VfN nt &gt;' w(,&amp;*\'Three-Phase Full Brdge Rectifiel'with ldeal Sourcels =0:
Purdue - ECE - 433
F'u.J5D5,D6!iiDl,vzD2,D3rlt:Ii D3,Dt 1,D5D5.D6; D6.DI'tIDiode Currnt in Three-Phase Full Bridge Diode Rectfier6-i.(-rlrf\=l=-A'^r\-\ 'S^&quot;1-.rS\-r_t\a\$\&gt;$P.'NFS\t&quot;f\:.5's-n'='rL-'\r /,=r.F'C/J^\s')' si!cg\\
Purdue - ECE - 433
_)fcfw_t ali' l-JLsf,, cdnrry&amp;r,rr,tr(rM(*'^ffi^u nb&quot;rly!.r#,W\|,:ffi#:Ils6oUrh&gt;qw(wurt _l. or o q&amp; on '^ &lt;ua'l, ,o#nnD6,conwahbn at urrl &amp;ro^ D6ta aLqj&amp;b)'rntrrrurP,AWd(, 2/rt, sltrt 'frt05, ob:,T,Dh/D I:05, DL,DIi qn'on'len
Purdue - ECE - 433
hxp,(vn E qLuvdl,et u'ntv'1t aP ll.e'4.-hft9de-\'r'etLs -l- I ryJCtf,ftWTirs?r l-^jVu.r(vo,t&gt;=Ftn[ 'ro'l ]i:C,Sy..: | - )ut L 5'Lourt.16r^4 4n,*),$m ur9,4t,t/rilr(k1rrt)-*okswarCiaJcas616,Laitt1Jcfw_t-lL ouiI\nn/e . the
Purdue - ECE - 433
1,ECE433-Exam L, February 22,2012,6:00-7:45Name:pMPUID:Note: For each question, you have to develop the mathematical equations and showthe comprehensive work to get the credit. Do not write any final equation withoutshowing the procedure. otherwise
Purdue - ECE - 433
EcE433-Midterm#2, APril 11, 2011Name:PUID:L) True/False (10 pts).Briefly explain your answer and your judgment. Otherwise you donot get the credit.l-l)For a tolerance-band current controlle-d inverter, the switching frequency depends on the;ni ux n
Purdue - ECE - 433
Project 2: Analysis of PWM InvertersDue: April 6, 2012NOTE: Sharing the codes or reports is prohibited. In Project 1, there were a few cases withsimilar reports. You have to present your own work to get the credit for the project. Incase of plagiarism
Purdue - ECE - 433
ECE 433- Project 3Project#3 is a team-work research project on one of the suggested topics. Each team consists of3 students to do the following tasks:1) Choose one of the topics2) Understand the basics of operation of the chosen circuit and its corres
Purdue - ECE - 433
ECE433- Quiz 4 - March 23, Z0lzName:PUID:For a UNIPOLAR PWM H-bridge inverter, shown in Fig. I (sinusoidal and triangular waveformsshownin the next page):a) Specify the modulation index and the frequency ratio.'fa=+k:D,q+@= o'B =o,BVtrt1f&quot;*
Purdue - CE - 371
1.1-2A building wall consists of 12-in. clay- brick and 2 x 4 unplastered woodstuds on both sides. Ifthe wall is 8 ft high, determine the load in pounds per foot length of wall that it exerts on thefloor.Using the data in Table 1-3,Minimum Design De
Purdue - CE - 371
CE 371 Section 001HW No. 121) 6-1333535(Points 10)2) 6-7(Points 10)3) 6-9(Points 10)4) 6-20Sol:MDmax(+) = 80(1/2)(5)(20) + 500(5)= 6500lbft = 6.50k.ftAnsBYmax(+) = 80(1/2)(1.75)(35) + 500(.75)= 3325lb = 3.32kAns(Points 10)5) 6-73Sol:
Purdue - CE - 371
CE 371.01 Structural Analysis IHomework #2due 12 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 2.2. Start reading Chapter 3.B. Problem assignments:Solve5. 2-28.6. 2-29.7. 2-34.8. 2-38.
Purdue - CE - 371
CE 371.02 Structural Analysis IHomework #3due 19 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 3.2. Start reading Chapter 4.B. Problem assignments:9. Classify each structure shown below as stable or unstable. If st
Purdue - CE - 371
CE 371.02 Structural Analysis IHomework #4Due 26 September 2008, Friday, 11:30amA. Reading assignments:1. Finish reading Chapter 4.2. Read Chapter 8 Sections 8-1, 8-2, and 8-3. Note that you should be familiar with these topicsfrom CE270.B. Problem
Purdue - CE - 371
CE 371.01 Structural Analysis IHomework #724. Using the moment-area theorems, determine the slope at point B and the deflection at point C.E and I are constant over the length of the member. Assume that the support at A is a roller andthe support at B
Purdue - CE - 371
CE 371 - Section 02Homework No. 6 - Solutions8- 3Determine the equations of the elastic curve for the beam using the x1 and x2 coordinates.Specify the slope at A and the maximum deflection. EI is constantSol:PPM1 (x) = Px1M2 (x) = Pax1ax2 - a
Purdue - CE - 371
Purdue - CE - 371
CE 371.02 Structural Analysis IHomework #4 SolutionsSol:2.31kNEDB4530A X = 231kNCA2m2mAY =2kN2kNJoint E:2.31kN30FEAFEC1/7+ !FY = 0;FEA = FEC+ ! FX = 0 ;2.31 2FEA sin 30 = 0FEA = 2.31 kN (C)Ans (2 Points)FEC = 2.31kN (T)Ans (1
Purdue - CE - 371
CE371 Homework No. Zero (thats right! #0)Taken from CE270 Final Exam Spring 2008Name: _ ID # (last 5 digits): _Start time: _End time:_General Instructions:This is a closed book homework. A formula sheet is provided at the backThere will be partial
Purdue - CE - 371
C E 371 - Se c t io n 002HW No. 10Sol:FEMBC = -wL2/12 = -81;FEMCB = wL2/8 = 81FEMCD = -3PL/16 = -27BC = 0AB =CD =MBA =3EI(B +)/12MBC =2EI(2B +C)/18 81MCB =2EI(2C +B)/18 + 81MCD =3EI(C +)12 27MBA + MBC = 0;0.472EIB +0.11EIC +0.25EI=81( Po i n
Purdue - CE - 371
CE 371.02 Structural Analysis IHomework #5: SolutionsTotal = 80 pointsSol:12kN/m3 0kN/m48kN5m5m12kNV(kN)48Points 5x4m-12M(kN.m)96Points 59060x1/8Sol:Using the FBDs of members ABC and BCD:+MA = 0;CY (5) BY (3) -15(1.5) = 0+MD = 0
Purdue - CE - 371
Homework No. 11CE 371 - Structural AnalysisProblem No. 12 -1FEMAB = -11wL2/192 = -51.56FEMBA = 5wL2/192 = 23.44FEMBC = -15PL/48 = -37.5FEMCB = 15PL/48 = 37.5KAB = 4EI/6&amp;KBC = 4EI/8DFAB = (4EI/6)/ (4EI/6+) = 0 = DFCBDFBA = (4EI/6)/ (4EI/6 + 4EI/
Purdue - CE - 371
Purdue - CE - 371
Purdue - CE - 371
CE 371 - HOMEWORK NO. 9Instructor: Varma, Section 1.Sol:FEM AB = wL2/30 = -54,FEMBC = 3PL/16 = -902FEMBA = wL /20 = 81(Points 2)MAB = 2EI(B)/9 54MBA = 2EI(2B)/9 + 81MBC =3EI(B)/6 90(Points 3)Moment equilibrium at BMBA + MBC = 04EI(B)/9 + 81
Purdue - CE - 595
CE595- Finite Elements in ElasticityEXAM No. 2Consider the concrete dam structure shown below. Assume that the concrete will have a nominalcompressive strength of 3500 psi. Develop a finite element model for the structure. Analyze themodel for two loa
Purdue - CE - 595
CE 595 Finite Elements in ElasticityA. VarmaExam No. 1Problem No. 1(Worth 30 points)A solid column with varying cross-sectional area (A=Ao ey/L) as shown in Figure 1 issubjected to uniform loading at the top. This loading produces stress o at the to
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CE595:Homework No. 6Given: Cantilevered beam with dimensions shown; rigidly fixed at x = 0; appliedtraction at x = 18. E = 27,000 ksi; = 0.25. Additional loading due to self-weight of steel= 0.003 k/in3.Required: Using CST plane stress elements, find
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CE 595 Finite Elements in ElasticityHomework No. 2For the beam-column problem shown below, use variational calculus to determine the governingdifferential equation, and the associated natural and forced boundary conditions at the ends.Use the given en
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EE321 ABET ExamSpring 2012You may establish credit for ABET objectives (by answering the followingquestions).1.)Objective 1. Ability to Analyze / Design Electromagnetic Devices.A solenoid is an electromechanical device used for actuation. In this si
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E;CEgl'llECEs9s ExamSpring 20121Notes: You must show work for creditThis exam has 5 problems and 12 pages.Note that problems 11 3, and 5 have different specifications depending onyou are in ECE321 orECE595Good luck!ifr)15pts.Consider a H-field
Purdue - ECE - 321/595
5, ^1;ot'lEeE32fC8595 Exm2Sprine 2012Nb'tss.rYou mus.t show work for crdi'This exam has 5 problems and 1.4 pages.Note that problems 2 and 3 have different specifications depending on if youare in ECE-321 or E-CE595Remembr io alw*ys work easier pro
Purdue - ECE - 321/595
EC32L4ECE595 Exam 3Spring2012SolutionNotes: You must show work for credltThis exam has 5 problems and 13 pages.Note tat problems 2r3, anil4 have different specifications depending onyou are in ECE321 or ECE595.Remember to always work easier problem
Purdue - ECE - 321/595
EE321 Spring 2012, HW #6Problem 1ra := 8kv := 0.016K := 5 10va := 6kv ( va kv r)ra= K rSet Te = Tlvar := kv 2kv + K rar = 428.571rad/sProblem 2ra := 10Rf := 50LAF := 0.5Va := 25Vf := 25Part 1 - Stall Torquei f :=i a :=VfRfVara
Purdue - ECE - 321/595
EE321 Spring 2011 HW7Problem 1Buck Converter OperationConsider a machine with the following parameters:ra := 0.1kv := 0.2The machine is fed using a buck converter with the following parametersvfsw := 2.4vfd := 2.0vdc := 125d := 0.7The machine i
Purdue - ECE - 321/595
EE321 Spring 2012Homework 7Problem 1 Buck converter operationConsider the example on page 56 of the lecture notes. Suppose the dc voltage ischanged to 125 V and the speed to 400 rad/s. Find the average armature current, theaverage switch current, the
Purdue - ECE - 321/595
EE321 HW#8Problem 1ra := 1kv := 0.053Laa := 2 10ia :=Tedeskvvdc := 20vfsw := 1Tedes := 0.1vfd := 0.8fmxdes := 30 103ia = 2Manipulating the expression in the notes we have()fsw r , h :=(vfd + ra ia + kv r) (vdc vfsw ra ia kv r)2 h Laa
Purdue - ECE - 321/595
ECE321/ECE595Homework 8Problem 1 Hysteresis Current ControlConsider a machine with an armature resistance of 1 , a voltage constant of 0.05Vs, and an armature inductance of 2 mH. Suppose it is fed from a dc source of 20 V,using a chopper circuit with
Purdue - ECE - 321/595
ECE321/ECE595 Spring 2012 HW#9Problem 1()()was = 100 cos 4 swbs = 250 sin 4 sias = 10 cos e t +B = 1.2 cos e t +88 4 s70 := 4 10Expanding B we haveB = 1.2 cos e t +AlsoB=F=Fg 0g0B cos( 4 s) + 1.2 sin e t + 8 sin( 4 s)8FinallyF
Purdue - ECE - 321/595
EE321/ECE595 Spring 2012Homework 9Problem 1 Rotating MMFThe winding function of the a- and b-phase stator windings of a machine aregiven by was = 100 cos(4 s ) and wbs = 250 sin(4 s ) . The a-phase current of the machine isgiven by i as = 10 cos( e t
Purdue - ECE - 321/595
EE321 Spring 2012HW#10Problem 1Lasar =r L 022 Ns Nr Pg2PPPcos sm sin sm rm dsm2220Lasar =r L 02 Ns Nr P2g212(0Lasar = 4 r L02g PLasar = 4 r L()1 Ns Nr sin r 2 20 2g P() Ns Nr sin rProblem 2()n as = 200 sin
Purdue - ECE - 321/595
EE321 Spring 2012Homework 10Problem 1 Phase InductanceSuppose the winding function of a-phase of the stator is given bywas =2PN s cos sm P2and the winding function of the b-phase of the rotor is given bywbr =2PN r sin rm P2Express the mut
Purdue - ECE - 321/595
EE321 Spring 2011Homework #11Problem 1Machine Parametersrs := 3 m := 0.173Lss := 10 10N := 3P := 4Load 2 r PTL( r) := 2 200 2.3Sourcevs := 100v := 0vq :=()2 vs cos v()vd := 2 vs sin vOk - lets solve the problem()rs vq r m r Ls
Purdue - ECE - 321/595
EE321 Spring 2012Homework 11Problem 1 Brushless DC Operation from a Voltage SourceA three phase brushless DC machine has the following parameters: rs = 3 , Lss = 10 mH,m = 0.17 Vs, P = 4 . It is operating from an inverter and the control is such that
Purdue - ECE - 321/595
EE321 Spring 2012Homework #12Problem 1500 eXphasor :=5+110( 100j) +Xphasor = 16.641(j1300( 100j)2Xphasor 2 = 23.534)arg Xphasor = 1.802x=23.5cos(100t-1.802)If the cosine term were a sine, I simply would have adjusted the phase to geta
Purdue - ECE - 321/595
EE321 Spring 2012Homework 12Problem 1 Phasor AnalysisConsider the differential equation5x +1 dx1 d2x+= 500 2 cos(100t + 1)10 dt 300 dt 2where all arguments of the cosine term are in radians. Use phasor analysis to find the steady-state solution
Purdue - ECE - 321/595
EE321 Spring 2012Homework #13Problem 1We have:i as = 50 sin( 200 t )i bs = 50 cos( 200 t )Now, we will also have()()was = W cos 2 smwbs = W sin 2 smThus, the stator MMF is()Fs = 50 W sin 200 t 2 smWhereupon the stator MMF is moving at 100
Purdue - ECE - 321/595
EE321 Spring 2012Homework 13Problem 1 Rotating MMFUsing the configuration we studied in class (Figure 5.2-1 in text), the stator currents of a 4 polemachine are given byias = 50 sin(200t )ibs = 50 cos(200t )The speed of the machine is 500 rpm in th
Purdue - ECE - 321/595
EE321 Spring 2012Homework #14Problem 1Machine Parameters33rs := 72.5 103Lls := 1.32 103rr := 41.3 10P := 4Llr := 1.32 10NLrr := Llr + Lms2N := 2Sourcevs :=460e := 2 603Mechanical Load50 746 = 18002 :=32 1800 60 60 50 746 1
Purdue - ECE - 321/595
ECE321/595 Spring 2012Homework 14Problem 1 Steady-State OperationConsider a 2-phase machine with the following parameters: rs = 72.5 m , Lls = L'lr = 1.32 mH,Lm = 20.1 mH, rr' = 41.3 m , and P = 4 . The load torque varies with the speed cubed, and is
Purdue - ECE - 321/595
5.),r20 pts (2 pts each). Short Answera.) Name a physical effect that reduces the accuracy of the co-energy approach toflrnding force and torque.h1$erc\ b) Which machine would you use if you wished to have open-loop position control?c)\o.rS\qp6f'
Purdue - ECE - 321/595
Purdue - ECE - 321/595
Purdue - ECE - 321/595
Rotating MMF in Three-Phase Systemso In this case supposeno,(,*)- L, sin(P,* l2)- L, sin(3 P,* l2)r, (,*)- L, sin(P,* l2-2rc l3)- L, sin(3 P,* l2)n&quot; (,*) - L, sin(P,* l2+2n l3)- L, sin(3 P,* l2)o Question: why \Mould I do this ?60Rotating MMF in
Purdue - ECE - 321/595
Transformation of VoltageEquatronso This yieldsvao, -rriao,o \Mhere(\hqr)r* ,\hn, * p\Tno,:l^h,-^;,olo In expanded form,ir-rri[r*0,^;r+p^;,vl, : rri, - cr^;, + p^;,V0,:TriLr+P0,34Trans formation ofF lux-LinkageEquationsa-DAcsL, lou.r
Purdue - ECE - 321/595
ue_(.Iao'F\cfw_+ a,+ 6,lrVirXSXf= cfw_tfS,\,X=ari I a(t&gt;\t + o 'o,o +,\,.lt^ TX=FxeX. =R,&quot;o\= X&quot; I 5X,(,U elt'r)o Re.\ ( xaire,)Q'e)ut)=A, e(r'l+*')-Keo&quot;\(eI)6.14\tJ-'d+.-C+r?1 G+&lt;/+4tt2 3Ja?\:,43r4!o\.u
Purdue - ECE - 321/595
Machine Variable ModelFlux Linkage Equationso WhereZrr:Lk*L*,Lrr-Lt *L*,r1&quot;ms-ryRmnr - lcfw_;&quot;mr Rmf _ /r/,usrFrR*30Machine Variable ModelTorque EquationLo Lets start with[ o,1fr &quot;r, l:[,],'?][lW. - \1 LT- \.LU&quot;LTlabb=Jr&gt;\
Purdue - ECE - 321/595
Balanced Steady- State Ope rationTFfr&quot;:q :r'sI foo&gt; G*-Snlr-c)-$rre.1[ lG i*lco&gt;(r*or'\ r futlF; srn(rtnb\1 i&quot;$dIco&gt; (e. +(e,=-g\gc=+lt^.r*-o)'F cfw_ *r^)[aFJ/ ,.r. -on)t().1 + erforr /)f.F5713t: = Co&gt;ta.(J.l +Oc /o\\c\Q*c
Purdue - ECE - 321/595
P arametero DC Testldenti fi c ationIV= anIf=:3 (o.l\5P)l* q3 ?3nSL\&quot;r\,\85P arameter-Identificationo Blocked Rotor TestSwg\ fto* 3-?hntrSuf c3Rcclce vHSecJrcQ lteftet&quot;.^clh)q ? en\Szv B .e68 S.G'loc3 it.Losulu.Lh)rB() S'7l^I-D
Purdue - ECE - 302
ECE 302 Probabilis/c Methods in Electrical and Computer Engineering Purdue University School of Electrical and Computer Engineering Spring 2012 Prof. Ilya Pollak Probability and Sta/s/cs Tools to extract paFerns from