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University of Illinois, Urbana Champaign - CHBE - 421
1. See page 309 of text book.2. Steam at 250 psi, 575F flows through a steel pipe (4.3" OD, 2,7" ID) at a rate of 1100lbm/hr.Estimate the value of h on the inside surface.Assume this is a turbulent pipe flow, and a cooling process.hi can be obtained f
University of Illinois, Urbana Champaign - CHBE - 421
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University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 12 SolutionsSec 6.4, No 1: For each of the following pairs of vectors z and w in C2 , compute (i) |z|, (ii)|w|, (iii) z, w , and (iv) w, z :4 + 2i4i(a) z =22+i,w =Solution:|z|2 = z, z = zH z ==4 + 2i4i4 + 2i 4i
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 11 SolutionsSec 6.1, No 1: Find the eigenvalues and the corresponding eigenspaces for each of the followingmatrices:3241(a) A =Solution:32410 = det(A I ) = det= (3 )(1 ) 8= 3 4 + 2 8 = 2 4 5 = ( 5)( + 1) = 5, 1F
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 7 SolutionsSec 5.1, No 1: Find the angle between the vectors v and w in each of the following:(a) v = (2, 1, 3)T , w = (6, 3, 9)TSolution: We use the resultcos =vT w2(6) + 1(3) + 3(9)42===12 + 12 + 32 62 + 32 + 92
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 6 SolutionsSec 4.1, No 5: Determine whether the following are linear transformations from R3 into R2 :(a) L(x) = (x2 , x3 )TSolution:L(x + y) = L(x1 + y1 , x2 + y2 , x3 + y3 )T )= (x2 + y2 , x3 + y3 )T= (x2 , x3 )T + (y
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 5 SolutionsSec 3.4, No 2: In Exercise 2 of Section 3.3, indicate whether the given vectors form a basis ofR3 .Solution: Parts (b), (c), and (d) of that question involved linearly dependent collections ofvectors and hence
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 4 SolutionsSec 3.3, No 2: Determine whether the following vectors are linearly independent in R3 :(a) 101 0 , 1 , 0 011Solution: We need to determine if the problem Ac = 0 has a non-trivial solution, where A isthe
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 2 SolutionsSec 1.4, No 9: Let00A=001000010000100001, A3 = 0000000000001000, A4 = 0000Show that An = O for n 4Solution:00A2 = 0000001000000000000000Since
University of Illinois, Urbana Champaign - MATH - 415
Math 415 Spring 2011 Homework 1 SolutionsSec 1.2, No 7: Give a geometric explanation of why an homogeneous linear system consistingof two equations in three unknowns must have innitely many solutions. What are the possiblenumber of solutions of a nonho
Texas A&M - ISEN - 314
Hypergeomtric Distribution - DDN x n - x p( x ) =x = 0,1, 2, ., min( n, D)NnThe mean and variancenD D N - n nD2=1 - & =NN N N - 1 Probability model for selecting a random sample of n items without replacement from a lot of N items of whic
Texas A&M - ISEN - 314
February 3, 2011Gustavo Espinoza UIN: 518000677Natalia SimanUIN: 919001336ISEN 314Lab 22.1 Discuss the similarities between the Shewhart cycle and DMAIC.Both systems look for ways to improve quality and processes . The Shewhart cycle isknown as th
Texas A&M - ISEN - 314
February 8, 2011Gustavo Espinoza UIN: 518000677Natalia SimanUIN: 919001336ISEN 314Lab 22.3 One of the objectives of the control plan in DMAIC is to hold the gain Whatthat this mean?By "hold the gains" it is meant to make sure that the gains are of
Texas A&M - ISEN - 314
February 10, 2011Gustavo Espinoza UIN: 518000677Natalia SimanUIN: 919001336ISEN 314Lab 3Discuss the seven step method used for problem solving and process improvementThe Seven Step Method is used for improving problem solving and processes. It is d
Texas A&M - ISEN - 314
February 17, 2011Gustavo Espinoza UIN: 518000677Natalia SimanUIN: 919001336ISEN 314Lab 31. What is the advantage of stem-and-leaf plots over frequency histograms?With frequency histograms, the identities of the individual observations are lost in t
Texas A&M - ISEN - 314
ISEN 314Natalia SimanGustavo EspinozaLab Exercise # 11.1 Why is it difficult to define quality?Quality is difficult to define because it is a very subjective term, people have their owndefinition. Also, each person may look for different desirable c
Texas A&M - ISEN - 314
March 2, 2011UIN:518000677Gustavo EspinozaNatalia SimanUIN:919001336ISEN 314Lab 5 HW3.7 Construct a histogram for the data provide, comment on the shape of thehistogram. Does it resemble any of the distributions that we have discussed inthis cha
Texas A&M - ISEN - 314
ISEN 314 Statistical Quality ControlLab Exercise: 1The following table contains observed data for service times at a local hamburger place. Thesetimes include placing an order, paying and then getting a hamburger.0.021.395.023.043.451.850.834.3
Texas A&M - ISEN - 314
February 24, 2011Gustavo Espinoza UIN: 518000677Natalia SimanUIN: 919001336ISEN 314Lab 41. Calculate estimates of the Mean, Variance and Standard deviation of this data by hand. For thevariance, use both (a) the second moment about the mean method
Texas A&M - ISEN - 314
Rodrigo LandivarJonovan RogersLab 5 HWISEN 3143.7 Construct a histogram for the data provided. Does it resemble any of the distributions thatwe have discussed in this chapter?The distribution for this histogram is beta.3.20. Consider the data in Ex
Texas A&M - ISEN - 314
Rodrigo LandivarJonovan RogersISEN 314 HW # 31. What is the advantage of stem-and-leaf plots over frequency histograms?One advantage to the stem-and-leaf plot over the histogram is that the stem-and-leaf plot displaysnot only the frequency for each i
Texas A&M - ISEN - 314
Nominal: Categorical data and numbers that are simply used as identifiers or names represent anominal scale of measurement. Numbers on the back of a baseball jersey and your social securitynumber are examples of nominal data. If I conduct a study and I'
Texas A&M - ISEN - 314
March 9, 2011Gustavo EspinozaNatalia SimanUIN:518000677UIN: 919001336ISEN 314Lab 6 HW2.Let X denote a random variable having a binomial distribution with p=0.4and n=20. Use table 2 of the Appendix to evaluate:a. P(X6)b. P(X12)c. P(X=8)4. A com
Blinn College - ISEN - 314
DescribingProcessQualityBasicDefinitionsSampleAcollectionofmeasurementsselectedfromsomelargersourceorpopulation.ProbabilityDistributionAmathematicalmodelthatrelatesthevalueofthevariablewiththeprobabilityofoccurrenceofthatvalueinthepopulation.Rando
Blinn College - ISEN - 314
Quality Controland Total Quality ManagementINTRODUCTIONSpring Semester.2010Dr Don T. Phillipsdrdon@tamu.edu845-5476Zach 242-DDEFINITIONQuality is conformance to requirementsor specifications (Crosby)Quality is fitness for use (Juran)Quality is
Blinn College - ISEN - 314
Quality Controland Total Quality ManagementINTRODUCTIONFall Semester.2009Dr Don T. Phillipsdrdon@tamu.edu845-5476Zach 242-DDimensions of QualityDefinitions of QualityQuality means fitness for use- Quality of design- Quality of conformance- Qu
Blinn College - ISEN - 314
Homework 5 Solution1.1a) I think that normal distributions are suitable assumption for x and y according to Central LimitTheorem. CLT tells us that when a lot of tiny random effects add together, then result will behave like anormal random variable, r
Blinn College - ISEN - 314
Homework #6 SolutionProblem 1: [12 pts] Use the typing time data you collected during Lab #7.Typist A30.2154.56115.6972.65118.456.47Manuscript#1Manuscript#2Manuscript#3Manuscript#4Manuscript#5Manuscript#6Typist B55.3107.66240.22154.652
Blinn College - ISEN - 314
HW7 - Solution.1 [6 pts].Maximize: Z0 =x1 x2Subject to: n1 + n2 = N . n1 + 2 n22Since ( x1 x2 ) is fixed, an equivalent statement isMinimize : L =2122 12 2 122+=+n1n2n1N n12 2 2dL= 1 + 2 =0dn1n12 n2n1 1=n2 2Allocate N betwee
Blinn College - ISEN - 314
Homework 8 Solution1. [8pts]Given = 1.5 , = 0.001 , n=4,UCL = 0 + Z 2LCL= 0 Z 2= 0 + 3.29= 0 + 1.645 ;n4= 0 3.29= 0 1.645 .n4Type II error isnn) ( Z / 2 )= (3.29 3) (3.29 3).= (0.29) ( 6.29) 0.61409 = ( Z / 2 2. [8 pts]Rule 1: c
Blinn College - ISEN - 314
Solution for HW9For Problem 1-3 which is from lab experiment, please refer to the Excel file for the details.1. Using the first 25 samples as training data and get the following Control Chart:m = 25 , n = 3 , d 2 = 1.693 , d 3 = 0.888 ;X = 1.708 , R =
Blinn College - ISEN - 314
Homework #10 SolutionProblem 1:See the Excel file for the individual X control chart.To estimate the sigma, we use x =MR x, where d2 is for n=2.d21m MRim 1 i=2MRi =| X i X i 1 |MR x =Problem2: See the excel file for the Xbar and R chart for n=
Blinn College - ISEN - 314
Homework 11 Solution1. The total number of beads = 500, and the number of colored beads = 45.Thus, the population fraction of the colored beads isp c = 45 / 500 = 0.09 .Part 1:2.number of colored beads in a sample of 100 beads 13== 0.13 .100100
Blinn College - ISEN - 314
Homework #1 SolutionQuestion 1.Acceptance Sampling: Given a lot of typed papers, select n pages as a sample and checkthe accuracy and cleanness on each page. If there is more than d inaccuracy and smudge,then reject the whole lot of typed papers. Othe
Blinn College - ISEN - 314
INEN314HW2Solution:1. Problem 2-2.2. Problem 2-4.(a) In ranked order, the data are cfw_948, 949, 950, 951, 953, 954, 955, 957, 959. The samplemedian is the also the middle value, x = 953 .1(b) Since the median is the value dividing the ranked sample
Blinn College - ISEN - 314
Solution for HW3:Experiment 1:1a) Without replacement, so X follows Hypergeometric Distribution.P=0.5, n=4, D=10, N=20X= 0,1,2,3,4(# of heads in the sample) D N D x n x P(X = x) =Nn 10 20 10 0 4 0 = 0.0433So P(X = 0) =20 4 10 20
Blinn College - ISEN - 314
Homework 4 SolutionNote: For experiment 1 and 2, I just follow the date I use. For different data, the answer shouldbe different. But for that kind of word question, what we need to learn is how to interpret.Experiment 1.1a).histogram of X252015f
Princeton - BIOLOGY - 101
Capacitpag 11A. ScimoneCAPACITA'Ci occupiamo adesso delle propriet dei condensatori, dispositivi che accumulano la caricaelettrica. I condensatori vengono usati in vari tipi di circuiti.Un condensatore un insieme di due conduttori isolati, di forma
Princeton - BIOLOGY - 101
Prova scritta diFISICA PER SCIENZE BIOLOGICHE MOLECOLARI A e CeFISICA PER SCIENZE ECOLOGICHE E DELLA BIODIVERSITA01.07.2008Esercizio 1 - MeccanicaUn satellite articiale (di massa m = 1200 kg ) ruota intorno ad un pianeta di massa M =7.4 1022 kg su
Princeton - BIOLOGY - 101
Corrente elettrica e circuiti elettriciLa corrente elettricaCome gi detto nell'atomo i protonihanno una carica elettrica di segnopositivo e gli elettroni di segnonegativo. Questi ultimi inoltre nonsfuggono alle loro orbite ellittiche acausa dell'at
Princeton - BIOLOGY - 101
CORRENTE ELETTRICACorso di Fisica per la Facolt di Farmacia, Universit G. DAnnunzio, Cosimo Del Gratta 2007CorsoDAnnunzio,INTRODUZIONE Dopo lo studio dellelettrostatica, nella quale abbiamodescritto distribuzioni e sistemi di cariche elettriche inq
Princeton - BIOLOGY - 101
ESERCIZI DI FISICA GENERALE nr. 27/071. Lo schema di figura rappresenta un circuito elettrico costituito da unR1generatore di differenza di potenziale continua V0 = 10.0 V dotato diuna resistenza interna R1 = 100 ohm (la resistenza interna +schemati
Princeton - BIOLOGY - 101
Physics Bio 178Physics Bio 178CHAPTER 20: Magnetismmachines. The basic design is shown in Fig. 2048. An electric field is appliedperpendicular to a blood vessel and to a magnetic field. Explain how ions are caused tomove. Do positive and negative ion
Princeton - BIOLOGY - 101
GLI STRUMENTI PER LA MISURA DI ALCUNEGRANDEZZE ELETTRICHEVOLTMETROE un dispositivo con due morsetti (bipolo) che misura la differenza dipotenziale tra i suoi due morsetti.+Caratteristica principale: non deve disturbare il circuito a cui vienecolleg
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 8http:/session.masteringphysics.com/myct/assignmentPrint?assignmentI.Chapter 26 HomeworkDue: 8:00am on Monday, February 22, 2010Note: To understand how points are awarded, read your instructor's Grading Pol
Princeton - BIOLOGY - 101
HW4Due: 11:59pm on Tuesday, September 8, 2009Note: To understand how points are awarded, read your instructor's Grading Policy .[ Return to Standard Assignment View]The hints for "What About Finite Sheets?" are very useful.Please take time to explore
Princeton - BIOLOGY - 101
HW9Due: 11:59pm on Tuesday, September 22, 2009Note: To understand how points are awarded, read your instructor's Grading Policy .[ Return to Standard Assignment View]Moving a ChargePart AA point charge with chargemoves from the point ( 0.165= 3.40
Princeton - BIOLOGY - 101
Manage this Assignment: Print Version with AnswersAssignment 4Due: 12:00pm on Tuesday, April 28, 2009Note: To understand how points are awarded, read your instructor's Grading Policy.Placing Charges Conceptual QuestionDescription: Simple conceptual q
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print Viewhttp:/session.masteringphysics.com/myct/assignmentPrintView?assignme.Homework 1Due: 11:59pm on Sunday, February 13, 2011Note: You will receive no credit for late submissions. To learn more, read your instructor's
Princeton - BIOLOGY - 101
Manage this Assignment: Print Version with Answers 6Assignment 4 (19)Due: 11:00pm on Wednesday, February 24, 2010Note: To understand how points are awarded, read your instructor's Grading Policy.Problem 19.3Description: (a) How much negative electric
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print ViewStudent Viewhttp:/session.masteringphysics.com/myct/assignmentPrintView.Summary ViewDiagnostics ViewPrint View with AnswersSettings per StudentH1 Coulomb's Law (21.1 - 21.3)Due: 11:59pm on Monday, September 1
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 2http:/session.masteringphysics.com/myct/assignmentPrint?assignmentI.Chapter 25 HomeworkDue: 8:00am on Wednesday, February 10, 2010Note: To understand how points are awarded, read your instructor's Grading
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 6http:/session.masteringphysics.com/myct/assignmentPrint?assignmentI.Chapter 27 HomeworkDue: 8:00am on Monday, March 1, 2010Note: To understand how points are awarded, read your instructor's Grading Policy.
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 6http:/session.masteringphysics.com/myct/assignmentPrint?assignmentI.Chapter 29 HomeworkDue: 8:00am on Thursday, March 11, 2010Note: To understand how points are awarded, read your instructor's Grading Poli
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 5http:/session.masteringphysics.com/myct/assignmentPrint?assignmentI.Chapter 28 HomeworkDue: 8:00am on Wednesday, March 3, 2010Note: To understand how points are awarded, read your instructor's Grading Poli
Princeton - BIOLOGY - 101
Chapter 27 Solutions PSS 27.2 The Electric Field of a Continuous Distribution of ChargeDescription: Knight Problem-Solving Strategy 27.2 The Electric Field of a Continuous Distribution ofCharge is illustrated. (vector applet)Learning Goal: To
Princeton - BIOLOGY - 101
HW11Due: 11:59pm on Monday, September 28, 2009Note: To understand how points are awarded, read your instructor's Grading Policy .[ Return to Standard Assignment View]In Parts A-F of "Electric Force and Potential: Spherical Symmetry",the point charge
Princeton - BIOLOGY - 101
MasteringPhysics: Assignment Print View1 of 7http:/session.masteringphysics.com/myct/assignmentPrint?assignmentID=.Chapter 30 HomeworkDue: 8:00am on Tuesday, March 23, 2010Note: To understand how points are awarded, read your instructor's Grading Pol
Princeton - BIOLOGY - 101
asteringPhysics: Assignment Print Viewhttp:/session.masteringphysics.com/myct/assignmentPrintView?assignme.Homework 5Due: 11:59pm on Sunday, April 10, 2011Note: You will receive no credit for late submissions. To learn more, read your instructor's Gra
Princeton - BIOLOGY - 101
Princeton - BIOLOGY - 101
Assignment 11: EMF and PowerDue: 8:00am on Wednesday, February 15, 2012Note: To understand how points are awarded, read your instructor's Grading Policy.Power in Resistive Electric CircuitsLearning Goal: To understand how to compute power dissipation