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HW_solu_09-01-04 UIllinois TAM 211
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  • Title: HW_solu_09-01-04
  • Type: Solutions
  • School: UIllinois
  • Course: TAM 211
  • Term: Fall

Coursehero >> Illinois >> UIllinois >> TAM 211
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HW_solu_09-03-04
Path: UIllinois >> TAM >> 211 Fall, 2005

Description: ...
HW_solu_09-08-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_09-10-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_09-13-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210 / 211, Fall, 2004 Homework solutions for 09/13 3.77 Given: Find: Truss members carrying the indicated forces Resultant of the four forces at P y z x Solution: v v Fr = Fr = 500lb - ^ + 800lb cos 45^ - sin 45^ + 100lb cos 30^ + sin 30^ + 12...
HW_solu_09-15-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210 / 211, Fall, 2004 Homework solutions for 09/15 3.88 Given: Find: The applied forces & couples at the positions shown Force and couple resultant of the four forces at O v Solution: Fr = v v v v v v v v F = 700lb(r r ) + 120lb(r r ) + 100lb(...
HW_solu_09-17-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210 / 211, Fall, 2004 Homework solutions for 09/17 3.120 Given: Find: The applied forces at the positions shown A single force resultant, if possible; if not, the force and couple resultant of the four forces at O P R T Solution: First, let\'s fi...
HW_solu_09-20-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210 / 211, Fall, 2004 Homework solutions for 09/20 3.143 Given: The distributed load shown. Required: Find the equipollent force/couple system at the wall. Solution: By inspection, we can easily see that the area under the curve is zero, so the ...
HW_solu_09-22-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210 / 211, Fall, 2004 Homework solutions for 09/22 Draw free body diagrams for objects requested in 4.1, 4.2, 4.4, 4.6, 4.10 4.1 Draw the free body diagram for the bar shown. 4.2 Draw a free body diagram of the crowbar (considering the nail is ...
HW_solu_09-24-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_09-27-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_09-29-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_10-01-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-06-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-08-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-11-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-13-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-15-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-18-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_10-20-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_10-22-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-25-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_10-27-04
Path: UIllinois >> TAM >> 211 Fall, 2005
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HW_solu_10-29-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_11-01-04
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_ch8.21.2249.50.53.54
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_ch8.94.97.98
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
HW_solu_ch8.104-107
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
sample1
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210/211 BL1 Sample Exam1 To receive all credit, show all your work Name: Section: v v v ^ 1. For the three vectors A = 3^ + 4^ , B = ^ + ^ + k , and C = 5k find each of the following: i j i j ^ v v a. A + B v v b. A - B v v c. A B v v d. A ...
sample1_soln_p1
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210/211 BL1 Sample Exam1 Name: Section: v v v ^ 1. For the three vectors A = 3^ + 4^ , B = ^ + ^ + k , and C = 5k find each of the following: i j i j ^ v v a. A + B v v A + B = (3 + 1)^ + ( 4 + 1)^ + k = 4^ + 5^ + k i j ^ i j ^ v v b. A - B v v...
sample1_soln_p2
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210/211 BL1 Sample Exam1 Name: Section: 3. If the weight of the box is known to be W (and the rings are massless), what is the tension in the rope which goes from B to D? (I am taking x positive to the right and y positive up.) FBD of the box: ...
sample_final_210_with_solns
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
sampleEXAM2
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 211/210 BL1 Fall, 2004 Practice Exam 2 To receive full credit you must show all your work 1. Name: Section: What is single force resultant to the distributed force system? Assume d and q0 are known. (25 points) x=0 x=d x = 5d F = q0 x2 TAM 21...
sampleEXAM2_solns
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 211/210 BL1 Fall, 2004 Practice Exam 2 To receive full credit you must show all your work 1. Name: Section: What is single force resultant to the distributed force system? Assume d and q0 are known. (25 points) x=0 x=d y x x = 5d F = q0 x2 Fi...
sampleEXAM3.tam211.HILL
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210/211 BL1, Fall 2004 Sample Exam 3 You must show all your work to receive full credit Name: Section: 1. Find the forces in members BC and EF of the truss. Indicate whether each is in tension or compression. TAM 210/211 BL1, Fall 2004 Sample ...
sampleEXAM3_solns
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: TAM 210/211 BL1, Fall 2004 Sample Exam 3 You must show all your work to receive full credit 1. First, use eq conditions for the object as a whole: Fx = 0 C x = 0 ; Fy = 0 D y + C y = Q Cy y Dy Q Cx M D = 0 2 Li (- Qj) + (3Li + Lj) C y = 0 ...
sampleEXAM4_solns.TAM211
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
09_20_2004_handout_resultants
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: Handout for TAM 210/211 BL1 posted 19 September, 2004 Things to keep in mind for finding special equipollent systems and resultants for a system of forces and couples I. Finding the \"force couple resultant\" (at point P) of a system of forces and coup...
09_24_2004_eq_probls_single_obj
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: General equilibrium problems single \"object\" A Draw a GOOD free body diagram 1. Make a clear distinction of the \"body\" (system) Separate it from other parts, including the ground 2. Sketch a contour of your \"free body\" 3. Identify all external force...
distributed loads handout
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: Distributed forces (review) For distributed forces along distributed force intensity\" v j = force / length dF(x ) dx = f (x )^ Resultants at ...
equipollent help sheet
Path: UIllinois >> TAM >> 211 Fall, 2005
Description: ...
hw 1
Path: Kansas State >> EECE >> 519 Spring, 2008
Description: EECE 519 Homework 1 (Due Thursday, January 24) 1. When a car has a dead battery, it can be started by connecting the battery from another car across its terminals as shown in the Figure below. If the current I = -50A, which car has the dead battery? ...
PotentialExamQuestions2008
Path: Kansas State >> LAR >> 322 Spring, 2008
Description: LAR 322 Potential Exam Questions: Exam 1 (the exam will include 9 of these questions and you will select 4 to answer as short [half-page] essay responses; bring only a pen/pencil to the exam) 1. Of what value is landscape ecology to our ability to pr...
LAR-322_Sprawl-Notes
Path: Kansas State >> LAR >> 322 Spring, 2008
Description: Sprawl Notes LAR 322: Environmental Issues Subdivide and Conquer\" video: To some people the most desirable and practical future seems to involve spreading out the human popu...
Additional%20Problems%20Exam%201
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
hw 2
Path: Kansas State >> EECE >> 519 Spring, 2008
Description: EECE 519 Homework 2 (Due Thursday, January 31) 1. Find the current I1 in the circuit. 5A R1 I1 + Vs - -+ 2A 4A 3A I1 = -2A 2. In the circuit shown below V = 8V1 and the power supplied by V is 8mW. Find V1 , V, and R. 2k V 4k + V - 1 R 8k V1 = V...
hw 3
Path: Kansas State >> EECE >> 519 Spring, 2008
Description: EECE 519 Homework 3 (Due Thursday, February 7) 1. Find the power delivered by the 14V source. 7 + 14V - 4 6 5 2 3 1 2 + 1 = 3, 3|3 = 1.5, 4 + 1.5 + 5 = 10.5, 10.5|6 = 3.818, 14V Req = 3.818+7 = 10.818, I = 10.818 = 1.29A, P = (14V )(1.29A) = 18.0...
hw_4s08
Path: Kansas State >> EECE >> 519 Spring, 2008
Description: EECE 519 Homework #4 (Due Thursday, February 28) 1. Find the equivalent capacitance. 50F 60F 70F 20F 120F 2. Express the following voltages in polar form. (a) v1 (t) = -10 cos(t + 50o ) (b) v2 (t) = 12 sin(t - 10o ) 3. The voltage across a 100F cap...
5
Path: Kansas State >> ME >> 534 Spring, 2008
Description: ...
6
Path: Kansas State >> ME >> 534 Spring, 2008
Description: ...
7
Path: Kansas State >> ME >> 534 Spring, 2008
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HW3
Path: Kansas State >> ME >> 533 Spring, 2008
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HW Solutions 1
Path: Kansas State >> ME >> 533 Spring, 2008
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HW Solutions 2
Path: Kansas State >> ME >> 533 Spring, 2008
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Additional HW Problems Exam 2
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
HW Solutions 4
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
HW Solutions 5
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
HW Solutions 6
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Exam 2
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Quiz 1
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Quiz 2
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Quiz 3
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Quiz 4
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Statics Prerequisite Quiz Solution
Path: Kansas State >> ME >> 533 Spring, 2008
Description: ...
Test1
Path: Kansas State >> ME >> 533 Spring, 2008
Description: Sour-r}ov Problem I (35 points). The rigid bar AD is supported two steelwires of l/16-inch by (E psi) anda pin at A. diameter : 29 x 106 Knowing that the wires were initially taut, determine: a) the additionaltensionin eachwire when a 220-lbloadP is ...
hw1soln_s08
Path: Kansas State >> ME >> 533 Spring, 2008
Description: EECE 519 Homework 1 (Due Thursday, January 24) 1. When a car has a dead battery, it can be started by connecting the battery from another car across its terminals as shown in the Figure below. If the current I = -50A, which car has the dead battery? ...
hw2soln_s08
Path: Kansas State >> ME >> 533 Spring, 2008
Description: EECE 519 Homework 2 (Due Thursday, January 31) 1. Find the current I1 in the circuit. 5A R1 I1 + Vs - -+ 2A 4A 3A I1 = -2A 2. In the circuit shown below V = 8V1 and the power supplied by V is 8mW. Find V1 , V, and R. 2k V 4k + V - 1 R 8k V1 = V...
hw3_s08_soln
Path: Kansas State >> ME >> 533 Spring, 2008
Description: EECE 519 Homework 3 (Due Thursday, February 7) 1. Find the power delivered by the 14V source. 7 + 14V - 4 6 5 2 3 1 2 + 1 = 3, 3|3 = 1.5, 4 + 1.5 + 5 = 10.5, 10.5|6 = 3.818, 14V Req = 3.818+7 = 10.818, I = 10.818 = 1.29A, P = (14V )(1.29A) = 18.0...
hw5_f08_soln
Path: Kansas State >> ME >> 533 Spring, 2008
Description: EECE 519 Homework 5 (Due Thursday, March 6) 1. Using mesh current analysis, determine the currents I1 and I2 . 100 + 15 0o V - I1 j750 -j 2000 I2 3 75 Mesh 1: 15 0o - 100I1 - (-j666.7)(I1 - I2 ) = 0 Mesh 2: -(-j666.7)(I2 - I1 ) - j750I2 - 75I2 = 0 ...
hw_4s08_soln
Path: Kansas State >> ME >> 533 Spring, 2008
Description: EECE 519 Homework #4 (Due Thursday, February 28) 1. Find the equivalent capacitance. 50F 60F 70F 20F 120F 50F and 70F in parallel = 50+70 = 120F , 60F and 120F in series = (60)(120) = 40F 60+120 40F and 20F in series = 40+20 = 60F 120(60) 120F and 60...
hw_acpower
Path: Kansas State >> EECE >> 519 Spring, 2008
Description: EECE 519 Homework - AC power 1. A residential electric power monitoring system rated for 120 V (rms), 60 Hz source registers power consumption of 1.2 kW, with a power factor of 0.8 lagging. Find (a) The rms current (b) The phase angle (c) The system...

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