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What Reconstruction were the goals of Reconstruction? Rebuild the south Prevent the return of the Confederate leaders Heal the wounds of the nation Deal with the aftermath of slavery This will be the most difficult 4 million blacks were freed in 1865 But how will they be treated in society? What were the goals of the opponents of Reconstruction especially the KKK? Destroy the Republican Party in the South Intimidate voters so they won't vote Keep blacks in their place Destroy schools Murder blacks who were too "uppity" "Protect" white values and culture against "Africanization" Lincoln's goals for Reconstruction versus the goals of the Radical Republicans Lincoln Issues "Proclamation of Reconstruction" in 1863 Abolition of slavery; pardon for whites Re-admittance Union to when 10% of white males vowed loyalty to USA Freedom for slaves; but no deeper chances in condition Meant they would be free, but little change Goal: End war and bring South back Lincoln is a moderate when it comes to freedom of slaves
Radical Republicans Lincoln is a Republican, but moderate Radical Republicans want deeper changes Let freed slaves vote Give them land on which to farm Don't trust Southerners or Lincoln's "Oath of Allegiance" Plan The Black Codes what were they and when/how were they enforced? Laws against voting, participation on juries, and interracial marriage. Harsh penalties for black vagrancy and double-standard punishment for crimes. Prevented from being implemented by presence of Union army Role of the U.S. Military in the South. Role of Freedman's Bureau.

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Arkansas - HIST - 2013

The Farmer's Revolt & the Populists I. Paper money vs Hard currency A. After Civil War US Government reduces printing of paper money 1. Lessen inflation B. Farmers like paper money because there is more of it in circulation 1. Makes paying off debt e

Arkansas - GEOL - 1113

Introduction to Geology February 11, 2008 PICK UP ELVIS PACK I. Cant see clearly through quartz crystal. II. For Wednesday: Extrusion Lava l l Intrusion Magma February 13, 2008 I. Igneous Processes a. Extrusion- lava b. Intrusion- magma II. Volcano

Arkansas - PSYC - 2003

Major Concept Sheet Exam 4 Note: for all of the topics/concepts you should know the definition and be able to apply them conceptually (hint: if you can apply them conceptually, then you know the definition) Chapter 12: Personality: Personality o Dist

Arkansas - PSYC - 2003

Major Concepts Sheet Test 1: Ch. 1 4 Chapter 1 How psychology started o What disciplines did it come from o Who are those responsible Early schools of thought (what they thought the disciple should be about and anyone mentioned in class associated w

Arkansas - PSYC - 2003

Major Concepts Sheet Exam 2 Chapters 6 & 7 + Lectures Note: for all of the topics/concepts you should know the definition and be able to apply them conceptually (hint: if you can apply them conceptually, then you know the definition) Learning: Classi

Arkansas - MATH - 2223

*REMINDER: Test on the 19th! 8.2: Measures of Central Tendency:Math Structures II February 07, 20081. MEAN: (arithmetic mean, "average") Most Commonly seen as the letter "x" with a horizontal line on top of it (opposite of being underlined) = (x(

Arkansas - HIST - 2013

U.S. History 1877-Present: Test I Study GuideReconstruction What were the goals of Reconstruction? What were the goals of the opponents of Reconstruction-especially the KKK? Lincoln's goals for Reconstruction versus the goals of the Radical Republic

Arkansas - PSYC - 2003

The 109 Typical Job Interview QuestionsThese 109 questions include both traditional and behavioral interview questions. For more information about types of interview questions, go to our Interviewing Resources section of Quintessential Careers. 1. H

Kansas State University - ECON - 102

1.For society, a good is not scarce if a. at least one individual in society can obtain all he or she wants of the good. b. firms are producing at full capacity. c. all members of society can have all they want of it. d. those who have enough incom

Kansas State University - FSHS - 110

1. _ is (are)being studied as a possible alternative to hormone replacement therapy for controlling hot flashes. 1. 2. 3. 4. 5. A. St. John's Wart B. Progesterone C. Estrogen D. Steroids E. SSRIsPoint Value: 2 2. What is the condition that results

Kansas State University - FSHS - 110

1. All of the following are aspects of family or marital life after children have departed, EXCEPT: 1. 2. 3. 4. 5. A. Adults have more time for their spousal roles B. Marital satisfaction may increase. C. The role and responsibilities associated with

Kansas State University - FSHS - 110

Quiz 4 Page 1 Point Value: 2 1. A child's understanding of the nature of objects, their properties and how they work is called the _. 1. A. object concept 2. B. object permanence 3. C. objectification 4. D. objective schemata 5. E. object relations P

Kansas State University - FSHS - 110

1. According to your text, some researchers suspect that _ among infants might be a good predictor of later intelligence test scores. 1. A. expressive and receptive discrepancies 2. B. rates of habituation 3. C. levels of accommodation 4. D. referent

Kansas State University - FSHS - 110

Quiz 6 Page 1 Point Value: 2 1. According to your text, which statement about adopted children is true? 1. A. Adopted children have fewer adjustment problems once they are old enough to understand that their adoption means that they were "chosen." 2.

Kansas State University - FSHS - 110

1. According to Case's neo-Piagetian explanation of children's cognitive development, the key limitation in the cognitive ability of a younger child, compared to an older child, is the younger child's _. 1. A. less operationally efficient short-term

Kansas State University - FSHS - 110

1.Beginning in the 1990s, which group experienced the most rapid growth in single motherhood?1. A. white teenagers 2. B. women over the age of 30 3. C. women over the age of 40 4. D. middle class professional women 5. E. African American teenager

Kansas State University - FSHS - 110

1. Logic and planning are abilities affected in middle childhood by further maturation of the _. 1. 2. 3. 4. 5. A. hippocampus B. cerebral cortex C. synapse D. myelin sheath E. brain stemPoint Value: 2 2. Which of the following is the best example

Kansas State University - FSHS - 110

1. According to Piaget's ideas about children's moral development, a child who insists that the rules of a game cannot be changed because they come from authorities such as parents or religious figures is demonstrating moral development at the _ stag

Kansas State University - FSHS - 110

1. With regard to homosexuality and adolescents, which of the following is FALSE? A. Homosexual youth are more likely to tell their peers than their parents of their homosexuality. B. Homosexual teens are often verbally attacked or ridiculed. C. Homo

Kansas State University - FSHS - 110

1. In the United States, earlier initiation to adolescent sexual activity is associated with _. A. involvement in school activities B. school-based sexuality education programs C. plans for college or education beyond high school D. earlier dating PA

RIT - PSYCH - 0514-210

The Language of Chemistry CHEMICAL ELEMENTS pure substances that cannot be decomposed by ordinary means to other substances.1AluminumSodium 2006 Brooks/Cole - ThomsonBromineThe Periodic Table2Dmitri Mendeleev (1834 - 1907) 2006 Brook

Whitworth University - TH - 130

1 2 viewpoints 1.1 Joshua - The 'fantastic' viewpoint. epic battles, quick action, etc. 1.1.1 Simple: Obey the Word; Victory is achieved 1.2 Judges - Slow, realistic view. 1.2.1 Obey the Word, there are human flaws, but victory is eventually

UMiami - CIS - 410

Chapter 10:Information Systems ManagementThis presentation has been modified from the original and should be downloaded from the Course Documents area in BlackboardLearning Objectives Understand the relationship of the CIO and CTO to other senio

RIT - ELECTRONIC - 0301-481

Chapter 19, Solution 1. To get z 11 and z 21 , consider the circuit in Fig. (a).1 + I1 V1-4 Io 6 2I2 = 0 + V2-(a)z 11 = V1 = 1 + 6 | (4 + 2) = 4 I1Io =z 21 =1 I , 2 1V2 = 1 I1V2 = 2 I o = I 1To get z 22 and z 12 , consider the c

RIT - ELECTRONIC - 0301-481

Chapter 1, Solution 1 (a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C (b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C (c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C (d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C Chapter 1, Solution 2 (a) (b)

RIT - ELECTRONIC - 0301-481

Chapter 2, Solution 1 v = iR i = v/R = (16/5) mA = 3.2 mAChapter 2, Solution 2 p = v2/R Chapter 2, Solution 3 R = v/i = 120/(2.5x10-3) = 48k ohms Chapter 2, Solution 4 (a) (b) i = 3/100 = 30 mA i = 3/150 = 20 mA R = v2/p = 14400/60 = 240 ohmsCha

RIT - ELECTRONIC - 0301-481

Chapter 3, Solution 1. v18 2 40 v26A10 AAt node 1, 6 = v1/(8) + (v1 - v2)/4 At node 2, v1 - v2/4 = v2/2 + 10 Solving (1) and (2), v1 = 9.143V, v2 = -10.286 V2 v1 (9.143)2 P8 = = = 10.45 W 8 848 = 3v1 - 2v2(1)40 = v1 - 3v2(2)P4 =

RIT - ELECTRONIC - 0301-481

Chapter 4, Solution 1. 1 i 5 io1V+ -838 (5 + 3) = 4 , i =1 1 = 1+ 4 5io =1 1 i= = 0.1A 2 10Chapter 4, Solution 2.6 (4 + 2) = 3, i1 = i 2 =1 A 25 4io =1 1 i1 = , v o = 2i o = 0.5V 2 4i1ioi2 1A 8 6 2If is = 1A, then vo

RIT - CIRCUITS - 0301-381

Chapter 5, Solution 1. (a) (b) (c) Rin = 1.5 M Rout = 60 A = 8x104 Therefore AdB = 20 log 8x104 = 98.0 dBChapter 5, Solution 2. v0 = Avd = A(v2 - v1) = 105 (20-10) x 10-6 = 0.1V Chapter 5, Solution 3. v0 = Avd = A(v2 - v1) = 2 x 105 (30 + 20) x 10

RIT - CIRCUITS - 0301-381

Chapter 6, Solution 1.i=Cdv = 5 2e -3t - 6 + e -3 t = 10(1 - 3t)e-3t A dt()p = vi = 10(1-3t)e-3t 2t e-3t = 20t(1 - 3t)e-6t W Chapter 6, Solution 2.1 2 1 Cv1 = (40)(120) 2 2 2 1 2 1 w2 = Cv1 = (40)(80) 2 2 2 w1 = w = w 1 - w 2 = 20(120 2

RIT - CIRCUITS - 0301-381

Chapter 7, Solution 1. Applying KVL to Fig. 7.1. 1 t i dt + Ri = 0 C - Taking the derivative of each term, i di +R =0 C dt di dt or =- i RCIntegrating, i( t ) - t = ln I 0 RCi( t ) = I 0 e - t RC v( t ) = Ri( t ) = RI 0 e - t RC or v(t ) = V0

RIT - CIRCUITS - 0301-381

Chapter 8, Solution 1. (a) At t = 0-, the circuit has reached steady state so that the equivalent circuit is shown in Figure (a).6 VS+ -6 +6+ vL 10 H (b) v -10 F -(a)i(0-) = 12/6 = 2A, v(0-) = 12V At t = 0+, i(0+) = i(0-) = 2A, v(0+) =

RIT - CIRCUITS - 0301-381

Chapter 9, Solution 1. (a) (b) angular frequency frequency f = = 103 rad/s = 159.2 Hz 2(c)periodT =1 = 6.283 ms f(d)Since sin(A) = cos(A 90), vs = 12 sin(103t + 24) = 12 cos(103t + 24 90) vs in cosine form is vs = 12 cos(103t 66) V

RIT - CIRCUITS - 0301-381

Chapter 10, Solution 1.=110 cos( t - 45) 10 - 45 5 sin( t + 30) 5 - 601H 1F jL = j 1 = -j jCThe circuit becomes as shown below.3 Vo j10-45 V+ -2 Io+ -5-60 VApplying nodal analysis, (10 - 45) - Vo (5 - 60) - Vo Vo + = 3 j

RIT - CIRCUITS - 0301-381

Chapter 11, Solution 1.v( t ) = 160 cos(50t ) i( t ) = -20 sin(50t - 30) = 2 cos(50t - 30 + 180 - 90) i( t ) = 20 cos(50t + 60) p( t ) = v( t ) i( t ) = (160)(20) cos(50t ) cos(50t + 60) p( t ) = 1600 [ cos(100 t + 60) + cos(60) ] W p( t ) = 800 +

RIT - CIRCUITS - 0301-381

Chapter 12, Solution 1. (a) If Vab = 400 , then Van = 400 3 - 30 = 231 - 30 VVbn = 231 - 150 V Vcn = 231 - 270 V(b) For the acb sequence, Vab = Van - Vbn = Vp 0 - Vp 120 1 3 Vab = Vp 1 + - j = Vp 3 - 30 2 2 i.e. in the acb sequence, Vab la

RIT - CIRCUITS - 0301-381

Chapter 13, Solution 1.For coil 1, L1 M12 + M13 = 6 4 + 2 = 4 For coil 2, L2 M21 M23 = 8 4 5 = 1 For coil 3, L3 + M31 M32 = 10 + 2 5 = 7 LT = 4 1 + 7 = 10H or LT = L1 + L2 + L3 2M12 2M23 + 2M12 LT = 6 + 8 + 10 = 10HChapter 13, Solution

RIT - CIRCUITS - 0301-381

Chapter 14, Solution 1.Vo R jRC = = Vi R + 1 jC 1 + jRCj 0 , 1 + j 0H () =H () =where 0 =1 RCH = H () = 0 1 + ( 0 ) 2 = H () = - tan -1 2 0 This is a highpass filter. The frequency response is the same as that for P.P.14.1

RIT - CIRCUITS - 0301-381

Chapter 15, Solution 1.e at + e - at 2 1 1 1 s L [ cosh(at ) ] = + = s2 - a2 2s - a s + a (a)cosh(at ) =(b)sinh(at ) =e at - e - at 2 1 1 1 a L [ sinh(at ) ] = - = s2 - a2 2s - a s + a Chapter 15, Solution 2.(a)f ( t ) = cos(t

RIT - CIRCUITS - 0301-381

Chapter 16, Solution 1. Consider the s-domain form of the circuit which is shown below. 1 I(s)1/s+ -1/ssI(s) = 1s 1 1 = 2 = 1 + s + 1 s s + s + 1 (s + 1 2) 2 + ( 3 2) 2i( t ) =2 3 e - t 2 sin 2 t 3 i( t ) = 1.155 e -0.5t sin (0.

RIT - CIRCUITS - 0301-381

Chapter 17, Solution 1. (a) This is periodic with = which leads to T = 2/ = 2.(b) y(t) is not periodic although sin t and 4 cos 2t are independently periodic. (c) Since sin A cos B = 0.5[sin(A + B) + sin(A B)], g(t) = sin 3t cos 4t = 0.5[sin 7t

RIT - CIRCUITS - 0301-381

Chapter 18, Solution 1.f ' ( t ) = ( t + 2) - ( t + 1) - ( t - 1) + ( t - 2) jF() = e j2 - e j - e - j + e - j2 = 2 cos 2 - 2 cos F() = 2[cos 2 - cos ] jChapter 18, Solution 2. t, f (t) = 0,f `(t)1 (t)0 < t <1 otherwisef "(t)01 -(t-1)

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

Cal Poly Pomona - MATH - 115

UCSB - PHYS - 1

1.98: Define S^ AiB^ j^ Ck r S^ ( xi Axy^ j By^ ^ zk ) ( Ai B^ j Cz^ Ck ) If the points satisfy Ax + By + Cz = 0, then r S perpendicular to S . 0 and all points r arePage 1 Of 1

UCSB - PHYS - 1

2.54 cm in . 1 km 10 5 cm 1.61 km 1.1: 1 mi 5280 ft mi 12 in. ft Although rounded to three figures, this conversion is exact because the given conversion from inches to centimeters defines the inch.

UCSB - PHYS - 1

1.2:0.473 L1000 cm3 1L1in 2.54 cm328.9 in 3 .

UCSB - PHYS - 1

1.3: The time required for light to travel any distance in a vacuum is the distance divided by the speed of light; 103 m 3.33 10 6 s 3.33 103 ns. 8 3.00 10 m s

UCSB - PHYS - 1

1.4:g 11.3 cm31 kg 1000 g100 cm 1m31.13 10 4kg . m3

UPenn - STAT - 431

Chapter 1: Overview and Descriptive StatisticsCHAPTER 1Section 1.11. a. b. c. d. Houston Chronicle, Des Moines Register, Chicago Tribune, Washington Post Capital One, Campbell Soup, Merrill Lynch, Pulitzer Bill Jasper, Kay Reinke, Helen Ford, Dav

UCSD - ECON - 111

Econ 111, Winter Quarter 2008 Midterm Answers 1. There were two versions of this question, one asking for the direct channels through which higher interest rates affect aggregate demand and the other asking for the channels through which lower rates

SUNY Buffalo - PHY - 208

1. The time it takes for a soldier in the rear end of the column to switch from the left to the right foot to stride forward is t = 1 min/120 = 1/120 min = 0.50 s. This is also the time for the sound of the music to reach from the musicians (who are

SUNY Buffalo - PHY - 208

1. In air, light travels at roughly c = 3.0 108 m/s. Therefore, for t = 1.0 ns, we have a distance of d = ct = (3.0 108 m / s) (1.0 10-9 s) = 0.30 m.2. (a) From Fig. 33-2 we find the smaller wavelength in question to be about 515 nm, (b) and the