Register now to access 7 million high quality study materials (What's Course Hero?) Course Hero is the premier provider of high quality online educational resources. With millions of study documents, online tutors, digital flashcards and free courseware, Course Hero is helping students learn more efficiently and effectively. Whether you're interested in exploring new subjects or mastering key topics for your next exam, Course Hero has the tools you need to achieve your goals.
2 Pages
history study guide- test 1
Course: HIST 2013, Fall 2007School: Arkansas
Rating:
Word Count: 248
Document Preview
What Reconstruction were the goals of Reconstruction? Rebuild the south Prevent the return of the Confederate leaders Heal the wounds of the nation Deal with the aftermath of slavery This will be the most difficult 4 million blacks were freed in 1865 But how will they be treated in society? What were the goals of the opponents of Reconstruction especially the KKK? Destroy the Republican Party in the South...
Unformatted Document Excerpt
Coursehero >> Arkansas >> Arkansas >> HIST 2013Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
Course Hero has millions of student submitted documents similar to the one
below including study guides, practice problems, reference materials, practice exams, textbook help and tutor support.
What Reconstruction were the goals of Reconstruction? Rebuild the south Prevent the return of the Confederate leaders Heal the wounds of the nation Deal with the aftermath of slavery This will be the most difficult 4 million blacks were freed in 1865 But how will they be treated in society? What were the goals of the opponents of Reconstruction especially the KKK? Destroy the Republican Party in the South Intimidate voters so they won't vote Keep blacks in their place Destroy schools Murder blacks who were too "uppity" "Protect" white values and culture against "Africanization" Lincoln's goals for Reconstruction versus the goals of the Radical Republicans Lincoln Issues "Proclamation of Reconstruction" in 1863 Abolition of slavery; pardon for whites Re-admittance Union to when 10% of white males vowed loyalty to USA Freedom for slaves; but no deeper chances in condition Meant they would be free, but little change Goal: End war and bring South back Lincoln is a moderate when it comes to freedom of slaves
Radical Republicans Lincoln is a Republican, but moderate Radical Republicans want deeper changes Let freed slaves vote Give them land on which to farm Don't trust Southerners or Lincoln's "Oath of Allegiance" Plan The Black Codes what were they and when/how were they enforced? Laws against voting, participation on juries, and interracial marriage. Harsh penalties for black vagrancy and double-standard punishment for crimes. Prevented from being implemented by presence of Union army Role of the U.S. Military in the South. Role of Freedman's Bureau.
Find millions of documents on Course Hero - Study Guides, Lecture Notes, Reference Materials, Practice Exams and more.
Course Hero has millions of course specific materials providing students with the best way to expand
their education.
Below is a small sample set of documents:
Below is a small sample set of documents:
Arkansas - HIST - 2013
The Farmer's Revolt & the Populists I. Paper money vs Hard currency A. After Civil War US Government reduces printing of paper money 1. Lessen inflation B. Farmers like paper money because there is more of it in circulation 1. Makes paying off debt e
Arkansas - GEOL - 1113
Introduction to Geology February 11, 2008 PICK UP ELVIS PACK I. Cant see clearly through quartz crystal. II. For Wednesday: Extrusion Lava l l Intrusion Magma February 13, 2008 I. Igneous Processes a. Extrusion- lava b. Intrusion- magma II. Volcano
Arkansas - PSYC - 2003
Major Concept Sheet Exam 4 Note: for all of the topics/concepts you should know the definition and be able to apply them conceptually (hint: if you can apply them conceptually, then you know the definition) Chapter 12: Personality: Personality o Dist
Arkansas - PSYC - 2003
Major Concepts Sheet Test 1: Ch. 1 4 Chapter 1 How psychology started o What disciplines did it come from o Who are those responsible Early schools of thought (what they thought the disciple should be about and anyone mentioned in class associated w
Arkansas - PSYC - 2003
Major Concepts Sheet Exam 2 Chapters 6 & 7 + Lectures Note: for all of the topics/concepts you should know the definition and be able to apply them conceptually (hint: if you can apply them conceptually, then you know the definition) Learning: Classi
Arkansas - MATH - 2223
*REMINDER: Test on the 19th! 8.2: Measures of Central Tendency:Math Structures II February 07, 20081. MEAN: (arithmetic mean, "average") Most Commonly seen as the letter "x" with a horizontal line on top of it (opposite of being underlined) = (x(
Arkansas - HIST - 2013
U.S. History 1877-Present: Test I Study GuideReconstruction What were the goals of Reconstruction? What were the goals of the opponents of Reconstruction-especially the KKK? Lincoln's goals for Reconstruction versus the goals of the Radical Republic
Arkansas - PSYC - 2003
The 109 Typical Job Interview QuestionsThese 109 questions include both traditional and behavioral interview questions. For more information about types of interview questions, go to our Interviewing Resources section of Quintessential Careers. 1. H
Kansas State - ECON - 102
1.For society, a good is not scarce if a. at least one individual in society can obtain all he or she wants of the good. b. firms are producing at full capacity. c. all members of society can have all they want of it. d. those who have enough incom
Kansas State - FSHS - 110
1. _ is (are)being studied as a possible alternative to hormone replacement therapy for controlling hot flashes. 1. 2. 3. 4. 5. A. St. John's Wart B. Progesterone C. Estrogen D. Steroids E. SSRIsPoint Value: 2 2. What is the condition that results
Kansas State - FSHS - 110
1. All of the following are aspects of family or marital life after children have departed, EXCEPT: 1. 2. 3. 4. 5. A. Adults have more time for their spousal roles B. Marital satisfaction may increase. C. The role and responsibilities associated with
Kansas State - FSHS - 110
Quiz 4 Page 1 Point Value: 2 1. A child's understanding of the nature of objects, their properties and how they work is called the _. 1. A. object concept 2. B. object permanence 3. C. objectification 4. D. objective schemata 5. E. object relations P
Kansas State - FSHS - 110
1. According to your text, some researchers suspect that _ among infants might be a good predictor of later intelligence test scores. 1. A. expressive and receptive discrepancies 2. B. rates of habituation 3. C. levels of accommodation 4. D. referent
Kansas State - FSHS - 110
Quiz 6 Page 1 Point Value: 2 1. According to your text, which statement about adopted children is true? 1. A. Adopted children have fewer adjustment problems once they are old enough to understand that their adoption means that they were "chosen." 2.
Kansas State - FSHS - 110
1. According to Case's neo-Piagetian explanation of children's cognitive development, the key limitation in the cognitive ability of a younger child, compared to an older child, is the younger child's _. 1. A. less operationally efficient short-term
Kansas State - FSHS - 110
1.Beginning in the 1990s, which group experienced the most rapid growth in single motherhood?1. A. white teenagers 2. B. women over the age of 30 3. C. women over the age of 40 4. D. middle class professional women 5. E. African American teenager
Kansas State - FSHS - 110
1. Logic and planning are abilities affected in middle childhood by further maturation of the _. 1. 2. 3. 4. 5. A. hippocampus B. cerebral cortex C. synapse D. myelin sheath E. brain stemPoint Value: 2 2. Which of the following is the best example
Kansas State - FSHS - 110
1. According to Piaget's ideas about children's moral development, a child who insists that the rules of a game cannot be changed because they come from authorities such as parents or religious figures is demonstrating moral development at the _ stag
Kansas State - FSHS - 110
1. With regard to homosexuality and adolescents, which of the following is FALSE? A. Homosexual youth are more likely to tell their peers than their parents of their homosexuality. B. Homosexual teens are often verbally attacked or ridiculed. C. Homo
Kansas State - FSHS - 110
1. In the United States, earlier initiation to adolescent sexual activity is associated with _. A. involvement in school activities B. school-based sexuality education programs C. plans for college or education beyond high school D. earlier dating PA
RIT - PSYCH - 0514-210
The Language of Chemistry CHEMICAL ELEMENTS pure substances that cannot be decomposed by ordinary means to other substances.1AluminumSodium 2006 Brooks/Cole - ThomsonBromineThe Periodic Table2Dmitri Mendeleev (1834 - 1907) 2006 Brook
Whitworth - TH - 130
1 2 viewpoints 1.1 Joshua - The 'fantastic' viewpoint. epic battles, quick action, etc. 1.1.1 Simple: Obey the Word; Victory is achieved 1.2 Judges - Slow, realistic view. 1.2.1 Obey the Word, there are human flaws, but victory is eventually
UMiami - CIS - 410
Chapter 10:Information Systems ManagementThis presentation has been modified from the original and should be downloaded from the Course Documents area in BlackboardLearning Objectives Understand the relationship of the CIO and CTO to other senio
RIT - ELECTRONIC - 0301-481
Chapter 19, Solution 1. To get z 11 and z 21 , consider the circuit in Fig. (a).1 + I1 V1-4 Io 6 2I2 = 0 + V2-(a)z 11 = V1 = 1 + 6 | (4 + 2) = 4 I1Io =z 21 =1 I , 2 1V2 = 1 I1V2 = 2 I o = I 1To get z 22 and z 12 , consider the c
RIT - ELECTRONIC - 0301-481
Chapter 1, Solution 1 (a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C (b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C (c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C (d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C Chapter 1, Solution 2 (a) (b)
RIT - ELECTRONIC - 0301-481
Chapter 2, Solution 1 v = iR i = v/R = (16/5) mA = 3.2 mAChapter 2, Solution 2 p = v2/R Chapter 2, Solution 3 R = v/i = 120/(2.5x10-3) = 48k ohms Chapter 2, Solution 4 (a) (b) i = 3/100 = 30 mA i = 3/150 = 20 mA R = v2/p = 14400/60 = 240 ohmsCha
RIT - ELECTRONIC - 0301-481
Chapter 3, Solution 1. v18 2 40 v26A10 AAt node 1, 6 = v1/(8) + (v1 - v2)/4 At node 2, v1 - v2/4 = v2/2 + 10 Solving (1) and (2), v1 = 9.143V, v2 = -10.286 V2 v1 (9.143)2 P8 = = = 10.45 W 8 848 = 3v1 - 2v2(1)40 = v1 - 3v2(2)P4 =
RIT - ELECTRONIC - 0301-481
Chapter 4, Solution 1. 1 i 5 io1V+ -838 (5 + 3) = 4 , i =1 1 = 1+ 4 5io =1 1 i= = 0.1A 2 10Chapter 4, Solution 2.6 (4 + 2) = 3, i1 = i 2 =1 A 25 4io =1 1 i1 = , v o = 2i o = 0.5V 2 4i1ioi2 1A 8 6 2If is = 1A, then vo
RIT - CIRCUITS - 0301-381
Chapter 5, Solution 1. (a) (b) (c) Rin = 1.5 M Rout = 60 A = 8x104 Therefore AdB = 20 log 8x104 = 98.0 dBChapter 5, Solution 2. v0 = Avd = A(v2 - v1) = 105 (20-10) x 10-6 = 0.1V Chapter 5, Solution 3. v0 = Avd = A(v2 - v1) = 2 x 105 (30 + 20) x 10
RIT - CIRCUITS - 0301-381
Chapter 6, Solution 1.i=Cdv = 5 2e -3t - 6 + e -3 t = 10(1 - 3t)e-3t A dt()p = vi = 10(1-3t)e-3t 2t e-3t = 20t(1 - 3t)e-6t W Chapter 6, Solution 2.1 2 1 Cv1 = (40)(120) 2 2 2 1 2 1 w2 = Cv1 = (40)(80) 2 2 2 w1 = w = w 1 - w 2 = 20(120 2
RIT - CIRCUITS - 0301-381
Chapter 7, Solution 1. Applying KVL to Fig. 7.1. 1 t i dt + Ri = 0 C - Taking the derivative of each term, i di +R =0 C dt di dt or =- i RCIntegrating, i( t ) - t = ln I 0 RCi( t ) = I 0 e - t RC v( t ) = Ri( t ) = RI 0 e - t RC or v(t ) = V0
RIT - CIRCUITS - 0301-381
Chapter 8, Solution 1. (a) At t = 0-, the circuit has reached steady state so that the equivalent circuit is shown in Figure (a).6 VS+ -6 +6+ vL 10 H (b) v -10 F -(a)i(0-) = 12/6 = 2A, v(0-) = 12V At t = 0+, i(0+) = i(0-) = 2A, v(0+) =
RIT - CIRCUITS - 0301-381
Chapter 9, Solution 1. (a) (b) angular frequency frequency f = = 103 rad/s = 159.2 Hz 2(c)periodT =1 = 6.283 ms f(d)Since sin(A) = cos(A 90), vs = 12 sin(103t + 24) = 12 cos(103t + 24 90) vs in cosine form is vs = 12 cos(103t 66) V
RIT - CIRCUITS - 0301-381
Chapter 10, Solution 1.=110 cos( t - 45) 10 - 45 5 sin( t + 30) 5 - 601H 1F jL = j 1 = -j jCThe circuit becomes as shown below.3 Vo j10-45 V+ -2 Io+ -5-60 VApplying nodal analysis, (10 - 45) - Vo (5 - 60) - Vo Vo + = 3 j
RIT - CIRCUITS - 0301-381
Chapter 11, Solution 1.v( t ) = 160 cos(50t ) i( t ) = -20 sin(50t - 30) = 2 cos(50t - 30 + 180 - 90) i( t ) = 20 cos(50t + 60) p( t ) = v( t ) i( t ) = (160)(20) cos(50t ) cos(50t + 60) p( t ) = 1600 [ cos(100 t + 60) + cos(60) ] W p( t ) = 800 +
RIT - CIRCUITS - 0301-381
Chapter 12, Solution 1. (a) If Vab = 400 , then Van = 400 3 - 30 = 231 - 30 VVbn = 231 - 150 V Vcn = 231 - 270 V(b) For the acb sequence, Vab = Van - Vbn = Vp 0 - Vp 120 1 3 Vab = Vp 1 + - j = Vp 3 - 30 2 2 i.e. in the acb sequence, Vab la
RIT - CIRCUITS - 0301-381
Chapter 13, Solution 1.For coil 1, L1 M12 + M13 = 6 4 + 2 = 4 For coil 2, L2 M21 M23 = 8 4 5 = 1 For coil 3, L3 + M31 M32 = 10 + 2 5 = 7 LT = 4 1 + 7 = 10H or LT = L1 + L2 + L3 2M12 2M23 + 2M12 LT = 6 + 8 + 10 = 10HChapter 13, Solution
RIT - CIRCUITS - 0301-381
Chapter 14, Solution 1.Vo R jRC = = Vi R + 1 jC 1 + jRCj 0 , 1 + j 0H () =H () =where 0 =1 RCH = H () = 0 1 + ( 0 ) 2 = H () = - tan -1 2 0 This is a highpass filter. The frequency response is the same as that for P.P.14.1
RIT - CIRCUITS - 0301-381
Chapter 15, Solution 1.e at + e - at 2 1 1 1 s L [ cosh(at ) ] = + = s2 - a2 2s - a s + a (a)cosh(at ) =(b)sinh(at ) =e at - e - at 2 1 1 1 a L [ sinh(at ) ] = - = s2 - a2 2s - a s + a Chapter 15, Solution 2.(a)f ( t ) = cos(t
RIT - CIRCUITS - 0301-381
Chapter 16, Solution 1. Consider the s-domain form of the circuit which is shown below. 1 I(s)1/s+ -1/ssI(s) = 1s 1 1 = 2 = 1 + s + 1 s s + s + 1 (s + 1 2) 2 + ( 3 2) 2i( t ) =2 3 e - t 2 sin 2 t 3 i( t ) = 1.155 e -0.5t sin (0.
RIT - CIRCUITS - 0301-381
Chapter 17, Solution 1. (a) This is periodic with = which leads to T = 2/ = 2.(b) y(t) is not periodic although sin t and 4 cos 2t are independently periodic. (c) Since sin A cos B = 0.5[sin(A + B) + sin(A B)], g(t) = sin 3t cos 4t = 0.5[sin 7t
RIT - CIRCUITS - 0301-381
Chapter 18, Solution 1.f ' ( t ) = ( t + 2) - ( t + 1) - ( t - 1) + ( t - 2) jF() = e j2 - e j - e - j + e - j2 = 2 cos 2 - 2 cos F() = 2[cos 2 - cos ] jChapter 18, Solution 2. t, f (t) = 0,f `(t)1 (t)0 < t <1 otherwisef "(t)01 -(t-1)
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
INSTRUCTOR'S MANUAL To Accompany ENGINEERING MECHANICS - DYNAMICS Volume 2 Fifth Edition, 2002 J. L. Meriam and L. G. Kraige Copyright 2002 by John Wiley & Sons, Inc.USE OF THE INSTRUCTOR'S MANUAL The problem solution portion of this manual has be
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
Cal Poly Pomona - MATH - 115
UCSB - PHYS - 1
1.98: Define S^ AiB^ j^ Ck r S^ ( xi Axy^ j By^ ^ zk ) ( Ai B^ j Cz^ Ck ) If the points satisfy Ax + By + Cz = 0, then r S perpendicular to S . 0 and all points r arePage 1 Of 1
UCSB - PHYS - 1
2.54 cm in . 1 km 10 5 cm 1.61 km 1.1: 1 mi 5280 ft mi 12 in. ft Although rounded to three figures, this conversion is exact because the given conversion from inches to centimeters defines the inch.