28 Pages

# Chapter 12 Test Questions and Answers

Course Number: MAT540 MAT540, Spring 2012

College/University: Strayer

Word Count: 5381

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Introduction to Management Science, 10e (Taylor) Chapter 12 Decision Analysis 1) A state of nature is an actual event that may occur in the future. Answer: TRUE Diff: 1 Page Ref: 527 Main Heading: Components of Decision Making Key words: state of nature 2) A payoff table is a means of organizing a decision situation, including the payoffs from different decisions given the various states of nature. Answer: TRUE...

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Strayer - MAT540 - MAT540
Introduction to Management Science, 10e (Taylor)Chapter 14 Simulation1) In computer mathematical simulation, a system is replicated with a mathematical model that isanalyzed with the computer.Answer: TRUEDiff: 1Page Ref: 628Main Heading: The Monte
Strayer - MAT540 - MAT540
Introduction to Management Science, 10e (Taylor)Chapter 15 Forecasting1) A trend is a gradual, long-term, up or down movement of demand.Answer: TRUEDiff: 1Page Ref: 682Main Heading: Forecasting ComponentsKey words: trend, forecasting components2)
Berkeley - STAT 134 - 134
Chemistry 3ASuggested Problems #1A few notes about the suggested problems. For those from theexambook, you will find the notation X(Y). X refers to the pagenumber at the bottom MIDDLE of the page. The Y refers to theproblem on that page. If there is
Berkeley - STAT 134 - 134
Suggested Problems #2 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.September 7, 2012From the Chemistry 3 ExambookBond-line structures, Resonance, Frontier MO theory, beginningarrow-pushing
Berkeley - STAT 134 - 134
Suggested Problems #3 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.September 13, 2012From the Chemistry 3 ExambookNomenclature:5(a, b: 1st and 2nd ones), 13(c), 42(a: 3rd one; b: 1st one),
Berkeley - STAT 134 - 134
S uggested Problems #4For instructions on how to interpret the numbering system below,see Suggested Problems #1.September 21, 2012From the ExambookConformations and Newman Projections9, 10, 47(a, b: 1st one only), 48, 75(e,f), 90(a: 1st one only), 1
Berkeley - STAT 134 - 134
S uggested Problems #5 for Chemistry 3AFor instructions on how to interpret the numbering system below seeSuggested Problems #1.September 25, 2012From the ExambookCyclohexane conformations and cycloalkane ring nomenclature.5(b: 3rd one), 12, 13(a),
Berkeley - STAT 134 - 134
S uggested Problems #6 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.October 4, 2012From the ExambookBicyclic and polycyclic compounds13(b), 42(a: 2nd one; b: 3rd one), 51, 84(b: 3rd one),
Berkeley - STAT 134 - 134
Suggested Problems #7 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.October 11, 2012From the Chemistry 3 ExambookStereochemistry. Part I17(a:3rd one; b:2nd one), 18, 36(not first a; a,b), 5
Berkeley - STAT 134 - 134
Suggested Problems #8 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.October 18, 2012ExambookStereochemistry. Part IIPlease note that the new instructions for all Predict theProducts proble
Berkeley - STAT 134 - 134
Suggested Problems #9 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.October 26, 2012From the Chemistry 3 ExambookSN2 and some (but not all) SN1 Reactions19(a), 20(a), 21(a), 23, 24, 54(a),
Berkeley - STAT 134 - 134
Suggested Problems #10 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.October 30, 2012From the Chemistry 3 ExambookSN1 and E1 and some more SN2 Reactions19(b), 21(b), 22, 54(d), 60, 96(b), 9
Berkeley - STAT 134 - 134
Suggested Problems #11 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.November 8, 2012From the Chemistry 3 ExambookE2 Reactions19(c), 115(a,b), 119, 144(c: 2nd box), 146(b), 149(a), 176(d),
Berkeley - STAT 134 - 134
Suggested Problems #12 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.November 15, 2012From the Chemistry 3 ExambookReduction of Aldehydes and Ketones and Grignard/alkyl lithiumReagents19(d
Berkeley - STAT 134 - 134
Suggested Problems #13 for Chemistry 3AFor instructions on how to interpret the numbering system below,see Suggested Problems #1.November 20, 2012From the Chemistry 3 ExambookAlkenes Part 1: Nomenclature and hydrogenation.26(a:4th,5th boxes; b), 29(
Berkeley - STAT 134 - 134
Homework 1 ProblemsStatistics 134, Pitman, Fall 20121.1.7 Suppose two dice are rolled. Find the probabilities of the following events.1. the maximum of the two numbers rolled is less than or equal to 2;2. the maximum of the two numbers rolled is less
Berkeley - STAT 134 - 134
Homework 1 Solutions1.1.7Statistics 134, Pitman, Fall 2012a) P (maximum 2) = P (both dice 2) = 4/36 = 1/9b) P (maximum 3) = P (both dice 3) = 9/36 = 1/4c) P (maximum = 3) = P (maximum 3) P (maximum 2) = 5/36d)OutcomeProbability12341/36 3/36 5
Berkeley - STAT 134 - 134
Homework 2 ProblemsStatistics 134, Pitman, Fall 20122.1.2 Suppose that in 4-child families, each child is equally likely to be a boy or a girl,independently of the others. Which would then be more common, 4-child families with2 boys and 2 girls, or 4-
Berkeley - STAT 134 - 134
Homework 2 SolutionsStatistics 134, Pitman, Fall 20122.1.2 P (2 boys and 2 girls) = 4 (1/2)4 = 6/24 = 0.375 &lt; 0.5. So families with dierent2numbers of boys and girls are more likely than those having an equal number of boysand girls, and the relative
Berkeley - STAT 134 - 134
Homework 3 ProblemsStatistics 134, Pitman , Fall 20122.4.4 Repeat the previous problem for the event of getting 30 or more sixes in 100 die rolls,which has probability 0.00068.2.4.6 A box contains 1000 balls, of which 2 are black and the rest are whit
Berkeley - STAT 134 - 134
Homework 3 SolutionsStatistics 134, Pitman , Fall 20122.4.4 Here = 365 0.00068 = 0.2482, anda) 1 e = .219796;b) 1 e e = 0.026150.2.4.6a) The number of black balls seen in a series of 100 draws with replacement hasbinomial (1000, 2/1000) distributio
Berkeley - STAT 134 - 134
Homework 4 Problems3.2.8 Suppose E (X 2 ) = 3,E (Y 2 ) = 4,Statistics 134, Pitman , Fall 2012E (XY ) = 2. Find E [(X + Y )2 ].3.2.14 A building has 10 oors above the basement. If 12 people get into an elevator at thebasement, and each chooses a oor
Berkeley - STAT 134 - 134
Homework 4 SolutionsStatistics 134, Pitman , Fall 20123.2.8 E [(X + Y )2 ] = E (X 2 ) + 2E (XY ) + E (Y 2 ) = 11.3.2.14 We want E (N ), where N is the number of oors at which the elevator makes a stop0to let out one or more of the people. N is a coun
Berkeley - STAT 134 - 134
Homework 5 ProblemsStatistics 134, Pitman , Fall 20123.3.2 Let Y be the number of heads obtained if a fair coin is tossed three times. Find themean and variance of Y 2 .3.3.4 Suppose X1 and X2 are independent. Find a formula for V ar(X1 X2 ) in terms
Berkeley - STAT 134 - 134
Homework 5 SolutionsStatistics 134, Pitman , Fall 20123.3.2 E (Y 2 ) = 3, V ar(Y 2 ) = 15/23.3.4 V ar(X1 X2 ) = E [(X1 X2 )2 ] [E (X1 X2 )]222= E (X1 ) E (X2 ) [E (X1 X2 )]222= (2 + 1 ) (2 + 2 ) (1 2 )2122222= 2 2 + 2 1 + 1 2213.3.6 By s
Berkeley - STAT 134 - 134
Homework 6 ProblemsStatistics 134, Pitman , Fall 20123.4.4 In the game of odd one out three people each toss a fair coin to see if one of theircoins shows a dierent face from the other two.1. After one play, what is the probability of some person bein
Berkeley - STAT 134 - 134
Homework 6 Solutions3.4.4Statistics 134, Pitman , Fall 2012a) The probability of some person being the odd one out is 1 the probability ofhaving the three coins be HHH or TTT. Thus the probability is 1 ( 1 )3 + ( 1 )3 =223.4b) Let the length of
Berkeley - STAT 134 - 134
Homework 7 ProblemsStatistics 134, Pitman , Fall 20124.1.2 Suppose X has density f (x) = c/x4 for x &gt; 1, and f (x) = 0 otherwise, where c is aconstant. Findc;E (X );V ar(X ).4.1.4 Suppose X with values in (0, 1) has density f (x) = cx2 (1 x)2 for 0
Berkeley - STAT 134 - 134
Homework 7 Solutions4.1.2Statistics 134, Pitman , Fall 2012a)1ccdx = 34x3x=1c3and since f (x) is a density function, it must integrate to 1, so c = 3.b)xE (X ) =133dx = 2x42x=1c)E (X 2 ) =x2133dx =x4xThus V ar(X ) = E (
Berkeley - STAT 134 - 134
Homework 8 ProblemsStatistics 134, Pitman , Fall 20124.2.4 Suppose component lifetimes are exponentially distributed with mean 10 hours. Find:1. the probability that a component survives 20 hours;2. the median component lifetime;3. the SD of componen
Berkeley - STAT 134 - 134
Homework 8 SolutionsStatistics 134, Pitman , Fall 20124.2.4 Let W be the lifetime of a component. Then W has exponential distribution withrate = 1/10.a) P (W &gt; 20) = e20 = e2 0.135 .b) The median lifetime m satises1/2 = P (W &gt; m) = em m =(log 2)=
Berkeley - STAT 134 - 134
Homework 9 ProblemsStatistics 134, Pitman , Fall 20124.5.4 Let X be a random variable with c.d.f. F (x). Find the c.d.f. of aX + b rst for a &gt; 0,then for a &lt; 0.4.5.6 Let X be a random variable with c.d.f. F (x) = x3 for 0 x 1. Find:1. P (X 1 );22.
Berkeley - STAT 134 - 134
Homework 9 SolutionsStatistics 134, Pitman , Fall 20124.5.4 If a &gt; 0, thenFaX +b (y ) = P (aX + b y )yb=P Xayb= FXaIf a &lt; 0, thenFaX +b (y ) = P (aX + b y )yb=P Xayb= 1 FXaassuming FX (x) is a continuous function of x.4.5.6a) P (X 1/2)
Berkeley - STAT 134 - 134
Homework 10 ProblemsStatistics 134, Pitman , Fall 20125.2.4 For random variables X and Y with joint density functionf (x, y ) = 6e2x3y(x, y &gt; 0)and f (x, y ) = 0 otherwise, nd:1. P (X x, Y y ); fX (x); fY (y ).2. Are X and Y independent? Give a rea
Berkeley - STAT 134 - 134
Homework 10 Solutions5.2.4Statistics 134, Pitman , Fall 2012a)yx6e2x3y dydxP (X x, Y y ) =00x=0y16e2x ( e3y ) dx30x2e2x dx= (1 e3y )03y= (1 eb))(1 e2x )6e2x3y dy = 2e2xfX (x) =0c)6e2x3y dx = 3e3yfY (y ) =0d) Yes, they are
Berkeley - STAT 134 - 134
Homework 11 ProblemsStatistics 134, Pitman , Fall 20126.1.2 In a particular town 10% of the families have no children, 20% have one child, 40%have two children, 20% have three children, and 10% have four. Let T represent thetotal number of children, a
Berkeley - STAT 134 - 134
Homework 11 SolutionsStatistics 134, Pitman , Fall 20126.1.2 Condition on the value of T :4P (G = g |T = t)P (T = t)P (G = g ) =t=0Now given T = t, G has binomial (t, 1/2) distribution, sot(1/2)t ,gP (G = g |T = t) =g = 0, . . . , t.Conclude:
Berkeley - STAT 134 - 134
Homework 12 ProblemsStatistics 134, Pitman , Fall 20126.4.4 Let (X, Y ) have uniform distribution on the four points (1, 0), (0, 1), (0, 1), (1, 0).Show that X and Y are uncorrelated but not independent.6.4.8 You have N boxes labeled Box1, Box2,. . .
Berkeley - STAT 134 - 134
Intermolecular Forces!Intermolecular forces take place between molecules.!!!!!An understanding of intermolecular forces is crucial !to a chemists ability to successfully carry out reactions !in the organic chemistry laboratory.!!The Forces Betwe
Berkeley - STAT 134 - 134
Terminology of MixingSolution: A homogenous mixture of two or more compounds.Solute: The compound in a solution present in lesser amount.Solvent: The major component of a solution.Miscibility: Two components of a solution are innitely soluble in each
Berkeley - STAT 134 - 134
Melting PointsTypical Phase Changes as a Function of Temperatureat a Constant PressureTemperatureDbp, cpBmp, fpELCGGas(G)LiquidSolidASL(L)(S)Heat AddedBC = melting point(mp)/freezing point(fp): [Psolid = Pliquid]DE = boiling point(b
Berkeley - STAT 134 - 134
Boiling PointsImpurities and Boiling PointsSoluble, Non-Volatile ImpurityPA = vapor pressureof compound A in a solution of A and asoluble impurityPressureRaoults Law:PA = XAPAELiquidSolidPatmDTCGasReduced vaporpressure curvedue to the
Berkeley - STAT 134 - 134
Purifying Solids!!!! Sublimation/Deposition! Chromatography! Recrystallization!Recrystallization!Step 1: Choosing the right equipment!The Glassware! Erlenmeyer ask!Richard Erlenmeyer! Test tube!Constricted opening!Large surface area!Step 1:
Berkeley - STAT 134 - 134
Chromatography!Separation of Different Compounds!!!! Partition! Adsorption!Adsorption Chromatography!Compounds that have Different Interactions with the Mobile Phase!Versus the Stationary Phase can be Separated !ABCABA CC CBBAaddsolventst
Berkeley - STAT 134 - 134
Retention Factor (Rf)!Not a Physical Constant!Rf = !distance to !midpoint!of spot!distance to !solvent front!Rf depends on:!u The stationary phase !u The mobile phase !u The amount of compound!spotted!u The temperature!TLC: Conclusions!Give
Berkeley - STAT 134 - 134
Structure Determination!v NMR Spectroscopy!v Mass Spectrometry!v X-Ray Crystallography!Spectroscopy!Absorption of Electromagnetic Radiation:!Something Changes from a Lower Energy !State to a Higher Energy State!E = h !E: change in energyh : Plan
Berkeley - STAT 134 - 134
Spin-Spin Splitting !(J Coupling)!Coupling of spins provides connectivity information !about neighboring nuclei!1HNMR Spectrum of 1,1,2-trichloroethane!HBPredicted !HAH B!ClHBClClHA!TMS6ppm5ppm4ppm3ppm2ppm1ppm0 ppmObserved! !TMS6p
Berkeley - STAT 134 - 134
Complex Coupling !singlet!doublet!triplet!?!quartet!Successive Application of the N + 1 Rule!HBHAHBClCl ClTMS6ppm5ppm4ppm3ppm1ppm2ppm0 ppmTwo different hydrogen atoms coupling to a third hydrogen atom!HAWhat if:!JAB = 3 Hz!JAC = 8
Indonesia Country AssessmentDavid FetnerAdam WertheimQmarth GhaemiTorrance ShepardsonAlexander LeeINDONESIA2Table of ContentsIntroduction.3Indonesia is an archipelago or a country that is composed of thousands of islands. With approximately 17,00
TYPE: TAKE HOMEBADM 2201 I NTER L FINANCIAL ENVIRN.Fall 2012Quiz # 3NAME QMARTH GHAEMIStudent ID# G39031185Section:13Each question is 5 pointsDUE: DECEMBER 4, 2012Is running a current account deficit bad for US? What does a current account defic
Qmarth GhaemiHow does/can a business balance profits and social responsibility?When a business becomes so consumed in worrying about profit it losses sight of what suroundsthe company. Even when a business is doing well there can be times in which soci
Qmarth GhaemiAssignment 3In Harold Koontzs article, The Management Theory Jungle Revisited, attempts to explain the new findings with the management jungle and how this is effecting everyone. It goeson to describe how the original management theory jun
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Please complete this worksheet for your Paper 2 Peer Review Assignment. You may also makecomments on their paper if youd like, but it is not required.Name of Student doing the Peer Review:Qmarth GhaemiName of Student whose paper is being peer reviewed