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categories1_toby UC Riverside PHYS 291
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  • Title: categories1_toby
  • Type: Notes
  • School: UC Riverside
  • Course: PHYS 291
  • Term: Fall

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as Groups Categories Questions by: John C. Baez, 2004 September 30 Answers by: Toby Bartels1 , 2004 October 7 Here s a little homework just to make sure you understand the concepts of category, functor and natural transformation, as de ned in the handout Some De nitions Everyone Should Know . Recall that a set with an associative binary product and an element serving as the unit for this product is called a monoid: examples include (N, +, 0) and (N, , 1). A monoid where every element has a two-sided inverse is called a group. A category C with only one object (say ) is the same thing as a monoid, since all C has is a set of morphisms f : that can be composed associatively, together with a morphism 1 : serving as the unit for composition. Similarly, a category with only one object and all morphisms invertible is the same as a group! So, among other things, category theory is a massive generalization of group theory. This means that whenever you encounter a de nition in category theory, you should gure out what it amounts to in the case of groups. In what follows, you can either do problems 1 5 or problem 6. I greatly prefer answers in LaTeX. 1. Suppose that G and H are groups, and regard them as one-object categories with all morphisms invertible. Figure out what a functor F : G H amounts to. What are such functors usually called? F consists of a function F : G H, such that F (1G ) = 1H and for any pair of elements f, g of G, F (f g) = F (f )F (g). This is usually called a group homomorphism from G to H. 2. Suppose G and H are groups regarded as categories, and let F, F : G H be a pair of functors. Figure out what a natural transformation : F F amounts to. consists of an element of H, such that for any element f of G, F (f ) = F (f ). 3. Suppose G is a group regarded as a category and let 1G : G G be the identity functor. Figure out what a natural transformation : 1G 1G amounts to. What is the set of all such natural transformations usually called? consists of an element of G, such that for any element f of G, f = f . The set of such is usually called the centre (or center) of G. 4. Let Vect be the category of vector spaces over your favorite eld, where the morphisms are linear transformations. Suppose G is a group as regarded a category. Figure out what a functor F : G Vect amounts to. What is such a functor usually called? F consists of an object F of Vect and a function F : G hom(F, F ), such that F (1G ) = 1F and for any pair of elements f, g of G, F (f g) = F (f )F (g). This is usually called a linear representation of G. 5. Suppose G is a group regarded as a category and let F, F : G Vect be functors. Figure out what a natural transformation : F F amounts to. What is such a natural transformation usually 1I reserve no legal rights whatsoever to any of my creative work; see http://toby.bartels.name/copyright/. called? consists of a linear operator : F F , such that for any element f of G, this diagram commutes: F F (f ) /F F F (f ) /F is usually called an intertwining operator from F to F . 6. Suppose G is a Lie group, regarded as a one-object category where the morphisms form a manifold. Let Aut(G) be the category whose objects are smooth invertible functors F : G G and whose morphisms are smooth invertible natural transformations : F F . The objects of Aut(G) form a Lie group. Any object F in Aut(G) gives a subset [F ] consisting all objects that are isomorphic to it. What do these subsets look like for G = SO(3)? How about for G = SU(2)? First, let me state some facts about automorphisms of Lie groups. To begin with, every element of G de nes an automorphism of G by conjugation. This de nes a group homomorphism G Ob(Aut(G)); let Inn(G) be the image of this homomorphism. Then Inn(G) is normal; let Out(G) be the quotient group. If G is a connected compact real form of a simple Lie group, then Out(G) is isomorphic to the symmetry group of the Dynkin diagram of G. Also, Inn(G) is isomorphic to G/Z, where Z is the centre of G. Now, both SO(3) and SU(2) are connected compact real forms of the Lie group A 1 : The symmetry group of this Dynkin diagram is trivial, so Ob(Aut(G)) = Inn(G) in both cases. Since Z(SO(3)) is trivial, I have Ob(Aut(G)) = Inn(G) SO(3) in both cases. = So, suppose F and F are elements of G, and let be F (F ) 1 . Then F (f ) = F f F 1 F (F ) 1 = F f (F ) 1 = F (F ) 1 F f (F ) 1 = F (f ). Thus, F F in Aut(G). Therefore, there is a unique isomorphism class [F ], which is all of = Ob(Aut(G)) SO(3). =

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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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Path: UC Riverside >> PHYS >> 291 Fall, 2008
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