Transcript 2013-07-01 2184321
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Transcript 2013-07-01 2184321

Course Number: EGR 125, Summer 2013

College/University: Lake County

Word Count: 11378

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eam. The waitress replies I'm sorry [ INDISCERNIBLE ] but we're out of cream, how about with no milk. Anyway. I don't know. >> Moving on. . >> Oh, because it's with nothing. >> Right. >> So it's like the absence of it. >> Yeah. Anyway. Kind of dumb. How can you tell the difference between a chemist and a plumber, ask them to pronounce ununionized. Get, unionized. >> What...

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The eam. waitress replies I'm sorry [ INDISCERNIBLE ] but we're out of cream, how about with no milk. Anyway. I don't know. >> Moving on. . >> Oh, because it's with nothing. >> Right. >> So it's like the absence of it. >> Yeah. Anyway. Kind of dumb. How can you tell the difference between a chemist and a plumber, ask them to pronounce ununionized. Get, unionized. >> What do you get when you cross a joke with a rhetorical question? All right. Anyway. I thought that would be fun to share. Yeah. . >> I have a physics joke. >> You have a physics joke. All right, what is it? I'm waiting. . >> We don't serve faster than light particles here says the bartender. [ INDISCERNIBLE ] >> I don't get it. . >> We don't serve faster than light particles here citizen the bartender. [ INDISCERNIBLE ] walks into the bar. >> Oh, I get a. All right. Get it. It's faster than light. >> It's faster than light. That's what the joke is. >> All right. Well, I thought that would be kind of fun. Tori let me get you, your exam here. Hold on a second. All right. Any questions on the 3.7 and 3.8 stuff before we move on and talk about related [ INDISCERNIBLE ] day. We're going to spend the whole day on one section. It's kind of a big one. It's one of the biggest and useful applications of the derivative that we'll come across today. But at first, anything from the last section? >> Could you do an example [ of INDISCERNIBLE, SPEAKER'S VOLUME TOO LOW ] >> Like a radioactive [ INDISCERNIBLE ] problem? >> Sure. There's one and the homework that I think I assigned. Number nine and number 11 both deal with data. Why don't we do number nine, I think. Number nine says [ INDISCERNIBLE ] 137 is 30 years. >> Suppose we have 100-milligram sample to start. All right. Well, right off the bat, whenever, and pretty much all of these problems that you're going to do in 3.28 you're trying to determine what [ INDISCERNIBLE ] what's this thing that we don't know that we want to know. And they're going to give us some initial conditions to figure it out. We have half life, but we don't have what? The decay rate, right? We do know that y of t is equal to y initial e to the kt, for all of our problems we're going to follow that, and that was what we had talked about last class, right, before the exam? It's always y initial e to the kt, where k is your k rate or our growth rate, in this case it's the decay rate, and times is obviously the vary. So we have an y initial, what's our y initial? >> [ INDISCERNIBLE, SPEAKER'S VOLUME TOO LOW ] >> Yes, so we start with 100, right? So we have a function that's not y of t yet because we still don't know what k is. But we are given important information. Half life of [ INDISCERNIBLE ] 37 is 30 years so if we're starting with 100 milligrams, right? What can we plug in then in order to figure out [ INDISCERNIBLE, VOLUME TOO LOW

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