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Rochester - PHY - 113
P114PROBLEM SET 2Spring 2007Homework to be handed in by 1700 hours on Tuesday, 6 February 2007. [1] A uniform line charge extends from x = -2.5cm to x = 2.5 cm and has linear charge density = 4.5 nC/m. a: Find the total charge b: Find the elec
Rochester - PHY - 113
P114PROBLEM SET 3Spring 2007Homework to be handed in by 1800 hours on 13 February 2007. [1] If a conducting sphere is to be charged to a potential of 10,000 V, what is the smallest possible radius of the sphere such that the electric field will
Rochester - PHY - 113
P114PROBLEM SET 6Spring 2007Homework to be handed in by 1700 hours on 6 March 2007. [1] Consider a single turn circular loop of radius 20 cm. a) At what point along the axis is the magnetic field 1% of that at the center? b) Find the current in
Rochester - PHY - 113
P114PROBLEM SET 7Spring 2007Homework to be handed in by 1800 hours on Tuesday 20 March 2007. [1] A 2.0 cm by 1.5 cm rectangular coil has 300 turns and rotates in a magnetic field of 4000 G. a; What is the maximum emf generated when the coil rot
Rochester - PHY - 113
P114PROBLEM SET 8Spring 2007Homework to be handed in by 1700 hours on 27 March 2007. [1] A plane parallel plate capacitor with circular plates of radius 1 meter and separation 1 mm is being charged with a current of 1 amp. (a) Show that the tot
Rochester - PHY - 113
P114PROBLEM SET 9Spring 2007Homework to be handed in by 1700 hours on 3 April 2007. [1] Light of wavelength 550 nm is incident on a long, narrow slit. Find the angle of the first diffraction minimum if the width of the slit is: a) 1mm b) 0.1mm
Rochester - PHY - 113
P114 - Problem Set 10Homework to be handed in by 1700hrs on Tuesday 10 April 2007 . [1] Light conditions on a certain day for a certain film call for an aperture stop of f/8 at 1/250 sec. a; If you wish to take a picture of a humming bird at 1/1000
Rochester - PHY - 113
P114PROBLEM SET 11Spring 2007Homework to be handed in by 1700 hours on 17 April 2007. [1] A penny weighs 2.5 g. Calculate the rest energy for a penny. If you convert this energy completely to electrical energy and sell it at 10 cent/kW-hour, ho
Rochester - PHY - 113
Rochester - PHY - 113
Physics 113, Fall 2005 Homework assignment 6 Due Tuesday, Oct. 25, 2005, 4:00pm Read Giancoli chapters 8 and 9. 1. Giancoli, Chapter 8, problem 14 (page 200). 2. Giancoli Chapter 8, problem 55 (page 203). 3. Giancoli Chapter 8, problem 87 (page 205)
Rochester - PHY - 113
Physics 113, Fall 2005 Homework assignment 9 Due Tuesday, November 22, 2005, 4:00pm Read Giancoli chapters 13 and 14. 1. Giancoli, Chapter 12, problem 48 (page 326). 2. Giancoli, Chapter 12, problem 54 (page 327). 3. Giancoli, Chapter 13, problem 34
Rochester - PHY - 113
Physics 113, Fall 2005 Homework assignment 10 Due Tuesday, Dec.6 2005, 4:00pm Read Giancoli chapters 14, 15 and 16.(Exclude sections 14-7,14-8, and 15-10.) 1. Giancoli, Chapter 14, problem 28 (page 383). 2. Giancoli, Chapter 14, problem 42 (page 383
Rochester - PHY - 113
Rochester - PHY - 113
4-46. (a) See drawing (b) If we select all three blocks as the system, we have F m1 Fx = max: F = (m1 + m2 + m3)a, which gives a = F/(m1 + m2 + m3). x (c) For the three blocks individually, for Fx = max we have F Fnet1 = m1a = m1F/(m1 + m2 + m3); Fne
Rochester - PHY - 113
Rochester - PHY - 113
Solutions to problem set 10 P113 Fall 200612-71. (a) The cylinder will roll about the contact point A.We write = I about the point A: Fa(2R h) + FN1[R2 (R h)2]1/2 Mg[R2 (R h)2]1/2 = IA. When the cylinder does roll over the curb, contact
Rochester - PHY - 113
Rochester - PHY - 113
Solutions to problem set 11 P113 Fall 200613-5413-75. The liquid pressure is produced from the elevation of the bottle: P = gh. (a) (65 mm-Hg)(133 N/m2 mm-Hg) = (1.00 103 kg/m3)(9.80 m/s2)h, which gives h = 0.88 m. (b) (550 mm-H2O)(9.81 N/m2
Rochester - PHY - 113
Phys 113 Problem Set 1 Solutions 1)vc = 90 km h 1000 m 750 km h 1000 m = 25 m s , vt = = 20.83 m s h 3600 s km h 3600 s km xc = vc t = ( 25 m s ) t , xt = x0t + vt t = 100 m + ( 20.83 m s ) txc = ct , ( 25 m s ) t = 100 m + ( 20.83 m s ) t , ( 4.1
Rochester - PHY - 113
Physics 113, Fall 2005 Homework assignment 2 Due Monday, Sept. 19, 2005, 4:00pm Read Giancoli chapter 3. 1. Giancoli, Chapter 2, problem 61. (page 42). Assume the acceleration due to gravity is 9.80m/s2 . 2. Giancoli, Chapter 2, problem 70 (page 42)
Rochester - PHY - 113
Physics 113, Fall 2005 Homework assignment 3 Due Monday Sept. 26, 2005, 4:00pm Read Giancoli chapter 4. 1. Giancoli, Chapter 3, problem 30 (page 71). 2. Giancoli, Chapter 3, problem 45 (page 72). 3. Giancoli, Chapter 3, problem 55 (page 73). 4. Gian
Washington - ACCTG - 225
Washington - ACCTG - 225
To Succeed in Accounting 225 . Come to big classes . prepared Attend all quiz sections . prepared Read the class notes, chapters and do the problems without the solutions Explore the textbook website and do the end-ofchapter quizzes Be an activ
Washington - SCAND - 151
19th-SCAND 151 AND 20 -CENTURY FINNISH LITERATURE AND CULTURE Prof. Andrew Nestingen http:/faculty.washington.edu/akn/scand151.htm Winter 2008thCourse Information5 Credits Room: Sieg 224 T., Th: 1:30-3:20. Office Hours: M. 11 :30-1 :20Instr
Washington - ACCTG - 225
The standard cost card for the production of 1 unit of Zippy at Hanson's Manufacturing is as follows:AStandard Quantity or Hours1.5 lbs. 1.5 hours 1.5 hoursBStandard Price or RateAxBStandard Cost per Unit6.00 18.00 4.50 28.50InputsDirect
Virginia Tech - PHYS - 2306
Physics 2306 Spring 2008 First Exam FORM A1) The pressure fluctuation from ambient pressure due to a sound wave is given by p(x,t) = (2.010-5 N/m2) sin[(5 radians/meter) x + (4000 radians/second) t] Which one of the following statements is true? A.
Virginia Tech - PHYS - 2306
Physics 2306 Spring 2008 Second Exam FORM A1) The electric field lines of two charges, A and B, are shown in the figure. The magnitude of charge A is 12.0 C. What is the charge (in Coulombs) of B? A. -10 B. 10 C. -4.0 D. 4.0 E. -8.0 F. 8.0 G. 20 H.
UIllinois - CEE - 300
BName _FIRST HOUR EXAMINATION - TAM 324/CEE300Friday February 16, 2007 Work all problems in spaces provided One page of hand-written notes permitted.1. (10 points) Nitrogen gas can be used to improve the properties of steel. A sheet of steel
UIllinois - CEE - 300
AName _SECOND HOUR EXAMINATION - TAM 324/CEE300Wednesday March 7, 2007 Work all problems in spaces provided One page of hand-written notes permitted.1. (15 points) Assume a single-crystal BCC material. (a)(5pts) Sketch the BCC crystal unit c
Colorado - CVEN - 3227
8.1 (a) B = stress = y / 0.1; A = strain = x / 10^^Let, E(B A = a) = + a Nos. 1 2 3 4 5 6 ai 9x10-4 20x10-4 28x10-4 41x10-4 52x10-4 63x10-4 213x10-4 bi 10 20 30 40 50 60 210 aibi 9x10-3 40x10-3 84x10-3 164x10-3 260x10-3 378x10-3 935x10-3 ai2 8
Colorado - CVEN - 3227
8.2 (a)(b)Stopping Distance (m) Yi Xi2 Yi2 XiYi Yi'=a+bXi (Yi-Yi')2Vehicle No.Speed (kph) XiTotal:On the basis of calculations in the above table we obtain the respective sample means of X and Y as,X = 679/12 = 56.6 kph,and correspondin
Colorado - CVEN - 3227
8.3 (a)Plot of peak hour traffic vs daily traffic1.61.41.2Peak hour traffic (1000 vehicles)10.80.60.40.20 0 1 2 3 4 5 6 7Daily traffic (1000 vehicles)(b)Let X be the daily traffic volume and Y the peak hour traffic volume, b
Colorado - CVEN - 3227
8.4 (a)(b)Country # Per Capita GNP Per Capita Energy ConsumptionXiYiXi2Yi2XiYiYi'=a+bXi(Yi-Yi')2Total:On the basis of calculations in the above table we obtain the respective sample means of X and Y as,X = 37800/8 = 4725,and c
Colorado - CVEN - 3227
8.5 (a) Let X be the car weight in kips; X ~ N(3.33, 1.04). Hence X - 4.5 - 3.33 ) P(X > 4.5) = P( > 1.04 = P(Z > 1.125) = 1 (1.125) = 1 - 0.8697 0.130(b) Let Y be the gasoline mileage. For linear regression, we assume E(Y | X = x) = + x and s
Colorado - CVEN - 3227
8.6 (a)Let Y be the number of years of experience, and M be the measurement error in inches. We have the following data: i 1 2 3 4 5 yi 3 5 10 20 25 63 mi 1.5 0.8 1 0.8 0.5 4.6 yimi 4.5 4 10 16 12.5 47 yi2 9 25 100 400 625 1159From Eq. 8.4 & 8.3
Colorado - CVEN - 3227
8.9 (a) The formulas to use are=x yi =1 n ini- nx y - nx2xi =12 iand^ = y-xThe various quantities involved are calculated in the following table: n= 3 xi yi xiyi 66.15 168.36 640.56 875.07 xi2 1.1025 3.3489 9.8596 14.311 yi' (yi
Colorado - CVEN - 3227
2.3 (a)(b) Wind directionE190oE2 E3 E1Wind Speed60o 30o 0 (c) 15 35 45A and B are not mutually exclusive A and C are not mutually exclusive
Colorado - CVEN - 3227
2.4 Possible water level Outflow Inflow Outflow + 7' 5' 8' 6' 7' 7' 6' 5' 9' 6' 8' 7' 7' 5' 10' 6' 9' 7' 8'(a) Inflow 6' 6' 6' 7' 7' 7' 8' 8' 8'Hence possible combinations of inflow and outflow are (6',5'), (6',6'), (6',7'), (7',5'), (7',6'), (7
Colorado - CVEN - 3227
2.8 P(E1) = 0.8; P(E2) = 0.7; P(E3) = 0.95 P(E3 E 2 ) = 0.6; assume E2 and E3 are statistically independent of E1 (a) A = (E2 E3) E1 B = ( E 2 E 3 ) E1or E 2 E 3 E1(b) P(B) = P( E1 E 2 E 3 ) = P( E1 ) + P( E 2 E 3 ) P( E1 E 2 E 3 ) = 0.2 + P
Kansas State University - MATH - 240
Ohio State - CHEM - 121
Lecture 2Chapter 2 Atoms, Molecules, and IonsToday's reading: section 1 to section 7The Atomic Structure - the Electron Cloud Model1Properties of Protons, Neutrons and ElectronsParticle Proton Neutron Electron Charge +1 0 -1 Mass (g) 1.6727
Emory - CHEM - 141
SI Questions for Chapter 10 Sections 000 and 004Write the major Lewis structure(s) for the following molecules. Include any formal charges and resonance structures. If resonance is possible, determine the major resonance structure. H2CN2 (2 skeletal
Ohio State - CHEM - 121
Lecture 3 Reading: chapter 2 section 8 and chapter 3 section 1 Homework 2: chapter 2: 18, 20, 24, 38, 42, 44, 46, 48, 50, 52, 54, 56, 60, 62, 64, 66, 68 Due: Thursday, Oct. 4Ionic CompoundsIonic compounds are composed of oppositely charged ions he
Northeastern - CMN - 101
I\iQ\J\_)qs o.)l-"-t(Ja --7-<+g;P6Ec9' J i ; ) ::Dr i + i i * i i l Ef = * i T f : E:HH;:=g!g;F: =EgF rE3 1E ? 1 E!E i: : ; # ; i i rFI ' E=j E i * : E ; ? ! FE i E i ^ z l rErii 3 g 3l, *3 =ifr ; E i
Ohio State - CHEM - 121
Question: The formula of bromic acid is _. (a) HBr (b) HBrO4 (c) HBrO (d) HBrO3 (e) HBrO2Which of the following have the same number of electrons (isoelectronic)?1. 2. 3. 4. 5.19 9F Ne20 10Ne Mg27 1314 7N 3-19 9F20 10Ne24 12
Ohio State - CHEM - 121
Lecture 5 Chapter 3 Stoichiometry (continued) Reading: section 5-7 Homework 3: 12, 14, 16, 18, 20, 22b, 22d, 24b, 24d, 34, 38, 44, 48, 52, 54, 58, 62, 64, 72, 74. Due: Thursday Oct. 11, 8PMThe MoleProblem 1: How many moles of copper are in 2.50g C
Ohio State - CHEM - 121
Which of the following is the correct, balanced chemical equation for the combustion of ethanol (C2H5OH)?1. 2. 3. 4. C2H5OH + O2 C2H5OH + 3 O2 C2H5OH + 6 O2 2 C2H5OH + 7 O2 CO2 + H2O 2 CO2 + 3 H2O 4 CO2 + 6 H2O 4 CO2 + 6 H2O O O C C OCorrect Answe
Ohio State - CHEM - 121
Lecture 7 Chapter 4 Aqueous Reactions and Solution Stoichiometry (continued) Homework 4: chapter 4: 16, 20, 22, 24, 26, 38, 40, 42, 50, 52, 56, 62, 66, 68, 72, 74, 78, 80 Due: Thursday, Oct. 18 (drop in the file pockets) Today's Reading: section 4-6
Ohio State - CHEM - 121
Lecture 8, Oct. 16 Chapter 4. Aqueous Reactions and Solution Stoichiometry (continued) Reading: section 5 & 61Examples: 1. Calculate the molar concentration of a solution that contains 2.8g KOH in 250 ml solution. 2. What is the molarity of hydro
Ohio State - CHEM - 121
Lecture 9, Oct. 18 Chapter 6. Electronic Structure of Atoms Reading: section 1-5 Homework 5: chapter 6 16, 26, 30, 34, 36, 38, 50, 52, 54, 56, 60, 64, 66, 68, 72, 74 Due: Tuesday, Oct. 30th, 8PM (drop in the file pockets)Water Wave1The Wave Na
Ohio State - CHEM - 121
1020304050607080009. 991st midterm distributionAverage: 129 out of 17520 -2 9. 99 40 -4 9. 99 60 -6 9. 99 80 -8 9. 99 10 010 9. 99 12 012 9. 99 14 014 9. 99 16 016 9. 99Lecture 10, Oct. 23 Chapter 6. Electronic Structure of
Ohio State - CHEM - 121
Lecture 11, Oct. 25 Chapter 7. Periodic Properties of Elements Reading: section 1-5 Homework 6: Chapter 7: 12, 22, 24, 26, 28, 34, 38, 40, 42, 44, 46, 60, 64, 68, 70, 72, 76, 78 Due: Tuesday, Nov. 6th, 8PM (drop in file pockets)Ionization EnergyVa
Wright State - HIST - 101
gnuplot Quick Reference(Copyright(c) Alex Woo 1992 June 1) Updated by Hans-Bernhard Brker, April 2004 oGraphics DevicesAll screen graphics devices are specified by names and options. This information can be read from a startup file (.gnuplot in U
UIllinois - ARCH - 342
Daylight Availability1. 2. 3. 4. 5. 6. Correction for Solar Time Sky Conditions Solar Angles Overhangs Design Shadows & Sunlight Penetration Determining Daylight IlluminanceUniversity of Illinois at Urbana-Champaign Architecture 342 Fall 2006DA
Kansas State University - MATH - 240
Elementary Differential Equations-Math 240 Exam 2-Summer 2007 June 29, 2007 Name. Instructor. 6 7 8 9 Total12345This is a closed book exam. You can use a calculator and 8 "X 11" sheet of hand written note (both sides).Please write legibly
Kansas State University - MATH - 240
.rName: Recitation:Math 240t'")March 14, 2006Exam 'X,' vProblem 1 2 3 4 5 6 7 8 TotalScoreClosed book. You may use a calculator and one 8 ~ x 11" sheet of handwritten notes (both sides). You must show your work to receive full credit.
UIllinois - ARCH - 342
Architecture 342 Environmental Technology II Daylighting DesignIntroduction to Daylighting DesignArchitecture 342 Environmental Technology II Prof. M. BoubekriArchitecture 342 Environmental Technology II Daylighting Design1Architecture 342
UIllinois - TAM - 211
UIllinois - ARCH - 342
The Lumen Method of ToplightingRoof PlanCondition of use: 1. Uniform light distribution 2. No direct sunlight penetration into the roomSectionThe Lumen Method for ToplightingAverage Diffuse Daylight Illuminance in the SpaceEwp = ( EhD + Ehd
UIllinois - ARCH - 342
The Lumen Method of SidelightingThe Lumen Method of SidelightingConditions of use: 1. Diffuse light only inside the room. NO direct sunlight inside the room 2. Wall window is from wall to wall and from window sill to ceiling1The Lumen Method o
UIllinois - TAM - 211