BI09B11
American International, CHE 331
Excerpt: ... BI09B11 electromotive force Or , Genetic Errors Mutations Mutage ns Knockouts ...
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lect15_handout
Wisconsin, PHYS 202
Excerpt: ... Physics 202, Lecture 15 Todays Topics Faradays Law (Ch 31) Review Emf Change of Magnetic Flux and Emf () Lenz s Lenzs Law and its applications Formulation of Faradays Law Expected Preview: Ch 31.1-3 Sources of E and B Fields: An overview Sources for the electric field: Electric charges (Coulomb's Law, static) subjects of past several weeks Change of B field (Faraday's Law, varying in time) Today Sources for the magnetic field: Electric current (Biot-Savart Law/Amperes Law, static) Last week Change of E field (Ampere-Maxwell Law, varying) Ch 34 All these features are summarized in Maxwells Equations. Ch 34 Review: Electromotive Force (emf, ) Electromotive force , emf, is a measure of the voltage that can be provided by a source. emf is not a force, it has a unit of volts sources of emf: chemical process (battery) change of magnetic flux = 1.5V semiconductors. + + Demo: Emf and Change of Magnetic Flux e.g. battery: notice that emf has a direction emf may exis ...
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lect15
Wisconsin, PHYS 202
Excerpt: ... Physics 202, Lecture 15 Todays Topics Faradays Law (Ch 29) Change of Magnetic Flux and Emf () Lenzs Law Faradays Law of Induction Electromotive Force (emf, ) Electromotive force , emf, is a measure of the voltage that can be provided by a source. For a given device, if a charge Q passes through that device, and gains an energy U, the net emf for that device is the energy gained per unit charge, or U/Q. emf is not a force, it has a unit of volts sources of emf: = 1.5V + chemical process (battery) + change of magnetic flux + semiconductors. e.g. battery: notice that emf has a direction - emf may exist even if no current. 1.5V Demo: Emf and Change of Magnetic Flux Lenzs Law The emf due to change of magnetic flux tends to create a current which produces a magnetic field to compensate the change of original magnetic flux. Lenzs law is a convenient way to dete ...
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Lecture2
Rowan, ENG 102
Excerpt: ... Freshman Engineering Clinic II OHM: The Man, The Law, The Field Lecture 2 Ohm: The Man, The Law, The Field Ohm: The Man Ohm, Georg Simon (1787-1854), German physicist, best known for his research on electrical currents. He was born in Erlangen and educated at the University of Erlangen. From 1833 to 1849 he was director of the Polytechnic Institute of Nrnberg, and from 1852 until his death he was professor of experimental physics at the University of Munich. His formulation of the relationship between current, electromotive force , and resistance, known as Ohm's law, is the basic law of current flow. The unit of electrical resistance was named the ohm in his honor. Microsoft Encarta Reference Library 2002. 1993-2001 Microsoft Corporation. All rights reserved. Ohm: The LawResistance A conductor allows an electric current to flow through it, but it does not permit the current to flow with perfect freedom. Collisions between the electrons and the atoms of the conductor interfere with the flow of electr ...
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lect15
Wisconsin, PHYS 202
Excerpt: ... Physics 202, Lecture 15 Todays Topics Faradays Law (Ch 29) Change of Magnetic Flux and Emf () Lenzs Law Faradays Law of Induction Sources of E and B Fields: An overview Sources for the electric field: Electric charges (Coulomb's Law, static) subjects of past several weeks Change of B field (Faraday's Law, varying in time) Today Sources for the magnetic field: Electric current (Biot-Savart Law/Amperes Law, static) Chapter 28 Change of E field (Ampere-Maxwell Law, varying) Chapter 28 All these features are summarized in Maxwells Equations. Lecture 21 (Chapter 31) Review: Electromotive Force (emf, ) Electromotive force , emf, is a measure of the voltage that can be provided by a source. For a given device, if a charge Q passes through that device, and gains an energy U, the net emf for that device is the energy gained per unit charge, or U/Q. emf is not a force, it has a unit of volts sources of emf: ...
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ps7
Weber, PHSX 2220
Excerpt: ... Physics 2220 (Schroeder) fall 2005 Name Problem Set 7 (due Friday, October 12) 1. You have a loop of wire and a bar magnet. List at least three different ways to change the magnetic flux through your loop (and hence to induce a current in it). For each way of changing the flux, explain whether the force that causes the electrons to flow around the wire is an electric force or a magnetic force. The figure below shows a triangular loop of wire that is being pushed with speed |v| into a magnetic field. Left of the dashed line, there is a uniform field B pointing into the page; right of the dashed line there is no magnetic field. The left end of the triangle enters the field at time t = 0. Use the magnetic force law (not the flux rule or Faraday's law) to compute the electromotive force in the loop. (Remember that electromotive force is the work per unit charge done on each moving electron, not counting any possible resistive forces in the wire. You can compute the work as FB ds, where ds is the displacement ...
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Lecture_09_2097
Pittsburgh, PHYS 01750
Excerpt: ... ting. 32 The resistances of resistors A and B are R and 2R, respectively. If the same potential difference is applied across each resistor, the power dissipated in resistor A is a) one quarter b) one half c) the same as d) twice e) four times the value in resistor B. 33 Halliday, Resnick and Walker: Problem 26-39 A 120 V potential difference is applied to a space heater whose resistance is 14 when hot. (a) At what rate is electrical energy transferred to thermal energy? (b) What is the cost for 5.0 h at US$0.05/kWh? 34 Halliday, Resnick and Walker: Problem 26-58 A potential difference of 1.20 V will be applied to a 33.0 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (a) the current, (b) the magnitude of the current density, (c) the magnitude of the electric field within the wire, and (d) the rate at which thermal energy will appear in the wire. 35 Electromotive Force (emf) Electromotive force is defined as the work done per unit charge by nonelectrical means: dW E= dq Uni ...
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329fall08hw3sol
UIllinois, ECE 329
Excerpt: ... ECE-329 Fall 2008 Homework 3 (Solution) September 15, 2008 1. In this problem, we will study Faradays law, d E dl = B dS, dt C which states that the electromotive force E = C E dl around any closed loop C equals the time rate of change of the magnetic ux B = S B dS through the surface S bounded by the loop. (a) If B = 0 at all times, the magnetic ux is also zero (B = 0), and therefore, according to Faradays law, the electromotive force is zero (E = 0) over any closed loop C. (b) If B =0 then it is possible for E = 0 if the path C is disturbed or being displaced in such a way that the magnetic ux B = S B dS varies in time. (c) Let us dene a closed loop C passing through the xed points P1 and P2 (see the next gure). dl path A P2 C dl P1 path B S Since B is time-independent, the corresponding magnetic ux B is also time independent, and therefore, dB E dl = = 0. dt C Breaking the closed path integral into two parts, we have ...
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pdfSEEE 340.day43
ASU, EEE 340
Excerpt: ... EEE 340-April 9 Agenda Electrodynamics Maxwell's equations Electromotive Force and Kirchhoff's voltage law Schedule this Week Office hours Monday 1:30-2:40, Thursday 12:30-1:30 in GWC 422 Problem session Thursday, 11:30-12:30 in ERC 593. Normal homework & reading assignment due dates Modified HW due on Friday Copyuright 2001 by James T. Aberle and R. Grondin Homework due next Friday Chapter 8 Problem 1 Problem 2 Problem 27 Problem 30 Chapter 9 Problem 7 Problem 10 Copyuright 2001 by James T. Aberle and R. Grondin EEE 340-April 9 Agenda Electrodynamics Maxwell's equations Electromotive Force and Kirchhoff's voltage law Schedule this Week Office hours Monday 1:30-2:40, Thursday 12:30-1:30 in GWC 422 Problem session Thursday, 11:30-12:30 in ERC 593. Normal homework & reading assignment due dates Modified HW due on Friday Copyuright 2001 by James T. Aberle and R. Grondin 1 What happens if the fields are varying in time? Electromagnetic induc ...
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Magnetic_effects_in_matter
Syracuse, PHY 344
Excerpt: ... Feb. 2001 Magnetic Effects in Matter Phy 344 Introduction: This experiment is primarily intended to familiarize you with three important topics in magnetism: Electromagnets based on iron. Magnetic fluxmeters based on Faraday's law. The Hall effect in semiconductors. Each of these three topics will require that you understand a different type of physics. For electromagnets you generalize the basic idea that currents generate magnet fields to include the effects of strongly magnetic materials - in this case "soft" (ie. magnetically soft) iron. The fluxmeter is a device which measures magnetic flux by exploiting Faraday's law: a coil which cuts magnetic field lines will generate an electromotive force . Finally the Hall effect pertains to to the motions of the mobile charges inside matter when they experience both electric and magnetic forces. Suggested Reading: 1. Jerry B. Marion and William F. Hornyak, Principles of Physics (Saunders, New York, 1984), sections 31-4, 31-5, and Enrichment Topic B. This textboo ...
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lecture18
University of Illinois, Urbana Champaign, MATSE 346
Excerpt: ... Properties and Selection of Engineering Materials Lecture 18 18.1 Galvanic series Electromotive force : DC voltage needed to halt the ionization of a metal in a standard electrolyte. MatSE 346, Y Q Sun, UIUC, Fall 1999 1 Properties and Selection of Engineering Materials Lecture 18 Electromotive force series Metal Li Na Mg Al Ti Zn Fe Pb Ion Li+ Na+ Mg+ Al+ Ti+ Zn+ Fe+ Pb+ emf (V) -3.02 -2.71 -2.34 -1.67 -1.63 -0.76 -0.44 -0.13 2 MatSE 346, Y Q Sun, UIUC, Fall 1999 Reactive metals Properties and Selection of Engineering Materials Lecture 18 Electromotive force series Metal Cu Ag Hg Pt Au Ion Cu+ Ag+ Hg+ Pt+ Au+ emf (V) 0.33 0.79 0.86 1.20 1.50 MatSE 346, Y Q Sun, UIUC, Fall 1999 Noble metals 3 Properties and Selection of Engineering Materials Lecture 18 18.2 Galvanic two-metal corrosion Fe: anode, corrodes Cu: cathode, Does not corrode Introduction to Materials Science for Engineers, J.F. Shackelford, PrenticeHall, 1994. MatSE 346, Y Q Sun, UIUC, Fall 1999 4 Properties ...
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308_LN_Wk10
St. Lawrence, IT 308
Excerpt: ... ndreds of times larger than it would be for similar nonmagnetic metals. CLASS 20: ELECTROMOTIVE FORCE : The book talks about Electromotive force and its various causes, but there is not a lot here worth spending a lot of time with. The main thing I want you to see is that the Electromotive force , or "Emf" (normally pronounced "E-M-F"), is a voltage, not a force. Maybe the best thing to do is to write Emf, but pronounce it "oomf". I call it oomf because it is what provides the oomf to cause the charges to move in a circuit. OK, so in summary, Emf = voltage. The author's main reason for making a big point of the Emf seems to me to prepare you for the fact that there can be a nonzero Emf around a circuit. This contradicts Kirchhoff's voltage rule only if you confuse Emfs with voltages (which is a better thing to confuse them with than say 'forces'). MOTIONAL EMF: Let's return to the Hall effect. In the Hall effect a charge moving in a magnetic field is deflected, and this gives rise to a voltage perpendicular to ...
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Lecture26
Delaware, PHYS 202
Excerpt: ... Lecture 26 11/3/06 Energy in electric field Electromotive force Current Resistivity Resistance Ohms law Electric power Alternating current Phys202 Charge and potential are proportional, set by shapes, positions, orientations, medium between conductors, etc. Capacitance: q = CV Units: Farad= Work done as battery charges capacitor Energy needed to add charge starts at zero and increases Review: energy in charged capacitor Phys202 Coulomb Volt Total work done: W = qV = q V 2 W = ( CV ) W= 1 2 kx 2 Using expression for capacitor: q = CV Similar to spring potential energy! Pinball game Ball hits barriers as it rolls down How is this similar to a resistor? Homework 8 on Chapter 19 due today V 1 = CV 2 2 2 General expression for parallel plate capacitor: Energy = 1 CV 2 2 = 1 0 A 2 ( E d ) 2 d = 1 0 E 2 ( A d ) 2 Energy density = Energy 1 = 0 E 2 Volume 2 Example Phys202 The electronic flash attachment for a camera contains ...
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Ch21_W05
E. Michigan, PHY 222
Excerpt: ... circuits Ammeters and Voltmeters Specific Objectives This section, chapter 21 and the lectures that go with it, is the most important in our study of electricity because it provides the foundation for instrumentation in electrical measurements. Everything in this section is important, but you should pay particular attention to being able to: 1. understand the concept of electromotive force . 2. to use Ohm's law to help define resistance and to find the resistance in simple circuits. 3. differentiate between electric current and electron current. 4. calculate the power used in a circuit. 5. calculate the heat given off by a resistor in a given circuit. 6. calculate resistivity and demonstrate an understanding of this property. 7. demonstrate an understanding of what is meant by a semiconductor, and a superconductor. 8. define these terms: EMF resistance ohm watt kilowatt-hour resistivity superconductivity semiconductor 9. find the equivalent resistance for resistors in series and parallel circuits. 10. fin ...
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lecture_38_notes
Rose-Hulman, ECE 340
Excerpt: ... an electromagnetically induced voltage (It could also be an electrochemical battery or a photovoltaic source-let's suppose here that it's due to electromagnetic induction.) At some distance power plant, steam is driving the vans of a turbine connected to a shaft. This mechanical motion is coupled to the electric charge carriers via Faraday's Law. Mechanical energy produces mechanical motion and provides the v (it makes a shaft turn) in the Lorentz Force Law. We tie a magnetic field to this motion and induce voltage in a winding. lecture 38 notes 4 Transformer and Motional emf In General d m dt V = - (V is emf) In terms of the flux density. V = - d B i ds dt surface Transformer emf For the case where the surface is stationary in space, we can take the derivative inside the integral. V = - B i ds t surface lecture 38 notes 5 Motional emf Suppose we have a moving conductor in a magnetic field. F = q (v x B) (F is the actual electromotive force , it's a bit confusing that V is termed ...
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lec8
Clark Atlanta, PHY 122
Excerpt: ... Class Notes 8 Instructor: H. L. Neal 1 Electromotive Force Electromotive force (emf) is de.ned as the amount of energy gained per unit charge that passes through a device in the opposite direction to the electric .eld produced by that device. It is measured in volts. Sources of emf include electric generators (both alternating current and direct current types) and batteries. Electromotive force is often denoted by E. + R Created using UNREGISTERED Top Draw 3.10 Oct 7,'106 3:17:27 PM E In the circuit Fig. 1, the emf prodiced by the battery pushes electric charge aroubd the circuit to produce the current I. The electric potential dierence accross the resistor is V = IR = E: 2 Resistors in Series and Parallel = R1 R2 R1 + R2 R1 = 1/R1 + 1/R2 R2 Createdu gUNREG ERED T pDraw3.10O 7,'106 2:46:58PM sin IST o ct The resistors add and resistors in parallel divide is a good way to remember how to determine the equivalent resistance for any combination. Note that this es exactly opposite to the rule fo ...
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em04_sol6
Toledo, PHY 138
Excerpt: ... | = 1.60 10- 5 T for the 8.00 A current in wire 2. (d) From the lecture notes again we see that the force per unit length is given by: d|FB | = I1 |B2 | dl Given the field from part c) above and multiplying it by the current in wire |fB | one we find |f )21 | = 8.00 10-5 N/m . This had to be the same force we calculated in part b) above. 23.12 We know that the magnetic force on this wire moving through the |B| field is given by: |FB | = IlB And that from Faraday's law the electromotive force that will be generated in the loop that contains the bar will be: E = Blv But we can relate the electromotive force in the loop to the current and resistance using Ohm's law and so get: I= which can be re-arranged to give: IR lv (a) Plugging this all the way back into the first equation gives: B= I 2 lR |FB | = lv But we know that we are using a 1.00 N force to push the bar through the magnetic field at v = 2.00 m/s. So we can rearrange this to get: |FB |v = R 1.00 2.00 = 0.500A 8.00 . E Blv = R R I= So the c ...
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lecture-march20
St. Mary MD, PHYS 2520
Excerpt: ... Lecture #26, March 20 Kirchhoff's Rules Today we shall continue our study of electric currents. In order to have electric current, it is necessary to have a closed circuit which starts at one of the terminals of the battery, connected to one or combination of electric devices and then connected to the other terminal of the battery. The battery serves as a source of energy for the circuit. If there is no current going through the battery then the potential difference across the battery is the same as its nominal value, which is also known as electromotive force of the battery . Knowing the electromotive force of all the batteries in the circuit, one can calculate currents in various parts of the circuit. These currents are related to potential drops according to the Ohm's law as I= V . Req (26.1) Here Req is the equivalent resistance for the appropriate part of the circuit. Last time our task was to find out how one can calculate this resistance for different combinations of the resistors. We shall continue ...
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week14_1
Arizona, PHYS 331
Excerpt: ... y doesn't depend upon r. i.e. it is uniform as a function of r. * The potential therefore can be described by V = V0 z . L ^ And, E = - V0 z. L i.e. the electric field is uniform throughout the wire. The more well-known version of Ohm's Law. * For the cylindrical wire above, what is the current? * I = JA. J = E. I = EA E=V L I = A V . L L . A * V = IR Where R = 2 Electromotive Force The electromotive force is the work/unit charge to move a charge around a circuit. * qV = F dl. * E= Fdl q * It's actually a potential (not a force). * In an ideal battery, the potential across the terminals is E (emf). Recall the Lorentz Force law. * F = q(E + v B) Let's concentrate on the magnetic term. * E= q(vB) q dl A (B C) = C (A B) * E = B (dl v) * E = - B (v dl) B l v Now, take a rectangular loop of wire partially in a uniform magnetic field. * Only one of the edges will contribute to the EMF. * v dl = * v dl = dA . dt dx dt dl But, B dA = . * So, E = - d . d ...
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08F303L_L17_081006_Mon
University of Texas, PHY 303l
Excerpt: ... s. You should read the first 3 sections of chapter 28 before coming to class. Class notes are available for Fridays lecture on current, resistivity, and resistance. Chapter 27 Currents and Ohms Law 27.1 Electric current 27.2 Resistance and Ohms Law 27.3 Resistivity of materials 27.4 Resistances in combination Chapter 28 Direct Current Circuits 28.1 Electromotive force 28.2 Sources of electromotive force 28.3 Single-loop circuits 28.4 Multiloop circuits 28.5 Energy in circuits; joule heat 28.6 Electrical measurements 28.7 The RC circuit 28.8 The hazards of electric currents ...
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Lecture6_Electric_Circuits
Fayetteville State University, PHY 2049
Excerpt: ... 25. Electric Circuits Topics Electromotive "Force" Series and Parallel Resistors Kirchhoff's Rules RC Circuits 2 Circuit Symbols 3 Electromotive "force" (emf) An electric field in a conductor causes the free charges to drift. But, very quickly, the electric field energy will be dissipated within the conductor and reduce the electric field to zero. The conductor will then be in electrostatic equilibrium. 4 Electromotive "force" (emf) However, it is possible to maintain an electric field in a conductor if we can supply energy to the electric field to compensate for the energy dissipation. The conductor will no longer be in electrostatic equilibrium. A device that provides this compensating electrical energy is called a source of electromotive "force" (emf) 5 Electromotive "force" (emf) The (old) term electromotive force is very misleading because it has nothing to do with force! An ideal emf is simply a constant potential difference between two points. And ideal battery is a device that can supply a ...
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