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PHYS 2306 - Foundations Of Physics I - Virginia Tech Study Resources
  • 1 Page PHYS 2306 Solution Quiz 8
    PHYS 2306 Solution Quiz 8

    School: Virginia Tech

    Course: Foundations Of Physics II

    22) A bird is flying south with a positive charge in its beak. It flies through a homogeneous magnetic field that points towards the center of the earth. What is the direction of the magnetic force on the bird? A. B. C. D. E. F. north east south west away

  • 3 Pages q10_c29_sol
    Q10_c29_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 10 Phys. 2306 F09 You may use your text book, notes, and a calculator. A long straight wire is carrying constant current I in the +x direction. In (A) a metal rod of very small diameter is moving with constant velocity v in the +x diection. The rods

  • 2 Pages q9_sol_c28
    Q9_sol_c28

    School: Virginia Tech

    Course: Physcs 1

    Quiz 9 Phys. 2306 F09 You may use your text book, notes, and a calculator. Three innitely long wires run from z and carry currents of magnitude I. The current in wire 1 that passes through the point (x,y)=(0,a) ows in the +z direction, the current in the

  • 2 Pages q8_c27_sol
    Q8_c27_sol

    School: Virginia Tech

    Course: Physcs 1

    Solutions to Quiz 8 Phys. 2306 F09 You may use your text book, notes, and a calculator. A particle with negative charge q and mass m = 2.00 1015 kg is traveling at t = 0 with (vx , vy , vz ) = 1.00106 (3, 4, 5) m/s , at position (x, y, z ) = (a, 0, 0) m.

  • 1 Page q7_sol_2-5
    Q7_sol_2-5

    School: Virginia Tech

    Course: Physcs 1

    Quiz 7-2-5 Use lower 2 loops: a 4.00 E1 b E2 c 3.00 I1 I2 3.00 A 6.00 5.00 A d I in 3.00 resistor is I1+I2=8.00 A (e) This I is positive so sense stays the way it is drawn up (a) 0=(V(a)-V(b)+(V(d)-V(a)+(V(b)-V(d) = E1 -12.0 -24.0 E1=36.0 V (c) 0=(V(c)

  • 1 Page q7_sol_1
    Q7_sol_1

    School: Virginia Tech

    Course: Physcs 1

    Quiz 7-1 Use outer loop: R a 2.00 A c 4.00 6.00 3.00 A 5.00 A d (V(a)-V(c)+(V(d)-V(a)+V(c)-V(d)=0 -2.00R -12.00 +30.00 = 2.00R = 18.00 R = 9.00 (c) R 2.00 A a c b 4.00 E1 E2 6.00 Original Circuit 3.00 5.00 A 3.00 A d

  • 1 Page q6_sol_3-5
    Q6_sol_3-5

    School: Virginia Tech

    Course: Physcs 1

    Quiz 6- 3,4,5 C CP CP C = C C CS = V V V CP = C+C = 3C 1/CS = 1/3C+1/3C = 2/3C CS = (3/2)C U = CSV2/2 = (3/4)CV2 U-U = (3/4 2/3)CV2 = (1/12)CV2 C=2C Switch closed Q (QS QP) = (Cs - CP) V = (3/2-4/3)CV = (1/6)CV >0 Potential difference across battery is co

  • 1 Page q6_sol_1-2
    Q6_sol_1-2

    School: Virginia Tech

    Course: Physcs 1

    Quiz 6- 1,2 C C d a c C C V CS CS = V CP = V C=2C Switch open 1/CS = 1/C+1/C = (1/C)(1+1/2) = 3/(2C) CS = (2/3)C CP = 2CS = (4/3)C U = CPV2/2 = (2/3)CV2 QP = CPV = (4/3)CV QS = QP/2 = (2/3)CV = QC = QC Vc-Vd = (Vc-Va) + (Va-Vd) = -QC/C + QC/C = (2/3)(CV)(

  • 2 Pages q5_sol
    Q5_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 5 Phys. 2306 F09 Crn94823 You may use your text book, notes, and a calculator. Two very large area parallel, conducting plates A,B are kept at a potential dierence V by a battery. The plates are separated by a distance d. Small holes are drilled in t

  • 2 Pages q3_sol
    Q3_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 3 Phys. 2306 F09 CRN 94850 You may use your text book, notes, and a calculator. In order to illustrate that matter is electrically neutral to a very high degree, consider two Cu spheres of radii 0.1 cm that are 1 m apart. Thus they look like point ch

  • 2 Pages q2_sol
    Q2_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 2 Phys. 2306 F09 CRN 94850 You may use your text book, notes, and a calculator. Two loud speakers A,B are a distance L= 2.00 m apart. They each emit pure tones of frequency f= 206 Hz. The speed of sound in air is 344 m/s. 1) Along the line joining th

  • 2 Pages q1_sol
    Q1_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 1 Phys. 2306-94850 F09 You may use your text book, notes, and a calculator. A transverse wave on a string of mass/length is generated by xing one end of the string and attaching the other end to a motor that has an amplitude A, maintains a tension T

  • 6 Pages vectors
    Vectors

    School: Virginia Tech

    Course: Physcs 1

    Physics 2306 M. Blecher August 18, 2009 Chapter 1 Vectors 1.1 Representation of Vectors Vectors in three dimensional (3D) space are quantities possessing magnitude and direction. They are written in bold font in this note. In component form,vector A is wr

  • 2 Pages q3_sol
    Q3_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 3 Phys. 2306 F09 CRN 94850 You may use your text book, notes, and a calculator. In order to illustrate that matter is electrically neutral to a very high degree, consider two Cu spheres of radii 0.1 cm that are 1 m apart. Thus they look like point ch

  • 2 Pages PHYS 2306 Solution Quiz 7
    PHYS 2306 Solution Quiz 7

    School: Virginia Tech

    Course: Foundations Of Physics II

    a R=3 = 12 volts R=4 R=5 b C=6 F S1 c 19, 20 and 21) Consider the circuit shown above. The switch is closed at time t =0. 19) Just after the switch is closed, what is the current (in Amps) through the 4.0 resistor? A. B. C. D. E. F. G. H. 60/47 12/7 2

  • 1 Page PHYS 2306 Solution Quiz 6
    PHYS 2306 Solution Quiz 6

    School: Virginia Tech

    Course: Foundations Of Physics II

    16, 17 and 18) Consider the circuit shown below. The current through the 4 resistor is 3.0 A. 16) What is the equivalent resistance (in ohms) of the three resistors? A. B. C. D. E. F. G. H. 26/7 9 20/9 16/3 22/3 7 5 3 R=2 R=3 R=4 3 and 4 are in parallel.

  • 2 Pages PHYS 2306 Solution Quiz 5
    PHYS 2306 Solution Quiz 5

    School: Virginia Tech

    Course: Foundations Of Physics II

    13) You move a positive charge q = 3.0 C from the negative to the positive terminal of a 6.0 V battery. How much work (in Joules) did you do? A. B. C. D. E. F. G. H. 3.0 3.0 6.0 6.0 12 12 18 18 Change in electric potential energy of the charge q is q

  • 1 Page PHYS 2306 Solution Quiz 4
    PHYS 2306 Solution Quiz 4

    School: Virginia Tech

    Course: Foundations Of Physics II

    10) A charge q = 4.0E-06 is inside a spherical surface, but not at the center of the sphere? What is the electric flux (in N-m2/C) through the surface of the sphere A. Cant determine the flux because the charge is not at the center of the sphere B. 2.3E+0

  • 1 Page PHYS 2306 Solution Quiz 3
    PHYS 2306 Solution Quiz 3

    School: Virginia Tech

    Course: Foundations Of Physics II

    7) A positive charge q is placed at (x = a, y = 0, z = 0). A negative charge 2q is placed at (x = 2a, y = 0, z = 0). What is x-component of the electric field at the origin? A. B. C. D. E. F. G. H. 3kq/a2 3kq/2a2 3kq/a2 kq/2a2 kq/2a2 3kq/4a2 3kq/4a2 3

  • 1 Page PHYS 2306 Solution Quiz 2
    PHYS 2306 Solution Quiz 2

    School: Virginia Tech

    Course: Foundations Of Physics II

    4.) A pipe is 0.40 meters long. It is open at one end and closed at the other end? If the frequency produced by the pipe is 1075 Hz, what is the harmonic of that tone? The speed of sound in air is 344 m/s. A. 1 B. 2 Pipe open at one end and closed at the

  • 1 Page PHYS 2306 Solution Quiz 1
    PHYS 2306 Solution Quiz 1

    School: Virginia Tech

    Course: Foundations Of Physics II

    1. and 2.) The displacement of a transverse traveling wave is given by y(x,t) = (0.30 m)cos[2(x/0.50 m + t/0.0025 s)] 1.) The velocity (in meters/sec) of the wave is (positive velocity is in the +x-direction, negative velocity is in the x-direction) A. B.

  • 11 Pages PHYS 2306 Test 2 Solution
    PHYS 2306 Test 2 Solution

    School: Virginia Tech

    Course: Foundations Of Physics II

    Physics 2306 Second Exam Fall 2008 FORM D 1.) An ideal 12 V EMF is in series with a 2 F capacitor. The left plate of the capacitor has 1.5E05 C charge and the right plate has +1.5E05 C charge as shown in the figure below. What is the potential difference

  • 10 Pages PHYS 2306 Test 1 Solution
    PHYS 2306 Test 1 Solution

    School: Virginia Tech

    Course: Foundations Of Physics II

    Physics 2306 Fall 2008 First Exam FORM A 1) The pressure fluctuation in air due to a sound wave is given by p(x,t) = (20 Pa) sin[(5 radians/meter) x (2500 radians/second) t] Which one of the following statements is true? A. The wave is a transverse wave a

  • 8 Pages PHYS 2306 Final
    PHYS 2306 Final

    School: Virginia Tech

    Course: Foundations Of Physics II

    Physics 2306 Spring 2008 Final FORM A 1) What is the first Maxwell equation (based on the order given in my lecture notes)? A. B. C. D. E. F. G. H. around perimeter of surfaceBdl = 0[Ienclosed 0 dE/dt] over closed surface Enon-conservativedA = Qenclosed/0

  • 2 Pages q4_sol
    Q4_sol

    School: Virginia Tech

    Course: Physcs 1

    Quiz 4 Phys. 2306 F09 CRN 94850 You may use your text book, notes, and a calculator. Consider a hollow conductor. Its outer surface is a sphere with radius, R=0.100 m, while the inner surface is irregular. In the hollow cavity and insulated from the condu

  • 8 Pages exam_f_ins
    Exam_f_ins

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Final Exam F09 Instructions December 7, 2009 0 INSTRUCTIONS & FORMULAS FINAL EXAM F09 PHYS2306 This is a closed book exam. No books, notes, computers or other paper may be brought into the exam. All cell phones must be shut o. The honor system

  • 6 Pages exam_3a_09_sol
    Exam_3a_09_sol

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 3 F09 Form A November 25, 2009 0 Phys. 2306 Exam 3 F09 Form A Solutions In cosmic ray experiments, particles travel downward (j) with speed v= 3.00 106 m/s. They enter a region of constant magnetic eld, directed into the paper (k) at (x,y,

  • 6 Pages exam_3_ins
    Exam_3_ins

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 3 F09 Instructions November 3, 2009 0 INSTRUCTIONS AND FORMULAS EXAM 3 F09 PHYS. 2306 This is a closed book exam. No books, notes, computers or other paper may be brought into the exam. All cell phones must be shut o. The honor system is i

  • 26 Pages 30_InstructorSolutions
    30_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    INDUCTANCE 30 Apply Eq.(30.4). di (a) E2 = M 1 = (3.25 10-4 H)(830 A/s) = 0.270 V; yes, it is constant. dt 30.1. IDENTIFY and SET UP: EXECUTE: (b) E1 = M di2 ; M is a property of the pair of coils so is the same as in part (a). Thus E1 = 0.270 V. dt EVALU

  • 26 Pages 29_InstructorSolutions
    29_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    ELECTROMAGNETIC INDUCTION 29 29.1. 29.2. IDENTIFY: Altering the orientation of a coil relative to a magnetic field changes the magnetic flux through the coil. This change then induces an emf in the coil. SET UP: The flux through a coil of N turns is = NBA

  • 28 Pages 28_InstructorSolutions
    28_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    SOURCES OF MAGNETIC FIELD 28 28.1. ! ^ EXECUTE: (a) r = ( 0.500 m ) i , r = 0.500 m ! ! ^ v r = vr^ i = -vrk j ^ ! IDENTIFY and SET UP: Use Eq.(28.2) to calculate B at each point. ! ! ! ! ! qv r 0 qv r ^ r ^ B= 0 = , since r = . 4 r 2 4 r 3 r ! ! 6 ^ and

  • 29 Pages 27_InstructorSolutions
    27_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    MAGNETIC FIELD AND MAGNETIC FORCES 27 27.1. ! IDENTIFY and SET UP: Apply Eq.(27.2) to calculate F . Use the cross products of unit vectors from Section 1.10. ! ^ j EXECUTE: v = ( +4.19 104 m/s ) i + ( -3.85 104 m/s ) ^ ! ^ (a) B = (1.40 T ) i ! ! ! ^ ^ F

  • 35 Pages 26_InstructorSolutions
    26_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    DIRECT-CURRENT CIRCUITS 26 26.1. 26.2. 26.3. IDENTIFY: The newly-formed wire is a combination of series and parallel resistors. SET UP: Each of the three linear segments has resistance R/3. The circle is two R/6 resistors in parallel. EXECUTE: The resista

  • 22 Pages 25_InstructorSolutions
    25_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    CURRENT, RESISTANCE, AND ELECTROMOTIVE FORCE 25 25.1. 25.2. IDENTIFY: I = Q / t . SET UP: 1.0 h = 3600 s EXECUTE: Q = It = (3.6 A)(3.0)(3600 s) = 3.89 104 C. EVALUATE: Compared to typical charges of objects in electrostatics, this is a huge amount of char

  • 26 Pages 24_InstructorSolutions
    24_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    CAPACITANCE AND DIELECTRICS 24 24.1. 24.2. 24.3. Q Vab SET UP: 1 F = 10 -6 F EXECUTE: Q = CVab = (7.28 10 -6 F)(25.0 V) = 1.82 10 -4 C = 182 C EVALUATE: One plate has charge + Q and the other has charge -Q . Q PA and V = Ed . IDENTIFY and SET UP: C = 0 ,

  • 35 Pages 23_InstructorSolutions
    23_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    ELECTRIC POTENTIAL 23 ra = 0.150 m rb = (0.250 m) 2 + (0.250 m) 2 rb = 0.3536 m 23.1. IDENTIFY: Apply Eq.(23.2) to calculate the work. The electric potential energy of a pair of point charges is given by Eq.(23.9). SET UP: Let the initial position of q2 b

  • 28 Pages 22_InstructorSolutions
    22_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    GAUSS'S LAW 22 ^ E = E cos dA, where is the angle between the normal to the sheet n and the 22.1. (a) IDENTIFY and SET UP: electric field E . EXECUTE: In this problem E and cos are constant over the surface so E = E cos dA = E cos A = (14 N/C )( cos 60 )

  • 42 Pages 21_InstructorSolutions
    21_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    ELECTRIC CHARGE AND ELECTRIC FIELD 21 21.1. (a) IDENTIFY and SET UP: Use the charge of one electron ( -1.602 10 -19 C) to find the number of electrons required to produce the net charge. EXECUTE: The number of excess electrons needed to produce net charge

  • 22 Pages 16_InstructorSolutions
    16_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    SOUND AND HEARING 16 16.1. IDENTIFY and SET UP: Eq.(15.1) gives the wavelength in terms of the frequency. Use Eq.(16.5) to relate the pressure and displacement amplitudes. EXECUTE: (a) = v / f = (344 m/s)/1000 Hz = 0.344 m (b) pmax = BkA and Bk is constan

  • 26 Pages 31_InstructorSolutions
    31_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    ALTERNATING CURRENT 31 31.1. IDENTIFY: SET UP: EXECUTE: i = I cos t and I rms = I/ 2. The specified value is the root-mean-square current; I rms = 0.34 A. (a) I rms = 0.34 A 31.2. (b) I = 2 I rms = 2(0.34 A) = 0.48 A. (c) Since the current is positive hal

  • 16 Pages 32_InstructorSolutions
    32_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    ELECTROMAGNETIC WAVES 32 32.1. IDENTIFY: Since the speed is constant, distance x = ct. SET UP: The speed of light is c = 3.00 108 m/s . 1 yr = 3.156 107 s. 32.2. x 3.84 108 m = = 1.28 s c 3.00 108 m/s (b) x = ct = (3.00 108 m/s)(8.61 yr)(3.156 107 s/yr) =

  • 9 Pages exam_2a_09_sol
    Exam_2a_09_sol

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 2 F09 Form A October 16, 2009 0 Solutions Phys. 2306 Exam 2 F09 Form A In Thomsons atomic model of Helium, electrons are considered point charges and are like chocolate chips in cookie dough. In this case the dough is the alpha particle, t

  • 6 Pages exam_2_ins
    Exam_2_ins

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 2 F09 Instructions October 6, 2009 0 INSTRUCTIONS AND FORMULAS EXAM 2 F09 PHYS. 2306 This is a closed book exam. No books, notes, computers or other paper may be brought into the exam. All cell phones must be shut o. The honor system is in

  • 4 Pages exam_1a_09_sol
    Exam_1a_09_sol

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 1 F09 Form A Solutions Consider a horizontal (x) wire of uniform mass/length = 0.153 g/cm. The wire is attached to a wall at one end and driven up and down (y ) at frequency f= 2.00 Hz by a person applying tension T at the other end. Let y

  • 3 Pages exam_1_ins
    Exam_1_ins

    School: Virginia Tech

    Course: Physcs 1

    Phys. 2306 Exam 1 F09 Instructions September 8, 2009 0 INSTRUCTIONS AND FORMULAS EXAM 1 F09 PHYS. 2306 This is a closed book exam. No books, notes, computers or other paper may be brought into the exam. All cell phones must be shut o. The honor system is

  • 1 Page 2306fall2009
    2306fall2009

    School: Virginia Tech

    Course: Physcs 1

    PHYSICS 2306: FOUNDATIONS OF PHYSICS I Fall 2009 Text: University Physics by Young & Freedman Week 1 Start Date 8/24 2 8/31 3 9/7 4 9/14 5 9/21 6 9/28 7 10/5 8 10/12 9 10/19 10 10/26 11 11/2 12 11/9 13 11/16 14 11/30 15 12/7 Topics Introduction, Propertie

  • 20 Pages 38_InstructorSolutions
    38_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    PHOTONS, ELECTRONS, AND ATOMS 38 h f - . The e e 38.1. IDENTIFY and SET UP: The stopping potential V0 is related to the frequency of the light by V0 = slope of V0 versus f is h/e. The value fth of f when V0 = 0 is related to by = hf th . EXECUTE: (a) From

  • 20 Pages 37_InstructorSolutions
    37_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    RELATIVITY 37 Figure 37.1 37.1. IDENTIFY and SET UP: Consider the distance A to O and B to O as observed by an observer on the ground (Figure 37.1). (b) d = vt = (0.900) (3.00 108 m s) (5.05 10-6 s) = 1.36 103 m = 1.36 km. 37.3. 1 IDENTIFY and SET UP: The

  • 20 Pages 36_InstructorSolutions
    36_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    DIFFRACTION 36 36.1. IDENTIFY: Use y = x tan to calculate the angular position of the first minimum. The minima are located by m , m = 1, 2,. First minimum means m = 1 and sin 1 = / a and = a sin 1. Use this Eq.(36.2): sin = a equation to calculate . SET

  • 18 Pages 35_InstructorSolutions
    35_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    INTERFERENCE 35 35.1. 35.2. IDENTIFY: Compare the path difference to the wavelength. SET UP: The separation between sources is 5.00 m, so for points between the sources the largest possible path difference is 5.00 m. EXECUTE: (a) For constructive interfer

  • 38 Pages 34_InstructorSolutions
    34_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    GEOMETRIC OPTICS 34 y = 4.85 cm Figure 34.1 34.1. IDENTIFY and SET UP: Plane mirror: s = - s (Eq.34.1) and m = y / y = - s / s = +1 (Eq.34.2). We are given s and y and are asked to find s and y. EXECUTE: The object and image are shown in Figure 34.1. s =

  • 20 Pages 33_InstructorSolutions
    33_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    THE NATURE AND PROPAGATION OF LIGHT 33 33.1. IDENTIFY: For reflection, r = a . SET UP: The desired path of the ray is sketched in Figure 33.1. 14.0 cm EXECUTE: tan = , so = 50.6 . r = 90 - = 39.4 and r = a = 39.4 . 11.5 cm EVALUATE: The angle of incidence

  • 16 Pages 44_InstructorSolutions
    44_InstructorSolutions

    School: Virginia Tech

    Course: Foundations Of Physics II

    PARTICLE PHYSICS AND COSMOLOGY 44 44.1. (a) IDENTIFY and SET UP: Use Eq.(37.36) to calculate the kinetic energy K. 1 EXECUTE: K = mc 2 - 1 = 0.1547 mc 2 2 2 1- v / c m = 9.109 10 -31 kg, so K = 1.27 10-14 J (b) IDENTIFY and SET UP: The total energy of th

  • 3 Pages Chapter 35
    Chapter 35

    School: Virginia Tech

    Course: Foundations Of Physics

  • 5 Pages Chapter 16
    Chapter 16

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    Course: Foundations Of Physics

  • 6 Pages Chapter 15
    Chapter 15

    School: Virginia Tech

    Course: Foundations Of Physics

  • 9 Pages test1 solution
    Test1 Solution

    School: Virginia Tech

    Course: FOUNDATIONS OF PHYSICS I

    k = 9.0E+09 N-m2/C2 0 = 8.9E12 C2/N2-m2 Physics 2306 Spring 2004 fL =[(v vL)/(v vS)]fS First Exam The displacement of a transverse wave is given by y(x,t) = (0.02 m)sin[(400 rad/sec)t (10 rad/meter)x] What is the amplitude (in meters) of the wave? A. B. C

  • 8 Pages test2 solution
    Test2 Solution

    School: Virginia Tech

    Course: FOUNDATIONS OF PHYSICS I

    k = 9.0E+09 N-m2/C2 0 = 8.9E12 C2/N2-m2 Q(t) = Cx[1 - exp(-t/RC)] Physics 2306 Spring 2004 Second Exam 1.) If you move a positive charge from the negative terminal to the positive terminal of a battery, the change in electric potential energy of the charg

  • 9 Pages test3 solution
    Test3 Solution

    School: Virginia Tech

    Course: FOUNDATIONS OF PHYSICS I

    Physics 2306 Spring 2004 Third Exam Solution k = 9.0E+09 N-m2/C2 Q = Cx[1 exp(t/RC)] 0 = 8.9E12 C2/N2-m2 I = (x/R)[1 exp(Rt/L)] m0 = 4pE07 Wb/A-m Q = Q0 cos(wt + f) 1.) At t = 0 the switch is closed in an L-C circuit and the capacitor has its maximum char

  • 1 Page Test 3 review 3
    Test 3 Review 3

    School: Virginia Tech

    Course: Physics

  • 1 Page Test 3 review 2
    Test 3 Review 2

    School: Virginia Tech

    Course: Physics

  • 1 Page Test 3 review 1
    Test 3 Review 1

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    Course: Physics

  • 1 Page Study Guide 2
    Study Guide 2

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    Course: Physics

  • 1 Page Study Guide 1
    Study Guide 1

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    Course: Physics

  • 1 Page Cheat sheet2-2
    Cheat Sheet2-2

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    Course: Physics

  • 3 Pages Chapter 21
    Chapter 21

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    Course: Foundations Of Physics

  • 4 Pages Chapter 22
    Chapter 22

    School: Virginia Tech

    Course: Foundations Of Physics

  • 7 Pages Chapter 34
    Chapter 34

    School: Virginia Tech

    Course: Foundations Of Physics

    Chapter 34 Geometric Optics 34.1 Reflection and refraction at a plane surface Images Reflection 34.2 Reflection at a spherical surface Focal length Images 34.3 Refraction at a spherical surface 34.4 Thin lenses 34.7 Magnifier 34.8 Microscopes and Telescop

  • 4 Pages Chapter 32
    Chapter 32

    School: Virginia Tech

    Course: Foundations Of Physics

    Chapter 32 Electromagnetic Waves 32.1 Maxwells Equations 32.2 Plane electromagnetic waves 32.3 Sinusoidal electromagnetic waves 32.4 Energy and momentum Momentum flow and radiation pressure: Example: NASA is giving serious consideration to the concept of

  • 5 Pages Chapter 31
    Chapter 31

    School: Virginia Tech

    Course: Foundations Of Physics

  • 5 Pages Chapter 30
    Chapter 30

    School: Virginia Tech

    Course: Foundations Of Physics

    Chapter 30 Inductance 30.1-2 Mutual Inductance and Self-Inductance Mutual induction and mutual inductance Self-induction and self-inductance 30.3 Magnetic field energy The energy stored in an inductor 30.4 R-L Circuits Current growth Current decay 30.5 L-

  • 4 Pages Chapter 29
    Chapter 29

    School: Virginia Tech

    Course: Foundations Of Physics

  • 5 Pages Chapter 28
    Chapter 28

    School: Virginia Tech

    Course: Foundations Of Physics

    Chapter 28 Sources of Magnetic Fields 28.1 Moving charge 28.2 Current element, RHR 28.3 Straight current carrying conductor Example: A straight wire carries a current I = 3.0 A. A particle of charge q = +6.5 x 10-6 C is moving parallel to the wire at a di

  • 7 Pages Chapter 27
    Chapter 27

    School: Virginia Tech

    Course: Foundations Of Physics

  • 5 Pages Chapter 26
    Chapter 26

    School: Virginia Tech

    Course: Foundations Of Physics

  • 4 Pages Chapter 25
    Chapter 25

    School: Virginia Tech

    Course: Foundations Of Physics

  • 5 Pages Chapter 24
    Chapter 24

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    Course: Foundations Of Physics

  • 5 Pages Chapter 23
    Chapter 23

    School: Virginia Tech

    Course: Foundations Of Physics

  • 1 Page Cheat sheet2-1
    Cheat Sheet2-1

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    Course: Physics

  • 2 Pages Cheat sheet
    Cheat Sheet

    School: Virginia Tech

    Course: Physics

    Potential Energy of a pair of charges final-initial, Ratio of Bob to Sally = p= n= = 1kWh = 1 kW*3600s C2/n m2 = Volume of a sphere = Volume of a cylinder = m= k= m/s olu e (volume Current Density concentration charges ( () # free electrons = Potential en

  • 2 Pages Best cheat sheet2
    Best Cheat Sheet2

    School: Virginia Tech

    Course: Physics

    15 mechanical waves 16 sound and hearing 21 Electric charge and electric field Coulomb's law where and Electric Field wave power Electric dipoles Standing sound waves inverse square law for intensity 22 Gauss's Law Standing waves on a string node at close

  • 4 Pages lecture 3
    Lecture 3

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 2 Pages lecture 2
    Lecture 2

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 2 Pages lecture 1
    Lecture 1

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 7 Pages chapter 16
    Chapter 16

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 2 Pages Test 1 Formula Sheet
    Test 1 Formula Sheet

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 4 Pages Chapter+24+worksheet
    Chapter+24+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Produced with a Trial Version of PDF Annotator - www.PDFAnnotator.com Chapter 24 Capacitors & Dielectrics 23.1 Capacitors, capacitance, capacitance calculations Produced with a Trial Version of PDF Annotator - www.PDFAnnotator.com Example: What is the cap

  • 5 Pages Chapter+23+worksheet
    Chapter+23+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Chapter 23 Electric Potential 23.1 Electric Potential Energy Potential energy due to several point charges Example: An alpha particle and an electron are initially separated by a distance of 10-10 m. An alpha particle is a helium nucleus having two proton

  • 4 Pages Chapter+22+worksheet
    Chapter+22+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Chapter 22 Gausss Law 22.1-2 Electric Flux Calculation: Uniform Electric Field Non-uniform Electric Field 22.3-4 Gausss Law General Form Line Charge (like a wire) Sphere of charge 22.5 Conductors Electrostatic equilibrium. Field inside a conductor. Field

  • 4 Pages Chapter+21+worksheet
    Chapter+21+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Chapter 21 Electric Charge and Electric Field 21.1-2 Electric Charge Types of charge. The law of conservation of charge. Elementary charge. The coulomb. Conductor. Insulator. 21.3 Coulombs Law The force that point charges exert on each other 21.4-6 The El

  • 6 Pages Chapter+16+worksheet
    Chapter+16+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Chapter 16 - Sound Waves 16.1 Sound waves Sound waves as pressure fluctuations, pressure amplitude 16.2 Speed of sound 16.3 Intensity, decibel scale 16.4-5 Standing sound waves Pressure and displacement nodes and antinodes Open pipe conditions Stopped pip

  • 6 Pages Chapter+15+worksheet
    Chapter+15+worksheet

    School: Virginia Tech

    Course: Foundations Of Physics II

    Chapter 15 - Mechanical Waves 15.1 Properties of mechanical waves, transverse waves, longitudinal waves 15.2-3 Periodic waves, wave relations, wave function, sinusoidal wave, amplitude, phase, particle velocity, particle acceleration Example: A sinusoidal

  • 4 Pages lecture 4
    Lecture 4

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 4 Pages lecture 5
    Lecture 5

    School: Virginia Tech

    Course: Foundations Of Physics II

  • 7 Pages Midterm 3 typ A solutions
    Midterm 3 Typ A Solutions

    School: Virginia Tech

    Course: Physics

  • 6 Pages PracticeTestFinal-1
    PracticeTestFinal-1

    School: Virginia Tech

    Course: Physics

    Practice Test With Answers 1. Springs attached: The position as function of time of 1.5 kg mass on a spring is given by , where x is in meters and t is in seconds. a. What is the force constant of the spring? 1.5*(4.16)2 N/m b. What is the Time Period? s

  • 7 Pages Midterm 2
    Midterm 2

    School: Virginia Tech

    Course: Physics

  • 7 Pages Midterm 1 socultions
    Midterm 1 Socultions

    School: Virginia Tech

    Course: Physics

  • 6 Pages Midterm 2 solutions
    Midterm 2 Solutions

    School: Virginia Tech

    Course: Physics

  • 4 Pages test material
    Test Material

    School: Virginia Tech

    Course: Foundations Of Physics II

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