CS 110 Berkeley

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Berkeley CS 110 documents:

  • Berkeley CS 110 Fall 2008
    Solutions to Homework 1. Math 110, Fall 2006. Prob 1.2.1. (a) True this is axiom (VS 3). (b) False we proved the zero vector is unique. (c) False: take x to be the zero vector, and take any scalars a and b. (d) False: take a to be the zero scalar a
  • Berkeley CS 110 Fall 2008
    Solutions to Homework 1. Math 110, Fall 2006. Prob 1.2.1. (a) True this is axiom (VS 3). (b) False we proved the zero vector is unique. (c) False: take x to be the zero vector, and take any scalars a and b. (d) False: take a to be the zero scalar a
  • Berkeley CS 110 Fall 2008
  • Berkeley CS 110 Fall 2008
    Solutions to Homework 2. Math 110, Fall 2006. Prob 1.4.4. (a) Yes, since the linear system a+b 2a + 3b -a a-b has a solution a = 3, b = -2. (b) No, the corresponding linear system has no solution. (c) Yes, the corresponding linear system has a soluti
  • Berkeley CS 110 Fall 2008
  • Berkeley CS 110 Fall 2008
    Solutions to Homework 3. Math 110, Fall 2006. Prob 2.1.10. By the linearity of T , we use the fact (1, 0) + 3(1, 1) = (2, 3) to obtain T (2, 3) = T (1, 0) + 3T (1, 1) = (1, 4) + 3(2, 5) = (5, 11). The map T is 1 1 as we see that T (a(1, 0) + b(1, 1)
  • Berkeley CS 110 Fall 2008
  • Berkeley CS 110 Fall 2008
    Solutions to Homework 4. Math 110, Fall 2006. Prob 2.3.13. Let A = [aij ]. Then At = [aji ], and n n tr(A) = i=1 aii = j=1 ajj = tr(At ). The elements of A = [aij ], B = [bij ], AB = [cij ] and BA = [dij ] are connected by the formulas n n cij =
  • Berkeley CS 110 Fall 2008