STAT 611 Texas A&M

Statistics 611 Theory of Statistics II (Practical Mathematical Statistics) Section 602, Spring Term, 2007 This course introduces the issues, approaches and mathematical tools for developing statistical methodology, primarily univariate. In particula

STATISTICS 611 Spring 2000 INSTRUCTOR: OFFICE: PHONE #: E-MAIL: WEB SITE: OFFICE HOURS: TEXT: Dr. Thomas E. Wehrly 416B Blocker Building 845-3151 twehrly@stat.tamu.edu http:/stat.tamu.edu/twehrly/611/611.html 10-11 MWF, or by appointment Statistical

Statistics 611 T. E. Wehrly All the problems are from Casella and Berger. 1. Consider the situation described in Problem 8.5, page 386. a. Suppose = 1. Obtain the LRT of H0 : = 1 versus H1 : = 1. Express the rejection region in terms of the sucien

Statistics 611 T. E. Wehrly Final Exam May 6, 1997 Instructions: Answer all the following questions. Each part of each question is worth 10 points. This exam is closed book. You may use the table of distributions from your book. Be sure to justify

MSE in estimating exp(-theta), n=10 CRLB Var(MVUE) MSE(MLE) MSE*n 0.0 0 0.05 0.10 0.15 1 2 theta 3 4 MSE in estimating exp(-theta), n=10 0.18 MSE*n 0.12 0.14 0.16 CRLB Var(MVUE) MSE(MLE) 0.4 0.6 0.8 theta 1.0 1.2

Hint for 7.41 E(Y 4 ) = E[Y 3 (Y + )] = E[Y 3 (Y )] + E(Y 3 ) Use Steins Lemma for the rst term and Example 4.7.5 for the second. 1

Statistics 611 T. E. Wehrly Test 2 April 9, 1997 Instructions: Answer all the following questions. This exam is closed book. You may use the table of distributions from your book. Be sure to justify all your answers (including yes or no questions).

Statistics 611 T. E. Wehrly All the problems are from Casella and Berger. Homework 8 Due April 10, 2000 1. Consider the situation described in Problem 8.5, page 386. Suppose = 1. (a.) Obtain the Wald test of H0 : = 1 versus H1 : = 1. Find the re

STAT 611-602 May 26, 2004 Solution to Final Exam 1. The sample mean X is unbiased and hence M SE(X) = 2 /n. We have ^ E() = and hence ^ M SE() = n + m , n+m 2 n + m ^ + Var() - n+m m2 ( - )2 n 2 + m 2 = + (n + m)2 (n + m)2 m2 ( - )2 2 = . + (n +