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UC Davis - CHEM 107B
  • 2 Pages ps6
    Ps6

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 6 Due: March 11, 2011 1. Problems 21-10, 21-11, and 21-12, 22-1, and 22-2 in Simon and McQuarries Physical Chemistry. 2. Salt water is plentiful on earth; natural supplies of fresh water, on the other hand, are dwindling while mankind

  • 200 Pages Lecture+11+-+Quantum+mechanics
    Lecture+11+-+Quantum+mechanics

    School: UC Davis

    Course: Physical Chemistry

    Schrdinger Equation for Hydrogen Atom H-atom has one electron and one proton. Proton fixed and electron can move in three dimensions (x, y, z). Potential energy (V) given by coulombic interaction: H n ( x) = En n ( x) 2 Z 2e 2 V = 4 0 r + r 2 h d n (x)

  • 3 Pages ps9
    Ps9

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 9 Due: April 8, 2011 1. Problems 23-27, 23-28, and 23-36 in McQuarrie & Simons Physical Chemistry textbook. 2. At xed pressure p, a perfectly ideal solution of two miscible liquids is dened by the familiar dependence of chemical poten

  • 3 Pages PS8Solutions
    PS8Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 8 Solutions Total: 50 points 1. See MQS Solutions Manual. 2. (i) P (g) (0) (0) = Keq (g) = exp P (g) R (g) R (g) P ( ) (0) (0) = Keq ( ) = exp P ( ) R ( ) R ( ) (ii) R (g) (0) (0) = R = exp R (g) R ( ) R ( ) P (g) (0) (0) =

  • 2 Pages ps8
    Ps8

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 8 Due: April 1, 2011 1. Problems 26-17 and 26-39 in McQuarrie & Simons Physical Chemistry textbook. 2. In class we have examined separately the implications of standard state chemical potentials for partitioning of a solute between di

  • 3 Pages PS7Solutions
    PS7Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 7 Solutions Total: 50 points 1. (i) See handout on bspace. (ii) (0) is the change in free energy associated with moving one solute from octanol to water in the standard state. (iii) dG = SdT + V dp + i i dNi The Maxwell rel

  • 3 Pages PS6Solutions
    PS6Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 6 Solutions Total: 50 points 1. (10 points) See MQS Solutions Manual. 2. (i) (3 points) When the membrane is pushed through the solution, the number of microscopic states available to the ions decreases. This means the entr

  • 2 Pages PS5Solutions
    PS5Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 5 Solutions Total: 50 points 1. (20 points) See MQS Solutions Manual. 2. (i) (5 points) W (V1 , V2 ) = V1 N1 V2 N2 (stu independent of V ) Neglecting volume-independent terms, S = kB ln W = kB ln V1 N1 V2 N2 = kB ln V1 N1 +

  • 2 Pages ps5
    Ps5

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 5 Due: February 25, 2011 1. Problems 19-7, 19-13, 19-14, and 19-34 in Simon and McQuarries Physical Chemistry. 2. We have argued several times that, in a dilute system, the number of ways to arrange N identical molecules in a large vo

  • 4 Pages PS4Solutions
    PS4Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 4 Solutions Total: 50 points 1. (5 points) See MQS Solutions Manual. 2. (i) (4 points) The number of possible locations for a single particle is V /3 , where is the thermal deBroglie wavelength, = h/ 2mkB T . q= V 3 Because

  • 5 Pages PS3Solutions
    PS3Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 3 Solutions Total: 50 points 1. (11 points) See MQS Solutions Manual. The graph of fJ /f0 has a local maximum as a result of degeneracy, encoded in the prefactor (2J + 1). Without the entropic contribution to the relative p

  • 2 Pages ps3
    Ps3

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 3 Due: February 11, 2011 1. Problems 17-33, 17-37, 17-38, 17-39, I-1, I-2, I-3, I-13, 27-2, 27-3, 27-4, and 27-5 in McQuarrie & Simons Physical Chemistry textbook. For problem 17-37 explain in terms of energy and entropy why fJ /f0 ha

  • 4 Pages PS2Solutions
    PS2Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 2 Solutions Total: 50 points 1. (17-8) (3 points) See MQS Solutions Manual. (4 points) Bz No = exp Nw kb T Solving this for Bz , kB T ln Bz = No Nw If we want half as many spins opposed to the eld as aligned with it (Nw

  • 3 Pages ps2
    Ps2

    School: UC Davis

    Course: Physical Chemistry

    Chem 120B Problem Set 2 Due: February 4, 2011 1. Problems 17-8 and 17-43 in McQuarrie & Simons Physical Chemistry textbook. For problem 17-8, note that the two spin states of a proton in a magnetic eld have energies Bz /2. Calculate the eld strength Bz fo

  • 5 Pages PS1Solutions
    PS1Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 1 Solutions Total: 50 points 1. (i) (2 points) (A)2 = (A A )2 = A2 + A (A) 2 2 =A+A 2 2A A 2 2A A Recall from lecture that, because averages are not uctuating quantities, average of a sum is equal to the sum of the averag

  • 10 Pages chem120B-sp08-mt2-Geissler-soln
    Chem120B-sp08-mt2-Geissler-soln

    School: UC Davis

    Course: Physical Chemistry

  • 8 Pages CHEM 120B - Fall 2006 - Geissler - Midterm 2 (solution)
    CHEM 120B - Fall 2006 - Geissler - Midterm 2 (solution)

    School: UC Davis

    Course: Physical Chemistry

    =396 2%1) ,)6) 2SZIQFIV 'LIQ & 1MHXIVQ ERH 9WIJYP *SVQYPEW *MVWX PE[ SJ XLIVQSH]REQMGW H) ! H [ H U 7IGSRH PE[ SJ XLIVQSH]REQMGW HU 8 H7 +MFFW IRXVST] 7! O& < T PR T 'SQQSR XLIVQSH]REQMG JYRGXMSRW ) ! 87 %!) T: , ! ) T: 8 7 +!) 8 7 T: XMEP GLERKIW MR XL

  • 9 Pages CHEM 120B - Spring 2010 - Geissler - Midterm 1 (solution)
    CHEM 120B - Spring 2010 - Geissler - Midterm 1 (solution)

    School: UC Davis

    Course: Physical Chemistry

    KEY YOUR N AME H ERE Fbbruary 2 4,2010 Chem 1 208 M idterm # 1 ana Usefut Formdas: L!:ftjons Inverset emPerature: 1 k" T ' k B: 1.38x t0-23 J /K Boltzmann d istribution: g-98" P( u) : Partition a -BE" Equilibrium averages: : (E) - ( ffi," , ( 58\:( W),u,'

  • 14 Pages practicefinal
    Practicefinal

    School: UC Davis

    Course: Physical Chemistry

    YOUR NAME HERE May 11, 2010 Chem 120B Final Examination Denitions and Useful Formulas: E = T S pV + i i dNi qtrans = V /3 = h/ 2mkB T A = E TS G = E T S + pV # ways to distribute N indistinguishable objects among M places = M !/[N !(M N )!] H = E + pV 1/

  • 14 Pages Spring 2008 Final
    Spring 2008 Final

    School: UC Davis

    Course: Physical Chemistry

    YOUR NAME HERE May 17, 2008 Chem 120B Final Examination Denitions and Useful Formulas: E = T S pV + i i dNi A = E TS Q = q N /N ! qtrans = V /3 = h/ 2mkB T G = E T S + pV H = E + pV 1/T = (S/E )V,N # ways to distribute N indistinguishable objects among M

  • 1 Page Readings
    Readings

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B S11 Suggested Readings Week 1 MQS Chapter 17 (The Boltzmann Factor and Partition Functions) MQS Math Chapter H (Partial Dierentiation) 1

  • 3 Pages PS11Solutions
    PS11Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 11 Solutions 1. (i) The transition state theory rate constant is kB T Q E vib e h QA vib TST kAB = The total vibrational partition function is the product of the qvib s of all the modes. Ignoring quantum mechanical eects,

  • 3 Pages ps11
    Ps11

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 11 Due: April 29, 2011 1. Expressed in terms of partition functions, the transition state theory estimate of a rst order rate constant reads kB T Q TST kAB = h QA This expression can be evaluated in detail if the potential energy U is

  • 3 Pages PS10Solutions
    PS10Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 10 Solutions Total: 50 points 1. (i) The Debye screening length is given by = 4 I 2 j Nj qj /V and q = z/ 4 0 . For 0.1 molar NaCl, where I is the ionic strength, I= I= e 4 2 0.1 NA + 0 = 0.2 NA e 4 2 0.1 NA 0 e2 4 0 = 2

  • 2 Pages ps10
    Ps10

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Problem Set 10 Due: April 22, 2011 1. (i) 0.1 moles of NaCl are dissolved in 1 L of water at room temperature. Compute the Debye screening length of the solution. Compare your result with the following lengths: (i) (ii) (iii) 1/3 w 1/3 I e2 /( 40

  • 4 Pages PS9Solutions
    PS9Solutions

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 120B SP11 Problem Set 9 Solutions Total: 50 points 1. See MQS Solutions Manual. 2. (i) Use the ideal gas law to write the mole fraction in terms of partial pressures. pj = Nj kB T V p = p1 + p2 = N1 + N2 kB T V Nj pj = = xj p N1 + N2 (v) Equate

  • 3 Pages Fluctuations Notes
    Fluctuations Notes

    School: UC Davis

    Course: Physical Chemistry

    From the discussion of fluctuations in the number of particles on the left side of the box, or coin flips, we found in lecture: ("N L ) 2 = 2 2 NL # NL N NL = $h i i=1 N ("N L ) 2 = N $ hi i=1 ! N j =1 N hi i=1 $h j j =1 At this point, we used the statist

  • 2 Pages extra credit
    Extra Credit

    School: UC Davis

    Course: Physical Chemistry

    Chem120B Extra Credit Assignment Due: May 6, 2011 For this assignment you will use computer simulations to study the properties of a model uid. The model represents molecules as hard disks in two dimensions. The particles are hard in the sense that they a

  • 13 Pages ElectrostaticsNotes
    ElectrostaticsNotes

    School: UC Davis

    Course: Physical Chemistry

    Electrostatics and the thermodynamics of solutions Phillip Geissler March 19, 2010 We come together Cuz opposites attract. Paula Abdul Opposite charges attract one another; like charges repel. This simple and familiar fact plays a central role in determin

  • 1 Page DensityandMoleFractionNotes
    DensityandMoleFractionNotes

    School: UC Davis

    Course: Physical Chemistry

    Water Octanol Here we are looking at a single solute in a (very small) fixed volume, a, of octanol or water. Because the water is more dense by a fa

  • 10 Pages CHEM 120B - Spring 2010 - Geissler - Midterm 2 (solution)
    CHEM 120B - Spring 2010 - Geissler - Midterm 2 (solution)

    School: UC Davis

    Course: Physical Chemistry

    KEY YOUR N AME H ERE April 7, 20L0 Chem 1 208 M idterm # 2 Definitions and Useful Fqrmulas: InversetemPerature: k e:1'38x ro-23JfK P:#' First l aw o f t hermodYnamics: + dE=Td,S-pd'V t F fiNr, Entropy a nd t he s econd l aw: : l .g: k enw, s : - keLrr4itn

  • 2 Pages PS1
    PS1

    School: UC Davis

    Course: Physical Chemistry

    Chem 120B Problem Set 1 Due: January 28, 2011 1. (i) Show that the mean square uctuation in any quantity A can be written in terms of its mean and mean square values, (A)2 = A2 A 2 . (Here, as usual, the uctuation in A is dened as A = A A .) (ii) Generali

  • 8 Pages PracticeMidtermSolutions
    PracticeMidtermSolutions

    School: UC Davis

    Course: Physical Chemistry

  • 9 Pages PracticeMidterm2Solutions
    PracticeMidterm2Solutions

    School: UC Davis

    Course: Physical Chemistry

  • 200 Pages Lecture 15 - Quantum mechanics
    Lecture 15 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Heisenberg Uncertainty Principle h = mv x p = h Observing the electron with light disturbs its movement between slit and detector. Position of Baseball vs. Electron = p = p Schrodinger Wave Equation Bohr theory of H-atom fails to explain emission spectr

  • 200 Pages Lecture 14 - Quantum mechanics
    Lecture 14 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Bohr Energy Levels 1 Ze 2 E = - me v 2 = - 2 8 0 r Ze 2 v= 2nh 0 r r Angular momentum ( p r ) of the electron (mevr) is quantized: h me vr = n = nh 2 with n = 1, 2, 3, . e- + 1 Bohr energy levels of hydrogen atom quantized as: 2 3 1 me Z 2 e 4 1 E n = - m

  • 200 Pages Lecture 13 - Quantum mechanics
    Lecture 13 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Wave Mechanics Sinusoidal wave: A = A0 sin( x + ) A0 = amplitude of wave = phase angle x = distance = t Velocity of wave (v): v = = wavelength (length of cycle in m) = frequency (# of cycles per sec or Hz) x = distance (radians or degrees) Wave Interfer

  • 200 Pages Lecture 12 - Quantum mechanics
    Lecture 12 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Colorimetric Enzyme Assay colorless max = 400 nm Beer's Law: A = (conc)(pathlength) [ P ](t ) = [ S ]0 - [ S ](t ) = Vmax t A = log (I0/I) I0 I [ S ](t ) = -Vmax t + [ S ]0 Enzyme Inhibition Negative feedback inhibition Reversible vs Irreversible Inhibiti

  • 200 Pages Lecture 11- Enzyme Kinetics
    Lecture 11- Enzyme Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Michaelis-Menten Kinetics E+S k1 k-1 ES k2 E+P Initial rates method: Initial rate (v0) is slope of tangent at time zero. Measure initial rate at several substrate concentrations. d [P ] v0 = = k2 [ES ] dt 0 Vmax = k 2 [E ]0 [E]0 = [ES] + [E] kcat = k2 d

  • 24 Pages Lecture 10- Enzyme Kinetics
    Lecture 10- Enzyme Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 1 Friday, Jan 28, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "L") 176 Everson (last name begins with "M" - "Z") Exam covers Chapters 2.6 2.9 and all of 9 Closed Book and Closed Notes No electronic devices except calculator Pract

  • 200 Pages Lecture 9- Enzyme Kinetics
    Lecture 9- Enzyme Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Comparing Reaction Rate Theories Arrhenius Theory: k = Ae - EA RT EA - RT Collision Theory: Z AB 8k BT 2 = d AB = 1011 M-1 s-1 [ A][ B] Z AB k=P e [ A][ B] Transition State Theory: k BT k= e h S o R e H o - RT Ca2+(aq) + SO42-(aq) [Ca2+-SO42-] CaSO4(s) St

  • 200 Pages Lecture 8- Chemical Kinetics
    Lecture 8- Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 1 Friday, Jan 28, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "L") 176 Everson (last name begins with "M" - "Z") Exam covers Chapters 2.6 2.9, all of 9, and 10.1 10.3 Closed Book and Closed Notes No electronic devices except calc

  • 200 Pages Lecture 7 - Chemical Kinetics
    Lecture 7 - Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 1 Friday, Jan 28, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "L") 176 Everson (last name begins with "M" - "Z") Exam covers Chapters 2.6 2.9, all of 9, and 10.1 10.3 Closed Book and Closed Notes No electronic devices except calc

  • 200 Pages Lecture 6 - Chemical Kinetics
    Lecture 6 - Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Reaction Mechanism NO2(g) + CO(g) NO(g) + CO2(g) rate = k[NO2]2 Overall rxn Step (1) NO2(g) + NO2(g) NO3(g) + NO(g) Step (2) NO3(g) + CO(g) NO2(g) + CO2(g) NO2(g) + CO(g) NO(g) + CO2(g) rate = k1[NO2]2 rate = k2[NO3][CO] rate = k[NO2]2 slow fast AIP slow

  • 200 Pages Lecture 5 - Chemical Kinetics
    Lecture 5 - Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Problem Set #1: due at end of class on Fri Jan 14th. TA Office Hours: Rm 1488 Chem Annex, Thur Jan 13th. First-order Rise and Decay N 2O2 ( g ) 2NO ( g ) Concentration [N 2O2 ](t ) = [N 2O2 ]0 e rate = + [ NO ] 0 - kt 2.0 1.6 1.2 0.8 0.4 0.0 0 10 NO(t) 1

  • 200 Pages Lecture 4 - Chemical Kinetics
    Lecture 4 - Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Reactant and Product vs Time What is Chemical Kinetics? Kinetics investigates the rate of chemical reactions and how rate depends on temperature, concentration and catalysts. Concentration RP Reactant Product [P](t) [R ] [P] = rate = - t t Why Study Chem

  • 22 Pages Lecture 3 - Chemical Kinetics
    Lecture 3 - Chemical Kinetics

    School: UC Davis

    Course: Physical Chemistry

    Rate Depends on Collision Frequency (Z11) and Boltzmann Factor (e-Ea/RT) A + B Product Ea P Rate = (# of collisions per second) X (fraction collisions having E > Ea) 2 2 N d c Z11 = 2 V 2 exp(-Ea/RT) X cfw_ exp(-0/RT) = 108 M/s Rate = cfw_ Z11 (108 M s-

  • 200 Pages Lecture 2 - Kinetic Theory of Gases
    Lecture 2 - Kinetic Theory Of Gases

    School: UC Davis

    Course: Physical Chemistry

    Chem 107B TA Office Hours Chem Annex (Rm 1480A) Libo Li (lili@ucdavis.edu ) Benjamin Samudio (bmsamudio@ucdavis.edu ) Ying Liu (yixliu@ucdavis.edu ) Peiran Chen (prchen@ucdavis.edu ) Mon 9 noon Tu 9 noon Wed 9 noon Th 9 noon Final Exam: Fri March 18th at

  • 200 Pages Lecture 16 - Quantum mechanics
    Lecture 16 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Particle in a One-dimensional Box Translational motion (V=0) V 0 e- h 2 d 2 - 2 + V = E 2 8 m dx V =0 V = L 0< x<L x 0 or x L 0 x Particle located inside the box if V = 0: h 2 d 2 - 2 + 0 * = E 2 8 m dx Quantum Mechanical Particle in a Box n= 2 n sin x L

  • 200 Pages Lecture 17 - Quantum mechanics
    Lecture 17 - Quantum Mechanics

    School: UC Davis

    Course: Physical Chemistry

    Problem Set 2 due at end of class on Fri Feb 18th. Midterm 1 key on website. Schrdinger Equation for Hydrogen Atom H-atom has one electron and one proton. Proton fixed and electron can move in three dimensions (x, y, z). Potential energy (V) given by cou

  • 10 Pages PracticeMidterm2
    PracticeMidterm2

    School: UC Davis

    Course: Physical Chemistry

    YOUR NAME HERE April 7, 2010 Chem 120B Midterm #2 Denitions and Useful Formulas: Inverse temperature: 1 , kB T First law of thermodynamics: kB = 1.38 1023 J/K = dE = T dS pdV + i dNi i Entropy and the second law: S = kB ln W, S = kB P ( ) ln P ( ), dS = (

  • 14 Pages PracticeFinalSolutions
    PracticeFinalSolutions

    School: UC Davis

    Course: Physical Chemistry

  • 9 Pages chem120B-sp08-mt1-Geissler-soln
    Chem120B-sp08-mt1-Geissler-soln

    School: UC Davis

    Course: Physical Chemistry

  • 3 Pages 107B Syllabus
    107B Syllabus

    School: UC Davis

    Course: Physical Chemistry

    Chemistry 107B: Physical Chemistry for the Life Sciences (CRN: 16159) Summer 2011 Class webpage: https:/smartsite.ucdavis.edu and follow the links to CHE 107B. Lecturer: Prof. James B. Ames Lecture Times: TWR 10:00 11:40 A.M. at 179 Chemistry Office Hours

  • 21 Pages Lecture 27 - Spectroscopy
    Lecture 27 - Spectroscopy

    School: UC Davis

    Course: Physical Chemistry

    Final Exam Fri, Mar 18, 2011 10:30 12:30 pm 198 Young (last name begins with "A" - "M") 176 Everson (last name begins with "N" - "Z") 40-50% Chapters 2.6 2.9, 9, 10.1 10.5, 11, 12.1 12.7, 13.1 13.4, 14.1, 14.3 5 Closed Book and Closed Notes No electronic

  • 200 Pages Lecture 26 - Spectroscopy
    Lecture 26 - Spectroscopy

    School: UC Davis

    Course: Physical Chemistry

    Final Exam Fri, Mar 18, 2011 10:30 12:30 pm 198 Young (last name begins with "A" - "M") 176 Everson (last name begins with "N" - "Z") Chapters 2.6 2.9, 9, 10.1 10.5, 11, 12.1 12.7, 13.1 13.4, 14.1, 14.3 ? Closed Book and Closed Notes No electronic devices

  • 200 Pages Lecture 25 - Spectroscopy
    Lecture 25 - Spectroscopy

    School: UC Davis

    Course: Physical Chemistry

    Chapter 14: Spectroscopy Homework: 2, 4, 6, 8, 10, 12, 24, 26, 28, 30, 32, 34, 36, 38, 39, 42, 47, 60, 67, 68, 74, 76, 80, 82, 84 * h Spectral Line Width h Et 4 * Gas phase Solution h E 4t 1 t = = Z1 Z1 108 s-1 (gas) = 10 ns Z1 1012 s-1 (soln) = 1 ps Exci

  • 200 Pages Lecture 24 - Spectroscopy
    Lecture 24 - Spectroscopy

    School: UC Davis

    Course: Physical Chemistry

    Hydrophobic Interactions CH4 (g) + H2O(l) CH4 - H2O (aq) G > 0 & S < 0 Oil and water don't mix, called the hydrophobic effect. Methane Hydrate CH4 - non-polar solvent CH4 - H2O G > 0 Entropically unfavorable to dissolve non-polar molecule in H2O. Non-pola

  • 200 Pages Lecture 23 - Intermolecular forces
    Lecture 23 - Intermolecular Forces

    School: UC Davis

    Course: Physical Chemistry

    Molecular Interactions vs "Thermal Energy" Thermal energy (heat) defined as: kBT (at room temperature) = 2.4 kJ/mole Solid or fluid Gas Intermolecular Interactions smaller than kBT are broken by kBT. (Gases) Intermolecular interactions larger than kBT are

  • 21 Pages Lecture 22 - Intermolecular forces
    Lecture 22 - Intermolecular Forces

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 2 Wed, Mar 2, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "M") 176 Everson (last name begins with "N" - "Z") Exam covers Chapters 10.1 10.5, all of 11, and 12.1 12.7. Closed Book and Closed Notes No electronic devices except calc

  • 200 Pages Lecture 21 - Chemical bond
    Lecture 21 - Chemical Bond

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 2 Wed, Mar 2, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "M") 176 Everson (last name begins with "N" - "Z") Exam covers Chapters 10.1 10.5, 11, and 12. Closed Book and Closed Notes No electronic devices except calculator Practic

  • 200 Pages Lecture 20 - Chemical bond
    Lecture 20 - Chemical Bond

    School: UC Davis

    Course: Physical Chemistry

    Midterm Exam 2 Wed, Mar 2, 2011 1:10 2:00 pm 198 Young (last name begins with "A" - "M") 176 Everson (last name begins with "N" - "Z") Exam covers Chapters 10.1 10.5, 11, and 12. Closed Book and Closed Notes No electronic devices except calculator Practic

  • 200 Pages Lecture 19 - Chemical bond
    Lecture 19 - Chemical Bond

    School: UC Davis

    Course: Physical Chemistry

    Hybrid Atomic Orbitals sp3 sp2 sp Covalent Bond Geometry Why is water bent and CO2 linear? H O C O H O Water: Oxygen has an electron configuration of 1s2 2s2 2p4 (6 valence e-) Oxygen is sp3 hybridized (109 bond angles). Two sp3 orbitals form single bonds

  • 200 Pages Lecture 18 - Chemical bond
    Lecture 18 - Chemical Bond

    School: UC Davis

    Course: Physical Chemistry

    Radial Electron Distribution in H-atom Radial Wavefunction Probability = R(r ) 2 dr = 4 r 2 R(r ) 2 Density e -r e -r 2 Multi-Electron Atoms Electron repulsion Electron Shielding ^ H He = E He He e2 4 0 r12 Effective nuclear charge: Zeff = Z - He ( r1

  • 21 Pages Lecture 1 - Kinetic Theory of Gases
    Lecture 1 - Kinetic Theory Of Gases

    School: UC Davis

    Course: Physical Chemistry

    Thermodynamics vs Kinetics Chemical Reaction or Biological Process: f AB k krev Keq = [B]/[A] = kf/krev kf = forward rate constant (Thermo, 107A) (Kinetics, 107B) Thermo predicts how far a rxn proceeds (Keq). State function depends on difference between f

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