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Lawanda Henderson 32710
School: AIU Online
Name:Lawanda Henderson the graph to enlarge it if it will make it easier for you to read. A MTH133 Unit 1 & 2 Individual Project A Name: 1) Thefollowinggraphshowsthedepreciationforthecorporateairplanefrom2006to2009. Theplanewaspurchasednewin2006;therefore

MATH133_U4_answer
School: AIU Online
Course: College Algebra
Student Answer Form Unit 4 1. a. j(x)=(x+1)^2+3 y=(x+1)^2+3 No xintercept Y=4 Y = (1)^2 + 3 Y= (1) + 3 Y=4 The graph of f(x) shifted 3 units to the left. b. f(x)=x^2 h (x) = x^2 2 x= sqrt2 sqrt2 (0) y = 2 x^2 2 = 0 x^2= 2 x = sqrt2 x= sqrt2, sqrt2 y =

MATH133_U3_answer
School: AIU Online
Student Answer Form Unit 3 1. a. X= X= b. =27 2x2=3x36+9 2x2=3x+6 5x2=6 5x+2=+2 X= c. 11*4(x+1) = 8x+12= 8x+ 12 3x =3 11x= 9 X= d. X2 x 2 = 0 X2=0 x=2 2. a. C (60) = C= C = 26. 6666667 C = 27 b. 5 (x) = 1.5x =  5x^2 + 500v 5x^2  498.5x = 0 X

MATH133_unit 1 _ DB Assignment
School: AIU Online
Course: College Algebra
MATH133 March 23, 2011 The car of my dreams at the present time is a dark Plum, 2011 Dodge Challenger. I found a list of pricing for my dream car at Motor Trends website for $25, 495.00. I went to my personal banking website, Texell Federal Credit Union,

MATH133_U3IP2
School: AIU Online
Course: College Algebra
MATH133 Unit 3 Individual Project 2 1) Solve algebraically. Trial and error is not an appropriate method of solution. You must show all your work. Learn how to type math roots and fractions by clicking on the link in the assignment list. Alternately, you

MATH133_U5_answer
School: AIU Online
Student Answer Form Unit 5 IP_2 April 22, 2011 (1.) a. e^(0.05t)=1600 Answer: t=147.556 Show your work: ln(e^(0.05t)=ln(1600) 0.05t=ln(1600) (0.05t)/(0.05)=(ln(1600)/(0.05) t=(ln(1600)/(0.05) t=20ln(1600) t=147.556 b. ln(4x)=3 Answer: x= 5.0214 Show your

MATH133_U2IP2
School: AIU Online
Course: College Algebra
How to graph in MS Excel and copy your graph to MS Word (Word 2007) An example of a line and parabola are included. You should have at least 3 points ready to enter into MS Excel. Suppose I want to graph y=3x2. Because this will be a line, I just need to

MATH133_U5IP2
School: AIU Online
Course: College Algebra
MATH133 Unit 5 Individual Project 2 1) Solve: a) e.05t = 1600 Answer: Show your work in this space: b) ln[ln(4x)] = 3 Answer: Show your work in this space: c) log2 86x 5 Answer: Show your work in this space: d) 4 + 5ex = 9 Answer: Show your work in this

MATH133_U1IP2
School: AIU Online
Course: College Algebra
Name: _ MATH133 Unit 1 Individual Project 2 A 1) The following graph shows the depreciation for the corporate airplane from 2006 to 2009. The plane was purchased new in 2006; therefore, x = 0 represents the year 2006. X axis (horizontal) = years starting

MATH133_U3_Answerform
School: AIU Online
Student Answer and Work Form Unit 3 Ver. C Student Name: Linda I. Delgado 1a. Answer: T = 8_ 1a. Key work steps 1b. Answer: X = 32_ 1b. Key work steps 1c. Answer: X = 5/11_ 1c. Key work steps 2a. Answer: X = 1_ 2a. Key work steps 2b. Answer: No Solution_

MATH133 IP
School: AIU Online
1 Linda Delgado March 28,2013 Math 33U1IPA 1a. X Y .5 240,000 1 228,000 1.5 222,000 2 216,000 2.5 210,000 3 204,000 3.5 198,000 1b. M = 12,000 1c Y = 12,000 + 24,000 1d. $162,000 2a. 80 = 2L + 2(L5) 2b. L = 22.5 W = 17.5 3a. OPT 1: C = 225 + 10X OPT 2

Unit 2_DB MATH133
School: AIU Online
Unit 2 DB Assignment April 1, 2011 The total length of all three walls that John can afford is 66 feet. What is the formula for the area of the garage? A= L * W Choose two dimensions to plug into your formula. P=L+W+W P=L+12+16 W= 12 and W=16 What areas r

MATH133_U2_answer
School: AIU Online
Student Answer Form Unit 2 March 25, 2011 1. a. x^2 6x 16 = 0 (x + 2) (x  8 ) = 0 x+2=0 x8=0 x=8 x = 2, 8 b. 6x^2 + 3x 18 = 0 6x^3 = 18 6x^3 = 18 (6x^3)/(6)=(18)/(6) 6x^3/6=18/6 X^3= 18/6 X^3=3 X 1.44 c. 2x^2 3x 5 = 0 D= b^2 4ac D= (3)^24 * 2* (5)

MATH133_U1_answer
School: AIU Online
Student Answer Form Unit 1 March 23, 2011 1. a. (1.0, 228,000) (2.0, 216,000) b. m=(y2y1) / (x2x1) m= (216,000228,000) / (2.01.0) m= 12,000 / 1 m= 12,000 c. Y=(12,000) * x + b (228,000)= (12,000) * (1) + b (12,000) * (1) + b = (228,000) B 240,000

Math133 U3 IP2
School: AIU Online
Linda Isabel Delgado Math 133 Unit 3 IP 03/03/2013 1. A. t = 8 B. x = 32 C. x = 5/11 2. A. or B. 3. A. B. 4. A. B. C. 1. A. B. C. 2. A. or B. 3. A. B. 4. A. B. C.