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School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Kelsi Hayden Assignment 4 15 September 2013 Probability and Distributions 4.16 This exercise examines the population distribution in the U.S. based on race/ethnicity and blood type as reported by the American Red Cross. This exercise
School: Oklahoma State
Course: Statistical Methods I
Assignment 10 Statistical Methods I Kelsi Hayden 29 October 2013 Additional Problem 1: The researcher hypothesizes that on average men are taller than women. This is the null hypothesis. The alternative hypothesis would, in turn, be that men are not talle
School: Oklahoma State
Course: Statistical Methods I
Assignment 6 Statistical Methods I Kelsi Hayden 1 October 2013 4.64 This problem examines finding probabilities for a normal random variable with mean equal to 100 and standard deviation equal to 8. a) P(y > 100) = 50% = 1 F(100) = 1 (Phi) (100-100/8) = 1
School: Oklahoma State
Course: Statistical Methods I
Kelsi Hayden Ole Forsberg STAT 4053 23 September 2013 Assignment 5 Probability and Distributions 4.38 This problem examines a situation in which police officers are observing traffic. My main concerns are making the distinction between discrete and contin
School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Assignment 12 Solutions Kelsi Hayden Additional Problem 2: (1): p-value = 0.05689 (2): p-value = 2.728e-10 (3): p-value = 0.1094/2 = 0.0547 (4): p-value = 1.116e-09/2 (5): p-value = 2.2e-16/2 Additional Problem 3: (1): p-value = 0.05
School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Assignment 13 Solutions Kelsi Hayden Additional Problem 1: a) 1505 feet. b) 4.669047 c) -0.3750745 Additional Problem 2: a) -1.247059 b) 1.016827 c) 7.232e-12 Additional Problem 3: a) Romania b) Slavakia c) 0.02 d) p-value: 0.6984 e)
School: Oklahoma State
Course: Engineering Statistics
PROBABILITY I Test 2 - review topics August 5, 2008 1. Random variables (a) Random variables - real valued functions X on the sample space S , i.e. X : S R. Cumulative distribution function is dened as: F (x) = P cfw_X x, < x < . 2. Discrete random varia
School: Oklahoma State
Course: Engineering Statistics
Some continuous and discrete distributions Table of contents I. Continuous distributions and transformation rules. A. Standard uniform distribution U [0, 1]. B. Uniform distribution U [a, b]. C. Standard normal distribution N (0, 1). D. Normal distributio
School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Kelsi Hayden Assignment 4 15 September 2013 Probability and Distributions 4.16 This exercise examines the population distribution in the U.S. based on race/ethnicity and blood type as reported by the American Red Cross. This exercise
School: Oklahoma State
Course: Statistical Methods I
Assignment 10 Statistical Methods I Kelsi Hayden 29 October 2013 Additional Problem 1: The researcher hypothesizes that on average men are taller than women. This is the null hypothesis. The alternative hypothesis would, in turn, be that men are not talle
School: Oklahoma State
Course: Statistical Methods I
Assignment 6 Statistical Methods I Kelsi Hayden 1 October 2013 4.64 This problem examines finding probabilities for a normal random variable with mean equal to 100 and standard deviation equal to 8. a) P(y > 100) = 50% = 1 F(100) = 1 (Phi) (100-100/8) = 1
School: Oklahoma State
Course: Statistical Methods I
Kelsi Hayden Ole Forsberg STAT 4053 23 September 2013 Assignment 5 Probability and Distributions 4.38 This problem examines a situation in which police officers are observing traffic. My main concerns are making the distinction between discrete and contin
School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Assignment 12 Solutions Kelsi Hayden Additional Problem 2: (1): p-value = 0.05689 (2): p-value = 2.728e-10 (3): p-value = 0.1094/2 = 0.0547 (4): p-value = 1.116e-09/2 (5): p-value = 2.2e-16/2 Additional Problem 3: (1): p-value = 0.05
School: Oklahoma State
Course: Statistical Methods I
Statistical Methods I Assignment 13 Solutions Kelsi Hayden Additional Problem 1: a) 1505 feet. b) 4.669047 c) -0.3750745 Additional Problem 2: a) -1.247059 b) 1.016827 c) 7.232e-12 Additional Problem 3: a) Romania b) Slavakia c) 0.02 d) p-value: 0.6984 e)