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MAE 320  Thermodynamics  WVU Study Resources

Homework 1
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 1 Assignment The homework is due on Wednesday, August 29, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choice (28 points) 1a) The engineering thermodynamics

Homework 2
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 2 Assignment The homework is due Monday, September 10, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) (1a). Which is an intensive propert

Homework 3 Solutions
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 3 Assignment The homework is due Friday, September 21, 2012. Each problem is worth the points indicated. Copying of the solution from the others is not acceptable. (1). Multiple choice and multianswers questions (18 points). (1a

HW6
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 6 Assignment, Spring 2013 The homework (HW #6) is due on Friday, April 5, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1)

HW3
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 3 Assignment, Spring, 2013 The homework is due on Friday, February 15, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) (1a). A rigid tank

HW7
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 7a Assignment, Spring 2013 The homework (HW 7a) is due on Monday, April 15, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (

Climate Change HW2
School: WVU
Course: Thermodynamics
One of the key environmental concerns facing scientists and engineers today is the concept of global warming. This notion involves the incremental rise in the global temperature of our planets atmosphere as a result of the greenhouse effect caused by an i

Bomb Calorimeter HW4
School: WVU
Course: Thermodynamics
7) One method that nutritionists use to measure the calorie content of food is the bomb calorimeter. A calorimeter is a device used to measure the heat of chemical reactions and heat capacity; a bomb calorimeter is a constantvolume calorimeter used to me

HW4
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment, Spring 2013 The homework (HW 4) is due on Monday, March 4, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1).

HW7b
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 7b Assignment, Spring 2013 The homework (HW 7b) is due on Monday, April 29, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. 1

HW5
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics Solution to HW 5 Assignment, Spring 2013 The homework (HW #5) is due on Friday, March 15, 2013. Each problem/section is worth the number of points indicated (for a total of 120 points). Copying of the solution from another is not ac

HW1
School: WVU
Course: Thermodynamics
MAE 320  Thermodynamics HW 1 Assignment Assigned  January 18,2012 The homework (HW 1) is due on Friday, January 25, 2012. Each problem/section is worth the number of points indicated (jar a total of 100 points). Copying of the solution from another is n

Mae320hw02sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 2 Assignment The homework is due Monday, September 9, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice question (20 points) (1a). Please circle the int

Mae320hw03sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 3 Assignment, Fall, 2013 The homework is due on Friday, September 20, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (24 points) (1a). A system conta

Mae320hw01sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 1 Assignment, Fall, 2013 The homework is due on Wednesday, August 28, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) (1a). Which one is a

DatathiefManual
School: WVU
Course: Thermodynamics
DataThief III DataThief III manual v. 1.1 Bas Tummers bas@datathief.org 20052006 by Bas Tummers Table of contents 1. A quick introduction 3 2. DataThief full description 7 2.2. Defintion of axes 7 2.2.1. Systems with three well defined points 7 2.2.2. S

Lect1415
School: WVU
Course: Thermodynamics
Application of Control Volume Energy Analysis Most thermodynamic devices consist of a series of components operating in a cycle, e.g., steam power plant Main components of the above cycle are: 1) Boiler (steam generator) heat exchanger 2) Turbine generate

Mae320hw07sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 7a Assignment, Fall 2013 This homework covers the contents from Section 71 through 76 in Chapter 7. The homework (HW 7a) is due on Wednesday, November 13, 2013. Each problem/section is worth the number of points indicated (for

Mae320hw04sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment, Fall 2013 The homework (HW 4) is due on Monday, October 7th, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1

Mae320hw05sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 5 Assignment The homework is due Monday, October 21, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choices questions (18 points) (1a). The 1st law of thermod

Hw112
School: WVU
Course: Thermodynamics
College of Engineering and Computer Science Mechanical Engineering Department Mechanical Engineering 370 Thermodynamics Fall 2010 Course Number: 14319 Instructor: Larry Caretto Unit Ten Homework Solutions, November 18, 2010 1 Steamentersanadiabaticturbine

Electric Cars HW5
School: WVU
Course: Thermodynamics
8) Electric cars are propelled by an electric motor, which receives its power from a controller. The controller receives its power from an array of rechargeable batteries; it takes the power directly from the batteries and delivers it to the motor. The ac

CO2 Injection HW3
School: WVU
Course: Thermodynamics
A new technique to help combat the current global warming and climate change crisis today deals with the capture and storage of carbon dioxide in underground geological formations . This modern procedure involves capturing the carbon dioxide emissions fro

HW 1
School: WVU
Course: Thermodynamics
1) Concrete undergoes volume change through shrinkage, creep, and temperature variations, and this shall lead to induced stress and cracking. Discuss these indepth. Concrete undergoes volume change through shrinkage, creep, and temperature variations, an

Spr2013mae320_hw7asoln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 7a Assignment, Spring 2013 The homework (HW 7a) is due on Monday, April 15, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (

Equation%20sheet%20for%20exam%202
School: WVU
Course: Thermodynamics
Equations for MAE320 Exam 2 For saturated liquidvapor mixture: y = (1 x) y f + xy g = y f + xy fg , where y is a property of a substance (v, u, h) Quality: x = mg mtotal = mg m f + mg = v vf vg v f = uuf ug u f = h hf hg h f For compressed liquid under g

HW01
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 1 Assignment, Fall, 2013 The homework is due on Wednesday, August 28, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) (1a). Which one is a

HW4
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment, Fall 2013 The homework (HW 4) is due on Monday, October 7th, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1

HW4%20Sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment, Fall 2013 The homework (HW 4) is due on Monday, October 7th, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1

HW05
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 5 Assignment The homework is due Monday, October 21, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choices questions (18 points) (1a). The 1st law of thermod

HW05%20Sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 5 Assignment The homework is due Monday, October 21, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choices questions (18 points) (1a). The 1st law of thermod

HW06%20sol
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 6 Assignment The homework is due Wednesday, November 6, 2013. Each problem is worth the points indicated. (1). Multiple choice (32 points). The correct answers are highlighted in blue, bolded fonts (1a). Which one is invalid rega

Spr2013mae320_hw6soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 6 Assignment, Spring 2013 The homework (HW #6) is due on Friday, April 5, 2013. Each problem/section is worth the number of points indicated (for a tot a l of 100 points). C opying of the sol ut i on f rom anothe r is not a c c e

Spr2013mae320_hw6soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 6 Assignment, Spring 2013 The homework (HW #6) is due on Friday, April 5, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1)

Spr2013mae320_hw5soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics Solution to HW 5 Assignment, Spring 2013 The homework (HW #5) is due on Friday, March 15, 2013. Each problem/section is worth the number of points indicated (for a total of 120 points). Copying of the solution from another is not ac

Spr2013mae320_hw4soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment, Spring 2013 The homework (HW 4) is due on Monday, March 4, 2013. Each problem/section is worth the number of points indicated (for a total of 100 points). Copying of the solution from another is not acceptable. (1).

Exam 1 A Sol
School: WVU
Course: Thermodynamics
NAME:_Solution KEY A_ MAE 320  Thermodynamics Spring 2013 Exam 1 MWF 9:00 9:50 am (Section 02) Feb182012 Score / 100 pts. NOTES FOR EXAM 1: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables

Exam 1 B Sol
School: WVU
Course: Thermodynamics
NAME:_Solution KEY B_ MAE 320  Thermodynamics Spring 2013 Exam 1 MWF 9:00 9:50 am (Section 02) Feb182012 Score / 100 pts. NOTES FOR EXAM 1: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables

Exam 2 A Sol
School: WVU
Course: Thermodynamics
NAME:_ MAE 320  Thermodynamics Spring 2013 Exam 2 MWF 9:00 9:50 am (Section 02) March182013 Score / 100 pts. NOTES FOR EXAM 2: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables will be recy

Exam 2 B Sol
School: WVU
Course: Thermodynamics
NAME:_ MAE 320  Thermodynamics Spring 2013 Exam 2 MWF 9:00 9:50 am (Section 02) March182013 Score / 100 pts. NOTES FOR EXAM 2: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables will be recy

Exam 3 A Sol
School: WVU
Course: Thermodynamics
NAME:_ MAE 320  Thermodynamics Spring 2013 Exam 3 MWF 9:00 9:50 am (Section 02) April192013 Score / 100 pts. NOTES FOR EXAM 3: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables will be recy

Exam 3 B Sol
School: WVU
Course: Thermodynamics
NAME:_ MAE 320  Thermodynamics Spring 2013 Exam 3 MWF 9:00 9:50 am (Section 02) April192013 Score / 100 pts. NOTES FOR EXAM 3: The exam is CLOSED BOOK CLOSED NOTES! Please DO NOT make marks in the provided Appendix1 (xerox) Tables. (Tables will be recy

Spr2013mae320_hw1soln
School: WVU
Course: Thermodynamics
MAE 320  Thermodynamics HW 1 Assignment Assigned  January 18,2012 The homework (HW 1) is due on Friday, January 25, 2012. Each problem/section is worth the number of points indicated (jar a total of 100 points). Copying of the solution from another is n

Spr2013mae320_hw2soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 2 Assignment, Spring, 2013 The homework is due on Monday, February 4, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (24 points) (1a). Which one is N

Spr2013mae320_hw3soln
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 3 Assignment, Spring, 2013 The homework is due on Friday, February 15, 2013. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) (1a). A rigid tank

Spr2013mae320_hw7asoln
School: WVU
Course: Thermodynamics
MAE 320 T h e r mo d y n a m i cs HW 7a Assignment, Spring 2013 The homework (HW 7a) is due on Monday, April 15, 2013. Each problem/section is worth the number of points indicated (for a tot a l of 100 points). C opying of the solut ion f rom anothe r is

Exam 2 Practice
School: WVU
Course: Thermodynamics
EXAM 2 PRACTICE EXERCISES 2.4.24; 4.8.15 2.5.9 2.5.13 2.5.15 (a, c) CH2 Supplemental Exercises: #11 4.1.6 4.2.11 4.2.13 4.5.1 4.5.3 Page 258 example 4.53 (lognormal) 4.8.11 (see equation 4.50 at the bottom of page 276) 4.11.1 4.11.9 4.11.11 4.11.15 4.11.

Solutions_chap02
School: WVU
Course: Thermodynamics
CHAPTER TWO SOLUTIONS 1. (a) 12 s (b) 750 mJ (c) 1.13 k (d) 3.5 Gbits (e) 6.5 nm (f) 13.56 MHz (g) 39 pA (h) 49 k (i) 11.73 pA Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill, Inc. All Rights Reserved. CHAPTER TWO SOLUTIONS 2

Solutions_chap03
School: WVU
Course: Thermodynamics
CHAPTER THREE SOLUTIONS 1. Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill, Inc. All Rights Reserved. CHAPTER THREE SOLUTIONS 2. (a) six nodes; (b) nine branches. Engineering Circuit Analysis, 6th Edition Copyright 2002 McGr

Solutions_chap05
School: WVU
Course: Thermodynamics
CHAPTER FIVE SOLUTIONS 1. Define percent error as 100 [ex (1 + x)]/ ex x 0.001 0.005 0.01 0.05 0.10 0.50 1.00 5.00 1+x 1.001 1.005 1.01 1.05 1.10 1.50 2.00 6.00 ex 1.001 1.005 1.010 1.051 1.105 1.649 2.718 148.4 % error 5105 1103 5103 0.1 0.5 9 2

Solutions_chap06
School: WVU
Course: Thermodynamics
CHAPTER SIX SOLUTIONS 1. The first step is to perform a simple source transformation, so that a 0.15V source in series with a 150 resistor is connected to the inverting pin of the ideal op amp. Then, vout =  2200 (0.15) =  2.2 V 150 Engineering

Solutions_chap07
School: WVU
Course: Thermodynamics
CHAPTER SEVEN SOLUTIONS 1. (a) C = A 8.854 10 12 (78.54 10 6 ) = = 6.954 pF d 100 10  6 1 2E 2( 10  3 ) 1 CV 2 V = = = 16.959kV 2 C 6.954 10 12 (b) Energy , E = (c) E = 1 2 E 2(2.5 10 6 ) CV 2 C = 2 = = 500 pF 2 (100 2 ) V C= A Cd

Solutions_chap08
School: WVU
Course: Thermodynamics
CHAPTER EIGHT SOLUTIONS 1. (a) iL (0) = 100 = 2A iL (t ) = 2e 80t / 0.2 50 400 t = 2e A, t > 0 (b) (c) iL (0.01) = 2e4 = 36.63mA 2e 400t1 = 1, e400t1 = 2, t1 = 1.7329ms Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill,

Solutions_chap09
School: WVU
Course: Thermodynamics
CHAPTER NINE SOLUTIONS 1. o L = 10, s1 = 6s 1 , s2 = 8s 1 2 2 6 = + 2  o ,  8 =   2  o adding, 14 = 2 = 7 s 1 2 2 6 = 7 + 49  o o = 48 1 , o = 6.928 LC rad/s 6.928 L = 10, L = 1.4434H, 1 1 C= = 14.434mF, = 7 R = 4.949 4

Solutions_chap10
School: WVU
Course: Thermodynamics
CHAPTER TEN (Phasor Analysis) SOLUTIONS 1. (a) 2103 = 290.9t rad/s 21.6 f (t ) = 8.5sin (290.9t + ) 0 = 8.5sin (290.9 2.110 3 + ) T = 4 (7.5  2.1)103 = 21.6 103 , = = 0.6109rad + 2 = 5.672rad or 325.0 f (t ) = 8.5sin (290.9t + 325.0) (b

Solutions_chap19
School: WVU
Course: Thermodynamics
CHAPTER NINETEEN (WEB CHAPTER) SOLUTIONS 1. Order i1 , i2 , i3 :  2i1  6i3 = 5 + 2 cos10t  3i1 + 2i2 4i2 = 0.05i1  0.15i2 + 0.25i3 (2) i2 = 2i1  5i3 + 0.4 (i1  i3 ) dt + 8 0 t (1) (3) (1) 2i1  6i3 = 3i1 + 2i2 + 5 + 2 cos10t = A (

Solutions_chap11
School: WVU
Course: Thermodynamics
CHAPTER 11 SOLUTIONS 1. 50 ( j80) 106 =  j80 , = 42.40  32.01 j 500 25 50  j80 V = 84.80  32.01 V, I R = 1.696  32.01 A Zc = I c = 1.060057.99 A ps ( / 2ms) = 84.80 cos (45  32.01) 2 cos 45 = 116.85 W pR = 50 1.696 2 cos 2 (45  32.01) = 13

Solutions_chap12
School: WVU
Course: Thermodynamics
CHAPTER TWELVE SOLUTIONS 1. Vbc = Vbe + Vec = 0.7 10 = 9.3 V Veb =  Vbe = 0.7 V Vcb = Vce + Veb = 10 0.7 = 9.3 V Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill, Inc. All Rights Reserved CHAPTER TWELVE SOLUTIONS 2. (a) V

Solutions_chap13
School: WVU
Course: Thermodynamics
CHAPTER THIRTEEN SOLUTIONS 1. 1 and 3, 2 and 4 1 and 4, 2 and 3 3 and 1, 2 and 4 Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill, Inc. All Rights Reserved CHAPTER THIRTEEN SOLUTIONS 2. (a) (b) (c) iS1 = 4t A, iS 2 = 10t A vAG

Homework 3
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 3 Assignment The homework is due Friday, September 21, 2012. Each problem is worth the points indicated. Copying of the solution from the others is not acceptable. (1). Multiple choice and multianswers questions (18 points). (1a

Homework 4
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment The homework is due Monday, October 8th, 2012. Each problem is worth the points indicated. (1). Multiple choice and multianswer questions (21 points) (1a). A system contains heat and work (A) (B) (C) (D) (E) sometim

Homework 5
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 5 Assignment The homework is due on Friday, October 19th, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choice (3 points/each) (1a). Among the following stat

Homework 7
School: WVU
Course: Thermodynamics
MAE320 HW7A The homework is due Monday, November 12, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (28 points) 1a). Which statement is invalid regarding the entropy generati

Design Project
School: WVU
Course: Thermodynamics
Volume T[C] PA MA H2O CO2 HI 300 0.0842 0.0202 0.5186 0.3769 0.0001 T[C] PA MA H2O CO2 HI Selectivity 380 0.0664 0.0177 0.491 0.4247 0.0002 T[C] Vreactor[m^3] Cost [$] Component Price [$/kg] 380 0.0664 0.0177 0.491 0.4247 0.0002 400 0.0629 0.0171 0.4858 0

Design_v3.02
School: WVU
Course: Thermodynamics
v. 3.0, 20131113 v. 2.0, 20131021 v 1.0, 20130829 Design Project, Fall 2013 Material and Energy Balances 1, ChE 201 Production of Phthalic Anhydride from oXylene Phthalic anhydride (PA) is used in the manufacture of plasticizers (additives to polym

Entropy Change
School: WVU
Course: Thermodynamics
Entropy Change Property diagrams (Ts and hs diagrams) From the definition of the entropy, it is known that Q=TdS during a reversible process. Hence the total heat transfer during such a process is given by Qreversible = TdS Therefore, it is useful to c

Chapter07_2
School: WVU
Course: Thermodynamics
Chapter 7 Continued Entropy: A Measure of Disorder Study Guide in PowerPoint to accompany Thermodynamics: An Engineering Approach, 5th edition by Yunus A. engel and Michael A. Boles 1 Example 79 Air, initially at 17oC, is compressed in an isentropic proc

Chapter_6
School: WVU
Course: Thermodynamics
S.A. Klein and G.F. Nellis Cambridge University Press, 2011 A. Entropy Balances 6.A1 The two places that thermal energy is transferred from a car are through the engine block (to the coolant) and through the exhaust pipe. A company is marketing a device

Homework 7b Solutions
School: WVU
Course: Thermodynamics
MAE 320 HW 7B This comprehensive homework is due Monday, December 3rd, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable 1. Multichoice, multianswer question (35 Points) 1a. For ideal gas, please ci

Homework 7 Solutions
School: WVU
Course: Thermodynamics
MAE320HW7A The homework is due Monday, November 12, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. (1). Multiple choice (20 points) 1a). Which statement is invalid regarding the entropy generatio

Homework 6 Solutions
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 6 Assignment The homework is due Friday, November 2, 2012. Each problem is worth the points indicated. (1). Multiple choice (24 points) (1a). Which one is invalid regarding the 2nd law of thermodynamics? (A) The second law of the

Solutions_chap14
School: WVU
Course: Thermodynamics
CHAPTER FOURTEEN SOLUTIONS 1. (a) s = 0; (b) s = j9 s1; (c) s = 8 s1; (d) s = 1000 j1000 s1; (e) v(t) = 8 + 2 cos 2t mV cannot be attributed a single complex frequency. In a circuit analysis problem, superposition will need to be invoked, wher

Solutions_chap15
School: WVU
Course: Thermodynamics
CHAPTER FIFTEEN SOLUTIONS 1. Note that iL(0+) = 12 mA. We have two choices for inductor model: = 0.032s = 384 V 0.032s 12 mA s Engineering Circuit Analysis, 6th Edition Copyright 2002 McGrawHill, Inc. All Rights Reserved CHAPTER FIFTEEN SOLUTI

Solutions_chap16
School: WVU
Course: Thermodynamics
CHAPTER SIXTEEN SOLUTIONS 1. We have a parallel RLC with R = 1 k, C = 47 F and L = 11 mH. (a) Qo = R(C/L) = 65.37 (b) fo = o/ 2 = (LC) / 2 = 221.3 Hz (c) The circuit is excited by a steadystate 1mA sinusoidal source: 1030o A j L j/ C The adm

Solutions_chap17
School: WVU
Course: Thermodynamics
CHAPTER SEVENTEEN (TWOPORT) SOLUTIONS 1. 17 8 3 Z = 8 17 4 = 17(273) + 8(148)  3(83) = 3208 3 3 4 17 Z 3208 1002 Zin1 = = = 11.751 P1 = = 851.0 W 11 273 11.751 Zin 2 = Z 3208 1002 = = 11.457 P2 = = 872.8 W 22 280 11.457 (a) (b) (c

Solutions_chap18
School: WVU
Course: Thermodynamics
CHAPTER EIGHTEEN (Fourier Analysis) SOLUTIONS 1. v(t ) = 3  3cos(100 t  40) + 4sin(200 t  10) + 2.5cos 300 t V (a) Vav = 3  0 + 0 + 0 = 3.000 V 1 Veff = 32 + (32 + 42 + 2.52 ) = 4.962 V 2 T= 2 2 = = 0.02 s o 100 (b) (c) (d) v(18ms) = 3  3cos

Syllabus
School: WVU
MAE 320 Thermodynamics MWF 8:00 8:50 AM, Rm.401 ESB Course Syllabus Spring 2009 Prerequisite: Instructor: Office: PHYS 111 and MATH 156 Nianqiang "Nick" Wu, Ph.D. Rm. 515 ESB; Tel: 2933111 EXT.2335; Email: nick.wu@mail.wvu.edu Office hours: Catalog

Homework 4 Solutions
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 4 Assignment The homework is due Monday, October 8th, 2012. Each problem is worth the points indicated. (1). Multiple choice and multianswer questions (21 points) (1a). A system contains heat and work (A) (B) (C) (D) (E) sometim

Homework 5 Solutions
School: WVU
Course: Thermodynamics
MAE 320 Thermodynamics HW 5 Assignment The homework is due on Friday, October 19th, 2012. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. 1. Multiple choice (3 points/each) is invalid (1a). Among the fol

Chapter07_1
School: WVU
Course: Thermodynamics
Chapter 7 Entropy: A Measure of Disorder Study Guide in PowerPoint to accompany Thermodynamics: An Engineering Approach, 5th edition by Yunus A. engel and Michael A. Boles Entropy and the Clausius Inequality The second law of thermodynamics leads to the d