ssm_ch01 - Chapter 1 Student Solutions Manual 3. Using the...

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Chapter 1 – Student Solutions Manual 3. Using the given conversion factors, we find (a) the distance d in rods to be () ( ) 4.0 furlongs 201.168 m furlong 4.0 furlongs = 160 rods, 5.0292 m rod d == (b) and that distance in chains to be ( ) 4.0 furlongs 201.168 m furlong 40 chains. 20.117 m chain d 5. Various geometric formulas are given in Appendix E. (a) Expressing the radius of the Earth as ( ) 63 3 6.37 10 m 10 km m 6.37 10 km, R = × its circumference is 34 2 2 (6.37 10 km) 4.00 10 km. sR ππ × = × (b) The surface area of Earth is ( ) 2 23 4 4 6.37 10 km 5.10 10 km . AR =π =π × = × 8 2 (c) The volume of Earth is 3 33 44 6.37 10 km 1.08 10 km . VR 1 2 3 π π × = × 17. None of the clocks advance by exactly 24 h in a 24-h period but this is not the most important criterion for judging their quality for measuring time intervals. What is important is that the clock advance by the same amount in each 24-h period. The clock reading can then easily be adjusted to give the correct interval. If the clock reading jumps around from one 24-h period to another, it cannot be corrected since it would impossible to tell what the correction should be. The following gives the corrections (in seconds) that must be applied to the reading on each clock for each 24-h period. The entries were determined by subtracting the clock reading at the end of the interval from the clock reading at the beginning.
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This note was uploaded on 04/09/2008 for the course PHYS 131 taught by Professor Drty during the Spring '08 term at Lafayette.

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ssm_ch01 - Chapter 1 Student Solutions Manual 3. Using the...

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