Chapter+3+.12ed

# Chapter+3+.12ed - 3.24 a Let H = Hyundai Elantra T Toyota...

• Notes
• 3

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3.24 a. Let H = Hyundai Elantra, T: Toyota Prius, and S = Subaru Forrester. All possible rankings are as follows, where the first car listed is ranked ﬁrst, the second car listed is ranked second, and the third. car listed is ranked third: HES H61?" 3,1353" SEE EH3 IEH b. If each set of rankings is equally likely, then each has a probability of 1.36. The probability that the Toyota Prius is ranked ﬁrst =P(T,H,S)+P(T,S,Hj=1.-"6+l.r'6 =2;‘6=1:‘3 The probability that the Hyundai Elantra is ranked third = P(S,T,H}+P(T,S,H) =1.r6+1.r'6 = 2.-‘6 =1.-'3_ The probability that the Toyota Prius is ranked first and the Subaru Forrester is ranked second = PCT,S,H) =1.r6_ 3.30 The experiment consists of rolling a pair of fair dice. The sample points are: Since each die is fair, each sample point is equally likely. The probability of each sample point is 1;"35. a. A: {(1, 6), (2, 5), (3, 4), (4, 3),(5,2),(6,1)} BI {(134)114);(3:4)=(434);(5,4):(5,4);(4; 1), (4, 2): (4; 3), (43 5), (4, 5)} A03: {(3, 4), (4, 3)} AUBI {(1: 4): (2, 4), (3} 4): (4, 4), (5; 4)} (5, 4), (4, 1); (4: 21501331391: 5): (4= 5), (1, 61(2, 5): C5: 2), (5, 13'} A“: {(1} 11'2 (1, 231,“; 310, 4L0; 5); (23 115(13): (2? 3); (3, 410; (5)76: 1), (3; 3); (3, 3), (3; 5); (151(4, 13,01; 332(4; 4): (4, 5); (4: 6); (5, 13; (52 3); (5: 43L (5;. 5): (5, 6), C6; 3): (5: 3): (6; 4): (6: 511:5, 6)} i\ =£=l P(a)=11[i]=ﬂ P(AHB)=2[-Hi\=i=i 36, 36 6 36 36 I36} 36 Is b P(A)—6[ W. F - r Pmoaj=15£i =1—3—i PKAE)=30| £133 30; 35 12 k30,73 1 11 l 6+‘ll—2 15 S c- PIZAUB)=P(A)+P{B)—P[AﬂB}=—+———=—=—=— 6 36 18 36 36 12 d. A andB are not mutually exclusive- To be mutually exclusive. P(.«1 rs 3) must be 0. Here, 1 Fame =—. ( ) 18 3.113 Deﬁne the following events: 3: {System shuts down} F1: {Hardware failure} F3: {Software failure} F3: {Power failure} From the Exercise, we know: P(F1) = .01, P(F2)=.05 ,and P(F3)=.ﬂ2. Also; P(S|F1)=.73, P(S|F1)=.12,andP(S|P;)=.38. The probability that the current shutdown is due to a hardware failure is: HF I S) 2 as n3) : P(S|F1)P(F1) 1 Po“) PIS I FIJHFJ + P(3 I Poms) +PcSI mes) _ 03001) _ .00r3 _ .00s3 _ 3362 03001) + .12(.05)+.88(.l]2) .00?3+.005+.01?5 .0309 'L The probability that the current shutdown is due to a software failure is: HF 3)_P(F2FISJ _ P(S|F:)P(F2) ‘ Po) P(S|F1)P(EJ+P(SI was) + P(S| Fame) .12(.05) .005 _ .006 21942 _ .7‘3(.01)+.12(.05) +.33(.02) _ .00r3 +.005+ .0115 _ .0309 The prebahility that the current shutdown is due to a pewer failure is: HF IS) _P(F3ﬂSJ _ PESIEFGD 3 _ Pia) _PIES|E)P(E)+P(S|EJP(F2)+P(SIF;)P(P;) .33(_02) Lane __{}1T6 : _ = — _ — = .5596 _?3(_:]1)+_12(_e5)+_33(_02) Janna +_ne5+_m?e .3313? ...
View Full Document

• Spring '12

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern