EE 42 - Spring 2009 - Poolla - Final - EECS Spring 2009 Final Exam PRINT NAME(Last First SIGN YOUR NAME STUDENT ID CIRCLE ONE EE 100 EE 42#1#2#3#4

EE 42 - Spring 2009 - Poolla - Final - EECS Spring 2009...

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EECS 100/42/43 Spring 2009 Final Exam PRINT NAME (Last, First): SIGN YOUR NAME: STUDENT ID #: CIRCLE ONE: EE 100 EE 42 E 147 # 1 # 2 # 3 # 4 SUBTOTAL 20 8 10 10 48 # 5 # 6 # 7 # 8 SUBTOTAL 10 15 10 10 45 # 9 # 10 # 11 # 12 # 13 SUBTOTAL TOTAL 10 10 10 15 7 52 145 Instructions: 1 Print and sign your name and enter your student ID number above. 2 Read the questions carefully. 3 Write your solution clearly. 4 You must show your work to get full credit. 5 This 2 1/2 hour exam has 13 questions worth 145 points, so you should proceed at approximately 1 point per minute. 1
Problem # 1 (20 points) (a) Simplify the following Boolean expression: Q = AB + B + ( A + C ) B + ABC Q = 3 points (b) What do these acronyms stand for? CMOS: 1 point RAM: 1 point RISC: 1 point ROM: 1 point (c) What is the principal advantage of CMOS logic circuits? Answer: 1 point (d) Consider an ideal diode connected in some circuit. Can the diode absorb energy? Explain your answer. Answer: 2 points (e) Draw a comparator and explain what it does. Answer: 2 points 2
(f) Consider the following code. We transmit the five bits 00000 for the digital 0 and the five bits 11111 for 1 . How many bit errors can this code correct? 1 point How many bit errors can this code detect? 1 point (g) Consider a 64 Megabyte memory chip that uses a 32 bit architecture (i.e. the data is stored in chunks of 32 bits). How many lines does the address bus have? 1 point How many lines does the data bus have? 1 point (h) What dopant material is typically used to make a p-type semiconductor? Answer: 1 point

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