ime261a11s - IME 2610 Fall 2010 Assignment 11 Solutions <30pts> Problem A a 5pts b 1pt c 5pts From your textbook Problem 10.4(page 485 You can complete

# ime261a11s - IME 2610 Fall 2010 Assignment 11 Solutions...

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IME 2610 - Fall 2010 Assignment 11 Solutions <30pts> Problem A: a) 5pts b) 1pt c) 5pts ________________________________________________________________________________________ From your textbook: Problem 10.4 (page 485). You can complete this problem by hand or using Minitab. If you use Minitab, please notate the printout by highlighting and explaining the information used to make your decision for each part. Be sure to answer all parts. a) Using Minitab <3pts> One-way ANOVA: Strength versus Mix Source DF SS MS F P Mix 4 487.45 121.86 58.89 0.000 Error 10 20.69 2.07 Total 14 508.14 S = 1.439 R-Sq = 95.93% R-Sq(adj) = 94.30% Individual 95% CIs For Mean Based on Pooled StDev Level N Mean StDev --+---------+---------+---------+------- 1 3 43.833 0.764 (---*--) 2 3 33.600 2.252 (---*---) 3 3 30.667 0.451 (--*---) 4 3 43.600 1.836 (---*---) 5 3 43.400 1.058 (---*---) --+---------+---------+---------+------- 30.0 35.0 40.0 45.0 Pooled StDev = 1.439
b)<3pts> The Tukey‐Kramer procedure is appropriate because the original ANOVA test showed significant differences between groups. Using Minitab: Grouping Information Using Tukey Method Mix N Mean Grouping 1 3 43.833 A 4 3 43.600 A 5 3 43.400 A 2 3 33.600 B 3 3 30.667 B Means that do not share a letter are significantly different.