Unformatted text preview: = += + = + =( b )The time of flight can be found from Eq. 211b, with x replaced by y , using a displacement of 0 for the displacement of the ball returning to the height from which it was hit. ( 29 ( 29 2 1 1 2 2 2 2 22m s 2 0 0 0 , 4.5 s 9.80m s v y y v t at t v at t t a = + + = + = = = = =The result of t = 0 s is the time for the original displacement of zero (when the ball was hit), and the result of t = 4.5 s is the time to return to the original displacement. Thus the answer is t = 4.5 seconds....
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This note was uploaded on 04/09/2008 for the course PHSX 114 taught by Professor Davis during the Spring '08 term at Kansas.
 Spring '08
 DAVIS

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