Formula Sheet for Exam 1 [Spring 2008]

# Formula Sheet for Exam 1 [Spring 2008] - Right Angled...

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PHSX 114 – Spring 2007 Formulae for 1 st Exam Constant : g = 9.80 m/s 2 downwards Trigonometric Relations : Kinematic Formulae : t x t - t x - x v 1 2 1 2 ave = = t v t - t v - v a 1 2 1 2 ave = = t x 0 t lim v = t v 0 t lim a = at v v 0 + = 2 0 0 at 2 1 t v x x + + = ) x 2a(x v v 0 2 0 2 - + = 2 v v v 0 ave + = Distance traveled, t v x - x ave 0 = For motion in earth’s gravitational field with the +y axis chosen to be upwards , gt v v 0 - = 2 0 0 gt 2 1 t v y y - + = ) y 2g(y v v 0 2 0 2 2 - - = , 2 v v v 0 ave + = but you must be careful when you use the latter relation Vectors : With A = magnitude of A and θ = angle between the direction of A and the x-axis, A x = Acos θ, A y = A sin θ, A 2 = A x 2 + A y 2 , θ = tan -1 x y A A For B A C + = , etc., C x = A x + B x and C y = A y +B y and B 2 A 4 D - = , etc., D x = 4A x - 2B x and D y = 4A y -2B y Phsx114 – sp08-Formula Sheet for Exam 1, Page 1 of 2 sin θ = a/c, cos θ = b/c, tan θ =a/b c 2 = a 2 + b 2 , θ = tan -1 (a/b) a b c θ

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Unformatted text preview: Right Angled Triangle x y A y A x A θ Quadratic Equation : Solution to the quadratic equation, ax 2 + bx + c = 0 is: 2a 4ac b b-x 2-± = Projectile Motion: With coordinate axes chosen with the x-axis horizontal and the y-axis vertically upwards, we have a x = 0 and a y = -g, giving the kinematic equations: v x = v 0x + a x t → v x = v 0x x = x + v 0x t +½ a x t 2 → x = x + v 0x t v y = v 0y + a y t = v 0x → v y = v 0y- g y t y = y + v 0y t +½ a y t 2 → y = y + v 0y t -½ gt 2 v y 2 = v 0y 2 + 2a y (y - y ) → v y 2 = v 0y 2 – 2g(y - y ) Phsx114 – sp08-Formula Sheet for Exam 1, Page 2 of 2...
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Formula Sheet for Exam 1 [Spring 2008] - Right Angled...

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