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Unformatted text preview: is at an angle of = 35.0 to the horizontal. Note : In numerical answers, enter only the magnitude of the number, without a sign. Enter scientific notation as 1.23E4. a. Calculate the horizontal friction force on the mower. [Num] [Units] b. Calculate the normal force exerted vertically upward on the mower by the ground. [Num] [Units] c. What force must the person exert on the lawn mower to accelerate it from rest to 1.20 m/s in 3.10 seconds, assuming the same friction force? [Num] [Units] *HINT: If the positive direction is forward (as is assumed since the force of the person is listed as positive) then the frictional force should be negative....
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This note was uploaded on 04/09/2008 for the course PHSX 114 taught by Professor Davis during the Spring '08 term at Kansas.
 Spring '08
 DAVIS

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