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Unformatted text preview: 930kg car 650 m up along a 9.3° incline? Enter scientific notation as 1.23E4. a. Ignore friction. [Num] [Units] b. Assume the effective coefficient of friction retarding the car is 0.17 . [Num] [Units] Question 3: (1 point) How much work must be done to stop a 1,310kg car traveling at 129 km/h ? Enter scientific notation as 1.23E4. 1 Number Units 2...
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 Spring '08
 DAVIS
 Scientific Notation, Friction, #, 4.9 m, 1,310kg, 9.3°

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