bme501RespiratoryMidtermSoln20083

bme501RespiratoryMidtermSoln20083 - HME 501 Respiratory...

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Unformatted text preview: HME 501 Respiratory Section Exam Fall 2008 Mark True(T) or False(F). 1 V2 points each, 30 points total. ’- l. ( i ) The sum of the partial pressures of gas in dry atmOSpheric air equals the barometric pressure. I_,../ 2.( l ) The normal blood-gas barrier is ofthe order of 0.3 micrometer thick . 3. ( ) Some of the cells lining the nasal passages secrete a substance called surfactant. / 4.( i ) Mucus secreted by mucous glands is removed by cilia which are hairline structures which beat and propel mucus mouthward. / 5.( l ) The maximal inhaled volume is called the vital capacity. / f 6.( l/ ) A spirometer alone can be used to measure total volume of gas in the lungs. T( F ) Alveolar ventilation can be higher than total ventilation in the human lungs. / 8.( i” ) Ifa subject stands on his head, the base(bottom) ofthe lungs should ventilate better than the apical region. /, 9.( f” ) lfa subject is totally immersed in water up to the neck, but still in an upright posture regional differences in ventilation and perfusion due to pleural pressure differences should still be present. ,/ 10.( i ) Hypoxia in the lungs normally leads to constriction ofthe pulmonary blood vessels. A!” 11.( l ) In an electric circuit composed of capacitors of different capacitances in parallel connected to a current source the current will split in a way where the higher current will flow in the larger capacitance. ./ l2( r) During moderate exercise in normals arterial blood PCOZ rises in proportion to the metabolic production rate ofCOZ. .r/ l3( if ) Ifblood flow is interrupted to a major part ofthe body a metabolic alkalosis condition is expected. 14(f’ ) If alveolar oxygen is higher than normal the ventilatory CO2 response curve shows a steeper siOpe of ventilation plotted against alveolar PC02. 15( if) In ventilatory response to CO2 the increased slope ofthe CO2 response curve(ventilation plotted against alveolar partial pressure ofCO2)secn during hypoxia is mediated by the central chemoreceptors. /' 16( l") In a linear negative feedback control system instability results ifelosed loop gain is greater than unity and closed loop phase shift exceeds 180 degrees. 17%?) Time delay of 6 seconds is associated with a phase shift of [80 degrees if the frequency is 1:15 cycles per second. / 18(l/ ) Ifinspircd gas partial pressure ofoxygen in the lungs equals 40 mm Hg pulmonary venous blood can be higher than this value. Mar" 19{ l ) High partial pressures ofnitrogen such as experienced in diving at :> 100 feet sea water is known to have narcotic effects. _/ f 20( If) Release of nitrogen bubbles from tissue into blood can be caused by a rapid change in atmOSphen'e pressure in going from 20,000 feet altitude to sea level. Fill in the Blanks. Two points each, 20 points total. '- n '1 (If- 2.1 The CY h " effect involves the shift in the blood 02 dissociation curve as a function of pH. 2.2 The 5'“ ti" effect involves the vertical shift in the blood CO2 dissociation curve as a function of oxygenation level. _/ J "-ll . . . . . 2.3 Q i J "r‘ “ ' law deals With pressure flow characteristics for laminar flow in a tube where driving pressure islldireetly proportional to flow rate legs am: w: l c C. _ . . . . . refers to the lung volume rema1n1ng after a maximal expiration. .. .l . . . . . . fir E > 2.5 Diffilswn 1n the lungs rand tiss e IS described by . ’ ‘ law. I l ydztggc’l VIC L/‘T' ‘e’r’iv'll r 2.6 The“; Tél L equation relates blood pH. PC02. and bicarbonate. 2.4 /’ - _.‘ 2.? The C ‘h‘ {fl/“(ll L law or equation predicts pressure caused by liquid surface tension efa sphere. .. f— 5) ("Ew- ’ - .5; //'3' _ I _ _ 2.8 The// 2 reflex Involves sensors which respond to lung inflation by terminating the breath. o..- .r nil r 2.10 The peripheral chemoreceptors in man are located in the -- at the bifurcation of the common carotid, artery. (two words) 2.9 The neural reSpiratory centers are located in the 3.(10) An arterial blood sample has{HCO3-]=32 rnMx‘l and PC02=20 mm Hg. (a) Calculate pH. (b) Calculate standard bicarbonate [HCO3-]?.4 for a buffer line slope of- 30 lil per pH unit. pH-=6.i+log([HCO3-].-‘(.03*PC02)) (c) What is the respiratory status ofthis sample? (d) What is the metabolic status ofthis sample c) ;.’t_.-g;2rrtclgv¢) (“vulva 3 d-‘>M.;.L,krflé[kc tort-x1061: (H/Qij ’ > ‘/ 4.(10) A balloon filled with a subject’s vital capacity ofS liters (BTPS) of gas with 10% helium and balance oxygen is rebreathed (inhaling and exhaling with vital capacity breaths (maximum possible) into the bag via the mouth with a noseclip attached) for 3 breaths with the subject starting at residual volume prior to rebreathing Assuming a closed system where no helium is lost to the blood or escapes from the lungs and balloon. Calculate residual volume (BTPS) if after the 3 deep breaths the bag has 7 percent helium. '3. J Jj ; r5 1/ g 4' «i... I???) 5(15) Based on a two compartment model oflung gas exchange, compartment 1 has a ventilation of 0.3 Lr’min, a blood flow of3 l.- min, and a FAQ; of .2039, compartment 2 has a ventilation of 3 l/min, a blood flow of 0.3 lr'min and a FAQ; of 0.0692, B=760 mm Hg , PH20=4? mm Hg. Calculate the alveolar and pulmonary venous P02. Assume individual compartmental Pa02=PA02. (‘30; = 0.201*SaOz III blood Sa03=(]_e‘-U46‘Pa02)2 f / r ,3 1. (9;)(Jgéfi) _.H 5.2; I’ch (J 9M 1 F K; 212% 2.; fl) raglan?» flag: fir W“? 5 r’ d I .21 35 7 3 r "3,6; ) ‘ ,,_ 4-7 {#23}. " ’Wlfl. (AU / f t l air-'3“ ’ {7/3) ; 4’31] “#3) farm): ré’é‘x‘z (712% "8 3 A a C“ {A «It? {1%1/(7z5’5‘) H LII {51: /H (r23./'*C€' _‘ “ ’ xyflwfi” . f . L4- ’ [<“/’2‘§z'¢' ('“r /“3}’5 \1 , er I! I. # CQLJ 3’: : (BC/{3 Tara/2) f kl“ if“ at 3‘ ' Hf 355 .j a . . s,‘ iii/I: 113*“:m5 1":3X’ 5.. r _ . I" x y r'-‘((, r‘rvx :' '3 I" ~ I'll-"(l 7' a) ‘é c b e ___ fl 7 _ H*_ _ l: Ar- I x“- 41 (3’71" { [I f 32,)61 F __ (“{z _ I (“~- 2 F {21-1 " ' ——~—. 3% w :- l a" 3/2 ' '~ 2 ‘ .;.__ a, -_ ate/Um; If WC“ grey}; ## #___ ' w'! R 1‘, :3— ’7l ”' l J 6.05) A subject has a minute ventilation of 8 Iitersr‘min (BTPS) with 8:565 mm Hg. Tbodwfl deg C, PHZO = 47 mm Hg . a) What is this ventilation converted to ambient (ATPS) conditions (25 deg C, PH20=18 mm Hg, 8:565 mm Hg) b) Ifthis ventilation is fully supplied by a compressed air cylinder ofvolume 10 liters and initial pressure =2000 psi(14.? psi = 760 mm Hg), how IOng will it take for the cylinder to be emptied? Cylinder temperature is also 25 deg C. i .5») r 5:1”) .1 tén«r_{f??i‘7f’5i) a) +3 7 ) (9735-1— 95-) I Here: S” (5135:411) (22:32:) (13939;) (fly-377 /’/7 ‘ x . . F a \ flay/av.” (i0) 3; M»? m) / .f, .. .I v” flf7 L/ L r _ _ V, J ,gex : 2:3 /, / f 3 I .‘ H'fl" in A ...
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This note was uploaded on 01/11/2009 for the course BME 501 taught by Professor Yamashiro,hsiai during the Fall '07 term at USC.

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bme501RespiratoryMidtermSoln20083 - HME 501 Respiratory...

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