BME_501___HW1_fall__2008

# BME_501___HW1_fall__2008 - BME 501 HW#1 Due Sept 10 1....

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BME 501 HW#1 Due Sept 10 1. Assume that a pilot in a fighter plane (Blue Angels flight show maneuver) can climb from sea level to 20,000 feet altitude essentially instantaneously. If gas in the lungs of the pilot has a partial pressure of oxygen of 100 mm Hg at sea level (P B =760 mm Hg) what will the partial pressure be at 20,000 feet if the barometric pressure there is 349 mm Hg. Alveolar gas is saturated with water vapor at 37 deg C (P H2O =47 mm Hg). Solution: According to the equation = × PO2 F B Since the plane climb from sea level to 20,000 feet altitude instantaneously, we consider the fraction of oxygen F as unchanged, which is = - = . F 100760 47 0 1403 Thus the partial pressure at 20,000 feet will be = - × . = . PO2 349 47 0 1403 42 36mmHg 2. In class the effective level of inspired oxygen partial pressure was calculated for a patient with a supplemental oxygen flow in a nasal cannula of 1 liter/minute and assuming a 50/50 inspiration-expiration split(B=565 mm Hg, inspired ventilation=8 liters/min). Instead, calculate what the supplemental flow level

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## This note was uploaded on 01/11/2009 for the course BME 501 taught by Professor Yamashiro,hsiai during the Fall '07 term at USC.

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BME_501___HW1_fall__2008 - BME 501 HW#1 Due Sept 10 1....

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