This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: (a) Let y = sin x and 0 ≤ x ≤ π . Revolve the region under the curve and above the xaxis. [Note that sin 2 x = 1 / 2cos(2 x ) / 2.] (b) Let y 1 = 4x 2 and y 2 = x 2 . Revolve the region between y 1 , y 2 , and the yaxis. (c) Revolve the region enclosed by the circle of radius 1 centered at (0 , 3). Here, just set up an integral that describes the volume of the resulting torus. Also, (d) Find the volume of a right circular cone of height H and base radius R. (e) Find the volume of a solid object with a circular base and square cross sections. Finally, if y 1 = 4x 2 and y 2 = x 2 , ﬁnd the area of following regions. (f) The region between y 1 , y 2 , and the yaxis, (g) The region between y 1 , y 2 , and the xaxis....
View
Full Document
 Fall '06
 McAdam
 Cone, dx

Click to edit the document details