Sample.ques.Test4 - 4 2 3 3 dx x x 5 Evaluate w/o...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Antiderivatives: 1. + - du u u 7 2 3 2. + dx x x ) 1 ( 4 3. dw w w w - 4 5 2 3 4. + dt t t t ) cos (tan sec 5. + vdv v csc sin 1 2 Riemman Sums and the Definite Integral: 1. Approximate the area under the curve using right endpoints for y = f(x) if ] 6 , 1 [ int 3 ) ( erval the on x x f + = 2. And approximate the area under the curve y = g(x) on the interval x = 0 to x = 6, where g(x) = e -3x 3. Let’s consider when the function is . ] 4 , 0 [ int 3 3 ) ( 2 erval the over x x x f + + = Divide the interval into n-equal subintervals and use the Riemann Sum and r.h.e.p. to write the Area(as a function of n) skinny little rectangles. Now, find the limit as n ∞. 4. Use the first part of the fundamental theorem of calculus to evaluate
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ∫ + + 4 2 3 3 dx x x 5. Evaluate w/o calculator ∫ +-8 1 2 3 6 dx x x 6. ∫-4 2 sec tan π dx x x 7. ∫ 2 sin 3 dx x You should be able to do 7 without calculator…try it, if not try to let the calculator to tell you the antiderivative only. Then you evaluate the definite integral w/o calculator. 8. One question in the book (number 45 on page 391) asked why ∫-1 1 2 1 dx x is not simply the 1/x evaluated to get -2…? If that presents a problem can we evaluate the following ∫ 9 1 2 1 dx x ?? Why? Or Why not??...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern