{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Format of EXP 11 The Properties of Gases

Format of EXP 11 The Properties of Gases - Date Perform...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Date Perform: 11/12/07 Name: Josh LaCelle Date Submitted: 11/26/07 Partner: Nick Rorrer Instructor: Steven Burrows The Properties of Gases Objective to study the dependence of the volume of a gas on temperature and pressure. Experiment Data A. Charles’s law Diameter of Tube = 2.5mm Temperature ( o C) Length of air space (cm) 6 5.9 23 6.0 34 6.0 49 6.2 63 6.5 77 6.7 93 7.0 B. Boyle’s law Atmospheric Pressure = 717 ± 5 mmHg Syringe Volume (ml) Sensor Pressure (mmHg) 20 0.0 19 27.1 18 66.6 17 114.7 16 154.7 15 208.6 14 267.3 13 332.3 12 401.4 11 496.0 10 586.5 9 696.1 8 843.0 7 963.8 9.5 535.5 Sample Calculations Charles’ Law
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
V = πr 2 h V = π(.125cm) 2( 5.9cm) = 0.29cm 3 Boyle’s Law P air = P sensor + P atm P air = 27.1mmHg +717mmHg = 744.1mmHg PV = k 744.1mmHg x 19ml = 14137.9 Results and Conclusions Part A Temperature ( o C) Temperature ( o K) Height of air (cm) Volume (cm 3 ) 6 279 5.9 0.29 23 296 6.0 0.29 34 307 6.0 0.29 49 322 6.2 0.30 63 336 6.5 0.32 77 350 6.7 0.33 93 366 7.0 0.34 Conclusion: As the temperature increases the volume increases as well. V vs. T is a direct relationship. As the temperature increases so does the volume. Volume (ml) = .0197(Temp (K)) + 0.098
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern