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Experiment 4 Lab Write Up

Experiment 4 Lab Write Up - Date Performed Date Submitted...

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Date Performed: 9/17/07 Joshua LaCelle Date Submitted: 9/24/07 Lab Partner: Nick Rorrer Instructor: Steven Burrows Determination of a Chemical Formula Objective: To determine the percentage composition and simplest formula for an oxide of copper by its reduction with methane gas (CH 4 ) at approximately 500 o C. This experiment is a study of stoichiometry. Experimental Data: Mass Copper Oxide 1.999g ± .0014g Mass Cu 1.642g ± .0014g Mass Oxygen 0.357g ± .0017g Moles Cu .0258 moles ± .0014 moles Moles O .0225 moles ± .0017 moles Mole Ratio 1:1 = CuO = Copper(II)Oxide Sample Calculations: Mass Copper Oxide = Mass Test Tube and Copper Oxide – Mass Test Tube = (19.431g ± .001g) – (17.432 ± .001g) = 1.999g ± .0014g Page 1 of 3

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Date Performed: 9/17/07 Joshua LaCelle Date Submitted: 9/24/07 Lab Partner: Nick Rorrer Instructor: Steven Burrows Mass Cu = Mass of Cu and Tube – Mass Tube = (19.074g ± .001g) – (17.432g ± .001g) = 1.642g ± .0014g Mass Oxygen = Mass Copper Oxide – Mass Copper = (1.999g ± .001g) – (1.642g ± .0014g) = 0.357g ± .0017g Moles Cu = Mass Cu / MW Cu = (1.642g ± .0014g)/(63.55g/mol) = .0258 moles Cu ± .0014 moles Moles O = Mass O / MW O = (0.357g ± .0017g)/(15.999g/mol) =
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