Experiment 9 Vapor Pressure

Experiment 9 Vapor Pressure - 15.3 2.729753 0.003289 63.4...

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Date Perform: 10/29/07 Name: Josh LaCelle Date Submitted: 11/5/07 Partner: Nick Rorrer Instructor: Steven Burrows Objective : To determine the vapor pressure of curve for a liquid as a function of temperature Experiment Data Temperature ( o C) Temperature (Kelvin) Length of Bubble (cm) 4 277 3.31 12 285 3.44 19 292 3.52 31 304 3.77 41 314 4.19 51 324 4.63 Sample Calculations P BAR = 724 ± 5 mmHg P vap = {[L 2 -((T 1 /T 2 )xL 1 )]/L 2 } x P atm P vap = {[3.44-((285/277)x3.31)]/ 3.44} x724 = 0.99936 mmHg lnP= -11198(1/T) + 39.56
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Date Perform: 10/29/07 Name: Josh LaCelle Date Submitted: 11/5/07 Partner: Nick Rorrer Instructor: Steven Burrows A = 39.56 B = 11198 Vapor Pressure (mmHg) Ln(P) 1/T 0.00 Does Not Exist 0.00361 0.999 -0.00064 0.003509 4.41 1.482963 0.003425
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Unformatted text preview: 15.3 2.729753 0.003289 63.4 4.149945 0.003185 117 4.757728 0.003086 The graph of pressure versus temperature is an exponential relationship. The graph of the natural log of the pressure versus the inverse of temperature is a negative linear relationship. Discussion of Uncertainty Uncertainty in this lab comes from the human error in measuring the length of the bubble. Since the liquid is in the tube, it does not form a perfectly straight line to measure the length of the bubble. Also there is human error in measuring the temperature with the thermometer. This could be as simple as looking at the thermometer from an angle....
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Experiment 9 Vapor Pressure - 15.3 2.729753 0.003289 63.4...

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