109e2rvw - 109 Exam 2 Review Sheet Spring 2008 Posted 12...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
109 Exam 2 Review Sheet Spring 2008 Posted 12 days before Exam 2, you can use this sheet as we cover the material in class or just before the exam to check your knowledge. This review is divided up by topics we have covered. The STP info is possible information you would want to put in your white box. It is not all inclusive, and certainly some of it you may not want to put down. Each section has many problems for you to try. After you have done the suggested problems in your text, problems given in reci and on blackboard, try some of these questions for review. (Answers in parenthesis after question). About the most representative 5 to work are mentioned by number at the beginning of the section, if you do not wish to work through the entire sheet. Aqueous Solutions STP N SPACE info: Molarity (M) = mol/L; M 1 V 1 = M 2 V 2 ; Review questions (3, 7, 12, 19) 1.) A solution contains 10.0 g of KOH and 900.0 mL of water. The volume of the solution is 904.7 mL. a) Which component of the solution is the solute? Which is the solvent? b) What is the molarity of this solution? (a. KOH solute, water solvent; b. 0.197 M) 2.) Which of the following are strong electrolytes, weak electrolytes, or nonelectrolytes in water: HBr, H 2 S, CCl 4 , NH 3 , Ba(OH) 2 , KCl, and benzene? (strong: HBr, Ba(OH) 2 , and KCl; weak: H 2 S and NH 3 ; non: benzene and Ccl 4 ) 3.) What is the molarity of Na + ions in a 0.02 M Na 3 PO 4 solution? (0.06 M Na + ) 4.) What is the molarity of ethylene glycol, C 2 H 4 (OH) 2 , in a solution prepared by mixing 5.00 g of ethylene glycol in 125 g of water? (0.644 M) 5.) To study the effect of dissolved salt on the rusting of an iron sample, a student prepared a solution of NaCl by dissolving 1.461 g of NaCl in a 250.0 mL volumetric flask and filled to the mark with water. What is the molarity of this solution? (0.1000 M)
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
6.) How many milliliters of 0.250 M NaCl solution must be measured to obtain 0.100 mol of NaCl? (400 mL) 7.) How many milliliters of 0.150 M KCl solution must be taken to provide 0.0500 mol of KCl? (33.3 mL) 8.) To study the precipitation reaction of sodium sulfide with cadmium nitrate, a student first had to make an aqueous solution of cadmium nitrate. A concentration of 0.100 M Cd(NO 3 ) 2 was judged to be appropriate. Moreover, 250.0 mL of solution was believed to be adequate. How many grams of pure cadmium nitrate are needed to prepare this much solution at a concentration of 0.100 M? (5.91 g) 9.) How many grams of CaCl 2 are needed to prepare 250 mL of 0.125 M CaCl 2 solution? (3.47 g)
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 7

109e2rvw - 109 Exam 2 Review Sheet Spring 2008 Posted 12...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online