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113 Quiz 3A Key

# 113 Quiz 3A Key - Chem 113 ~FALL 30 TOTAL POINTS Name Lab...

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Unformatted text preview: Chem 113 ~FALL 30 TOTAL POINTS Name Lab Section _ MOLAR MASSES ( g/mole) C = 12.01 Fe = 55.85 NH4 : 18.04 K3Fe(CZO4)3(H:O)3 = 491.3 0 = 16.00 C1023 88.02 H20 = 18.02 Fe(NH‘,)Z(S0030-120)6 = 3922 H = 1.008 K = 39.10 SO? : 96.06 1. (4pts) Calculate the percent of hydrogen in Fe(NH4)2(SO4)2(HZO)6 % of hydrogen 2. (4 pts) Calculate the molarity if 2.865 g of NrctQCZO4 is dissolved in 450 mL of water. Molarin = _ 3. (8 pts) A student started with7.98 g of Fe(NH4)2(SOA)2(HZO)6 . What will be the amount of K3Fe(CZO4)3(HzO)3 produced in the reaction if the yield is 94%. The mole ratio is 1 to 1. What is the percent theoretical yield if the student produced 9.18 g? % Theoretical Yield Amount produced ght to be 0.0310 M and you are asked to prepare i mL aliquots will be used t 0 standardize the KMnOl. If approximately 33.0 mL of WHO; is to be used, calculate how much Nu2C204 should be weighed out in grams. (8 pts) A student weighed out 0.423 g of K3Fe(C12‘F)4)_\3 _ KMnO4 solution to reach the endpoint. Zinc dust w 6.02 mL of theiiKMnO4 solution to reach the endpoint. ‘ sample. 5Fe(C'204)3‘ + mm; + 48H+ __'_>., ‘ 53¢: 4H++ 5Fe2++ MnO; —————+ SR: Chem 113 — p62? Lab Q I ...
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113 Quiz 3A Key - Chem 113 ~FALL 30 TOTAL POINTS Name Lab...

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