Stats_Material41 - Q1)7.2#4 Answers...

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Q1) 7.2#4 Answers – Margin of Error= Z a/2 Sqrt(p*(1-p)/n))      x = Mean      n = Sample Size      a = 1 - (Confidence Level/100)   Za/2 = Z-table value     CI = Confidence Interval  Mean(x)=200 Sample Size(n)=500 Sample proportion =0.4 Margin of Error =  Z a/2 *  ( Sqrt ( (0.4*0.6) /500) ) =  1.96* Sqrt(0.0005) =0.0429 Q2) 7.2#5 Answers – Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)  Z a/2 at 0.05 is = 1.96 Sample Proportion  = 0.5 ME = 0.06 n =  ( 1.96 / 0.06 )^2 * 0.5*0.5 = 266.7778 ~ 267 Q3) 7.2#6 Answers – Confidence Interval For Proportion  If (n>=30) CI = p  ±  Z a/2 Sqrt(p*(1-p)/n))    x = Mean    n = Sample Size    a = 1 - (Confidence Level/100)   Za/2 = Z-table value    CI = Confidence Interval  Mean(x)=270 Sample Size(n)=540 Sample proportion = x/n =0.5 Confidence Interval = [ 0.5  ± Z a/2 ( Sqrt ( 0.5*0.5) /540)  ]    =  [ 0.5 - 2.58* Sqrt(0.0005) , 0.5 + 2.58* Sqrt(0.0005) ]   =  [ 0.444,0.556] Q4)  7.3 #1
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