**Unformatted text preview: **3.2 MC = dC/dQ = 5 + 4Q. At Q = 1, MC = 9 ; Q = 5 , MC = 25 3.3 (1) 2x + 2 ; (2) 15x 4 + 8x + 10 ; (3) -1/x 2 + 1/2(x-1/2 ) 4.1 (1) Trivial solution, line x + z = 1 (2) Graph is L shaped curve with minimum point at (1,1) (3) Graph is inverse(mirror image) of that for min fn. with maximum pt at (1,1) (4) Level curve is hyperbola with z : Æ ∞ , -∞ as x : Æ 0 4.2 fn : U = l + r , for U = 10 level curve is a straight line l + r = 10 4.3 ∂ F/ ∂ x = 2x + 2z ∂ F/ ∂ z = 2x + 30z 2 5.1 For x to be a maximum or minimum f’(x) = 0 => 50 – 4x = 0 => x = 25/2...

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- Fall '08
- HOGENDORN
- UCI race classifications, Tour de Georgia, 1.7 M, Omair Sarwar