problem23_17

University Physics with Modern Physics with Mastering Physics (11th Edition)

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23.17: a) Work done is zero since the motion is along an equipotential, perpendicular to the electric field. b) J 10 5 . 7 ) m 670 . 0 ( m V 10 4.00 nC) 0 . 28 ( 4 4 - × =
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Unformatted text preview: = = qEd W c) J 10 06 . 2 ) 45 cos 60 . 2 ( m V 10 4.00 nC) . 28 ( 3 4--= - = = qEd W...
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