problem23_17

University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

23.17: a) Work done is zero since the motion is along an equipotential, perpendicular to the electric field. b) J 10 5 . 7 ) m 670 . 0 ( m V 10 4.00 nC) 0 . 28 ( 4 4 - × =
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: × = = qEd W c) J 10 06 . 2 ) 45 cos 60 . 2 ( m V 10 4.00 nC) . 28 ( 3 4-×-= °- × = = qEd W...
View Full Document

  • '
  • NoProfessor
  • Physics, Electric charge, Electromagnetic field

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern