problem23_07

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 23.7: a) U k q1q2 r12 q1q2 r13 q1q2 r23 k (4.00 nC)( 3.00 nC) (0.200 m) (4.00 nC)(2.00 nC) (0.100m) ( 3.00 nC)(2.00 nC) (0.100 m) 3.60 10 7 J. b) If U 0 x q 2 q3 q1q 2 q1 q3 . So solving for x we find: r12 x r12 x 8 6 60 60 x 2 26 x 1.6 0 x 0.074 m, 0.360 m. Therefore x 0.2 x 0.074 m since it is the only value between the two charges. 0, 0 k ...
View Full Document

This document was uploaded on 02/06/2008.

Ask a homework question - tutors are online