Chapter2 solutions - Problem 2.1 Find the current I and the power supplied by the source in the network shown I 6V 20 k Suggested Solution I= 6 = 0.3 mA

Chapter2 solutions - Problem 2.1 Find the current I and the...

  • Carleton University
  • ELEC 2501
  • Notes
  • CompMaster22
  • 93
  • 100% (1) 1 out of 1 people found this document helpful

This preview shows page 1 - 17 out of 93 pages.

Problem 2.1 Find the current Iand the power supplied by the source in the network shown. I 6 V 20 k Suggested Solution 3 6 0.3 mA 20 10 I = = × 3 (6)(0.3 10 ) 1.8 mW P VI = = × =
Image of page 1
Problem 2.2 In the circuit shown, find the voltage across the current source and the power absorbed by the resistor. 3 mA3 k+VCS_
Image of page 2
Problem 2.3 If the 10-resistor in the network shown absorbs 2.5 mW, find V . k S V S 10 k Suggested Solution 2 10 k S V P = or ( )( ) 3 3 2.5 10 10 10 5 V S R = × = × × = V P
Image of page 3
Problem 2.4 In the network shown, the power absorbed by x R is 5 mW. Find x R . R x 1 mA 2 Suggested Solution ( ) 3 2 2 3 5 10 20 k 0.5 10 x P R I × = = = ×
Image of page 4
Problem 2.5 In the network shown, the power absorbed by x R is 20 mW. Find x R . 2 mA R x Suggested Solution ( ) 3 2 2 3 20 10 5 k 2 10 P R I × = = = ×
Image of page 5
Problem 2.6 A model for a standard two D-cell flashlight is shown. Find the power dissipated in the lamp. 1.5 V1.5 V1-lampSuggested Solution 1.51.53 VlampV=+=( )2239 W1lamplamplampVPR===
Image of page 6
Problem 2.7 An automobile uses two halogen headlights connected as shown. Determine the power supplied by the battery if each headlight draws 3 A of current. 12 V Suggested Solution ( )( ) 12 3 3 72 W S P VI = = + =
Image of page 7
Problem 2.8 Many years ago a string of Christmas tree lights was manufactured in the form shown in (a). Today the lights are manufactured as shown in (b). Is there a good reason for this change?
Image of page 8
Problem 2.9 Find 1Iin the network shown. I 1 12 mA 4 mA 2 mA Suggested Solution I 1 12 mA 4 mA 2 mA I 2 2 0.004 0.002 0.006 A I = + = 1 2 0.012 I I = + 1 6 mA I =
Image of page 9
Problem 2.10 Find 1 I and 2 I in the circuit shown. I 3 = 5 mA I S I 4 = 6 mA I 1 I 6 = 3 mA I 2 Suggested Solution By KCL, 1 4 6 mA I I = = Also, 6 2 4 I I I + = or 2 0.003 0.006 I + = 2 3 mA I =
Image of page 10
Problem 2.11 Find x I and y I in the network shown. 4 mA 12 mA 8 mA I x I y Suggested Solution 0.012 0.004 x I = + 8 mA x I = 0.004 0.008 y I = + 4 mA y I = −
Image of page 11
Problem 2.12 Find xI, yIand zIin the circuit shown. IxIyIz2 mA12 mA4 mA
Image of page 12
Problem 2.13 Find xIin the circuit shown.
Image of page 13
Problem 2.14 Find x I , y I and z I in the network shown. 12 mA 3 mA 2 mA 4 mA I x I y I z Suggested Solution 12 mA 3 mA 2 mA 4 mA I x I y I z 0.003 0.012 x I + = 9 mA x I = 0.012 0.002 0.004 y I + + = 10 mA y I = − 0.004 0.002 z I + = 2 mA z I = −
Image of page 14
Problem 2.15 Find x I in the circuit shown. 2 I x I x 2 mA 6 mA Suggested Solution 2 I x I x 2 mA 6 mA 2 0.002 0.006 x x I I + = + 4 mA x I =
Image of page 15