problem23_40

University Physics with Modern Physics with Mastering Physics (11th Edition)

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23.40: For points outside this spherical charge distribution the field is the same as if all the charge were concentrated at the center. Therefore 2 0 4 r πε q E = and C 10 69 . 1 / N.m 10 9 ) m 200 . 0 ( ) C N 3800 ( 4 8 2 2 9 2 2 0 - × = × = = C Er πε q Since the field is directed inward, the charge must be negative. The potential of a point charge, taking as zero, is V 760 m 200 . 0 ) C 10 69 . 1 ( ) C / N.m 10 9 ( 4 8 2 2 9 0 - = × - × = = - r πε q V at the surface of the sphere. Since the charge all resides on the surface of a conductor, the
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Unformatted text preview: field inside the sphere due to this symmetrical distribution is zero. No work is therefore done in moving a test charge from just inside the surface to the center, and the potential at the center must also be . V 760-...
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