problem23_40

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
23.40: For points outside this spherical charge distribution the field is the same as if all the charge were concentrated at the center. Therefore 2 0 4 r πε q E = and C 10 69 . 1 / N.m 10 9 ) m 200 . 0 ( ) C N 3800 ( 4 8 2 2 9 2 2 0 - × = × = = C Er πε q Since the field is directed inward, the charge must be negative. The potential of a point charge, taking as zero, is V 760 m 200 . 0 ) C 10 69 . 1 ( ) C / N.m 10 9 ( 4 8 2 2 9 0 - = × - × = = - r πε q V at the surface of the sphere. Since the charge all resides on the surface of a conductor, the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: field inside the sphere due to this symmetrical distribution is zero. No work is therefore done in moving a test charge from just inside the surface to the center, and the potential at the center must also be . V 760-...
View Full Document

This document was uploaded on 02/06/2008.

Ask a homework question - tutors are online