103B PS 1 - Page 1 CHEMISTRY 103B, Sections 1-4 4/10/2008...

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Unformatted text preview: Page 1 CHEMISTRY 103B, Sections 1-4 4/10/2008 12:14:39 AM http://www.chem.arizona.edu/~kellerp/ps-answers/PS1an/PS1an.htm CHEMISTRY 103B, Sections 3, 4, 7, and 8 Problem Set 1: 12 Points Answer Key Problem1. (sixpoints) Thisprobleminvolvesa gas phase reactionwiththe following balanced equation. A 3 (g) + 3 B(g) + 2 C 3 (g) 3 AB 2 C(g) TheEnglishtranslationof the balancedequationstates that one moleof A 3 combineswith threemolesof B and threemolesof C 2 to produce threemolesof AB 2 C. At the start of the reaction(t = 0) the concentrationof each reactantwas 0.900 mol/L and the concentrationof the productwas 0.000 mol/L. (a) Whatisthe concentrationinmol/L of B whenthatof A 3 has dropped from0.900 to 0.800 mol/L? Theconcentrationof A 3 changes(decreases) by 0.100 mol/L. IfA 3 changesby x mol/L, thenB mustchangeby 3 timesthatamount. A 3 3 B 2 C 3 3 ABC 2 Initial 0.900 0.900 0.900 0.000 Change-0.100-0.300 Result 0.800 0.600 (B) = 0.600 mol/L (b) Whatisthe concentrationinmol/L of C 3 whenthatof A 3 has dropped from0.900 to 0.800 mol/L? A 3 3 B 2 C 3 3 ABC 2 Page 2 CHEMISTRY 103B, Sections 1-4 4/10/2008 12:14:39 AM http://www.chem.arizona.edu/~kellerp/ps-answers/PS1an/PS1an.htm A 3 3 B 2 C 3 3 ABC 2 Initial 0.900 0.900 0.900 0.000 Change-0.100-0.300-0.200 Result 0.800 0.600 0.700 (C 2 ) = 0.700 mol/L (c) Whatisthe concentrationinmol/L of ABC 2 (g) whenthatof A 3 has dropped from0.900 to 0.800 mol/L?...
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103B PS 1 - Page 1 CHEMISTRY 103B, Sections 1-4 4/10/2008...

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