EE_331F_2007_-_HW3S

# EE_331F_2007_-_HW3S - EE 331 Devices and Circuits I Problem...

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EE 331 Devices and Circuits I Autumn 2007 Problem Set #3 Solution 3.22 V D = nV T ln 1 + I D I S | I D = I S exp V D nV T 1 (a) V D = 1.05 0.025 V () ln 1 + 7 x 10 5 A 10 18 A ⎟ = 0.837 V (b) V D = 1.05 0.025 V ln 1 + 5 x 10 6 A 10 18 A ⎟ = 0.768 V (c) I D = 10 18 A exp 0 1.05 0.025 V 1 = 0 A (d) I D = 10 18 A exp 0.075 V 1.05 0.025 V 1 =− 0.943 x 10 19 A (e) I D = 10 18 A exp 5 V 1.05 0.025 V 1 1.00 x 10 18 A 3.23 V D = nV T ln 1 + I D I S I D = I S exp V D nV T 1 (a) V D = 0.025 V ln 1 + 10 4 A 10 17 A ⎟ = 0.748 V (b) V D = 0.025 V ln 1 + 10 5 A 10 17 A ⎟ = 0.691 V (c) I D = 10 17 A exp 0 0.025 V ⎟ − 1 = A (d) I D = 10 17 A exp 0.06 V 0.025 V

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EE_331F_2007_-_HW3S - EE 331 Devices and Circuits I Problem...

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