{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

314_HW8_solutions[1]

# 314_HW8_solutions[1] - EECS 314 Winter 2007 HW 08 Grading...

This preview shows pages 1–5. Sign up to view the full content.

EECS 314 Winter 2007 HW 08 Grading Policy © 2007 Alexander Ganago This document corrects the typos made in early versions of problems 4, 5, and 7. Problem 1 – 25 points Problem 2 – 25 points Problem 3 – 25 points Problem 4 – 30 points (one point for each correct answer) Problem 5 – 30 points (one point for each correct answer) Problem 6 – 15 points (one point for each correct answer) Problem 1 – 25 points (5 points for each part) = = = = = = = = = = = = = = = = = = = = = = = = = = = = = Total = 175 points, as usual

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
EECS 314 Winter 2007 HW 08 Problem 1 Student's name ___________________________ Discussion section # __________ (Last name, first name, IN INK) Alexander Ganago Page 2 of 2 Assorted diode circuits. (Expect similar problems on exam 3 ;) Use the offset-diode model (the diode acts as an open circuit unless it is biased at +0.7 V; the voltage drop across the diode does not exceed +0.7 V) and calculate the following parameters for each circuit: a) The current through the circuit b) The output voltage V 0 Show your work on a separate page. Part 4 Your answers: I = _______ mA V 0 = ________ V Part 5 Your answers: I = _________ mA V 0 = _________ V Part 6 Your answers: I = ________ mA V 0 = ________ V 16 V 10 V 8 V

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Solution (Barry Mullins) Part 1 First we assume the diode is not forward biased. In this case I=0 and V D0 = 6V, telling us that our assumption was wrong and that the diode is in fact forward biased. Thus, it can be replaced with an voltage source with a voltage equal to the diode offset voltage.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern