Sphw2 - HOMEWORK SET 2 3.32 Water at 120oC with a quality...

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HOMEWORK SET 2 3.32 Water at 120 o C with a quality of 25% has its temperature raised 20 o C in a constant volume process. What is the new quality and pressure? Solution: State 1 from Table B.1.1 at 120 o C v = v f + x v fg = 0.001060 + 0.25 × 0.8908 = 0.22376 m 3 /kg State 2 has same v at 140 o C also from Table B.1.1 x = v - v f v fg = 0.22376 - 0.00108 0.50777 = 0.4385 P = Psat = 361.3 kPa T C.P. v P C.P. v T 198.5 361.3 120 140 120 C 140 C 3.35 Water at 200 kPa with a quality of 25% has its temperature raised 20 o C in a constant pressure process. What is the new quality and volume? Solution: State 1 from Table B.1.2 at 200 kPa v = v f + x v fg = 0.001061 + 0.25 × 0.88467 = 0.22223 m 3 /kg State 2 has same P from Table B.1.2 at 200 kPa T 2 = T sat + 20 = 120.23 + 20 = 140.23 o C so state is superheated vapor x = undefined v 2 = 0.88573 + (0.95964 – 0.88573) 20 150 - 120.23 = 0.9354 m 3 /kg
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3.44 Ammonia at 20 o C with a quality of 50% and total mass 2 kg is in a rigid tank with an outlet valve at the bottom. How much liquid (mass) can you take out through the valve assuming the temperature stays constant? The bottom has liquid until the state inside becomes saturated vapor.
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This homework help was uploaded on 04/10/2008 for the course ME 235 taught by Professor Borgnakke during the Spring '07 term at University of Michigan.

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Sphw2 - HOMEWORK SET 2 3.32 Water at 120oC with a quality...

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