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Sphw2 - HOMEWORK SET 2 3.32 Water at 120oC with a quality...

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HOMEWORK SET 2 3.32 Water at 120 o C with a quality of 25% has its temperature raised 20 o C in a constant volume process. What is the new quality and pressure? Solution: State 1 from Table B.1.1 at 120 o C v = v f + x v fg = 0.001060 + 0.25 × 0.8908 = 0.22376 m 3 /kg State 2 has same v at 140 o C also from Table B.1.1 x = v - v f v fg = 0.22376 - 0.00108 0.50777 = 0.4385 P = Psat = 361.3 kPa T C.P. v P C.P. v T 198.5 361.3 120 140 120 C 140 C 3.35 Water at 200 kPa with a quality of 25% has its temperature raised 20 o C in a constant pressure process. What is the new quality and volume? Solution: State 1 from Table B.1.2 at 200 kPa v = v f + x v fg = 0.001061 + 0.25 × 0.88467 = 0.22223 m 3 /kg State 2 has same P from Table B.1.2 at 200 kPa T 2 = T sat + 20 = 120.23 + 20 = 140.23 o C so state is superheated vapor x = undefined v 2 = 0.88573 + (0.95964 – 0.88573) 20 150 - 120.23 = 0.9354 m 3 /kg
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